3.99/1.89 WORST_CASE(Omega(n^1), O(n^1)) 3.99/1.90 proof of /export/starexec/sandbox/benchmark/theBenchmark.koat 3.99/1.90 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 3.99/1.90 3.99/1.90 3.99/1.90 The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(n^1, max(1, 1 + Arg_0)). 3.99/1.90 3.99/1.90 (0) CpxIntTrs 3.99/1.90 (1) Koat2 Proof [FINISHED, 131 ms] 3.99/1.90 (2) BOUNDS(1, max(1, 1 + Arg_0)) 3.99/1.90 (3) Loat Proof [FINISHED, 223 ms] 3.99/1.90 (4) BOUNDS(n^1, INF) 3.99/1.90 3.99/1.90 3.99/1.90 ---------------------------------------- 3.99/1.90 3.99/1.90 (0) 3.99/1.90 Obligation: 3.99/1.90 Complexity Int TRS consisting of the following rules: 3.99/1.90 zip3(A, B, C) -> Com_1(zip3(A - 1, B - 1, C - 1)) :|: A >= 1 && B >= 1 && C >= 1 3.99/1.90 group3(A, B, C) -> Com_1(group3(A - 3, B, C)) :|: A >= 4 3.99/1.90 start(A, B, C) -> Com_1(zip3(A, B, C)) :|: TRUE 3.99/1.90 3.99/1.90 The start-symbols are:[start_3] 3.99/1.90 3.99/1.90 3.99/1.90 ---------------------------------------- 3.99/1.90 3.99/1.90 (1) Koat2 Proof (FINISHED) 3.99/1.90 YES( ?, max([1, 1+Arg_0]) {O(n)}) 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 Initial Complexity Problem: 3.99/1.90 3.99/1.90 Start: start 3.99/1.90 3.99/1.90 Program_Vars: Arg_0, Arg_1, Arg_2 3.99/1.90 3.99/1.90 Temp_Vars: 3.99/1.90 3.99/1.90 Locations: start, zip3 3.99/1.90 3.99/1.90 Transitions: 3.99/1.90 3.99/1.90 start(Arg_0,Arg_1,Arg_2) -> zip3(Arg_0,Arg_1,Arg_2):|: 3.99/1.90 3.99/1.90 zip3(Arg_0,Arg_1,Arg_2) -> zip3(Arg_0-1,Arg_1-1,Arg_2-1):|:1 <= Arg_0 && 1 <= Arg_1 && 1 <= Arg_2 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 Timebounds: 3.99/1.90 3.99/1.90 Overall timebound: max([1, 1+Arg_0]) {O(n)} 3.99/1.90 3.99/1.90 2: start->zip3: 1 {O(1)} 3.99/1.90 3.99/1.90 0: zip3->zip3: max([0, Arg_0]) {O(n)} 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 Costbounds: 3.99/1.90 3.99/1.90 Overall costbound: max([1, 1+Arg_0]) {O(n)} 3.99/1.90 3.99/1.90 2: start->zip3: 1 {O(1)} 3.99/1.90 3.99/1.90 0: zip3->zip3: max([0, Arg_0]) {O(n)} 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 Sizebounds: 3.99/1.90 3.99/1.90 `Lower: 3.99/1.90 3.99/1.90 2: start->zip3, Arg_0: Arg_0 {O(n)} 3.99/1.90 3.99/1.90 2: start->zip3, Arg_1: Arg_1 {O(n)} 3.99/1.90 3.99/1.90 2: start->zip3, Arg_2: Arg_2 {O(n)} 3.99/1.90 3.99/1.90 0: zip3->zip3, Arg_0: 0 {O(1)} 3.99/1.90 3.99/1.90 0: zip3->zip3, Arg_1: 0 {O(1)} 3.99/1.90 3.99/1.90 0: zip3->zip3, Arg_2: 0 {O(1)} 3.99/1.90 3.99/1.90 `Upper: 3.99/1.90 3.99/1.90 2: start->zip3, Arg_0: Arg_0 {O(n)} 3.99/1.90 3.99/1.90 2: start->zip3, Arg_1: Arg_1 {O(n)} 3.99/1.90 3.99/1.90 2: start->zip3, Arg_2: Arg_2 {O(n)} 3.99/1.90 3.99/1.90 0: zip3->zip3, Arg_0: Arg_0 {O(n)} 3.99/1.90 3.99/1.90 0: zip3->zip3, Arg_1: Arg_1 {O(n)} 3.99/1.90 3.99/1.90 0: zip3->zip3, Arg_2: Arg_2 {O(n)} 3.99/1.90 3.99/1.90 3.99/1.90 ---------------------------------------- 3.99/1.90 3.99/1.90 (2) 3.99/1.90 BOUNDS(1, max(1, 1 + Arg_0)) 3.99/1.90 3.99/1.90 ---------------------------------------- 3.99/1.90 3.99/1.90 (3) Loat Proof (FINISHED) 3.99/1.90 3.99/1.90 3.99/1.90 ### Pre-processing the ITS problem ### 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 Initial linear ITS problem 3.99/1.90 3.99/1.90 Start location: start 3.99/1.90 3.99/1.90 0: zip3 -> zip3 : A'=-1+A, B'=-1+B, C'=-1+C, [ A>=1 && B>=1 && C>=1 ], cost: 1 3.99/1.90 3.99/1.90 1: group3 -> group3 : A'=-3+A, [ A>=4 ], cost: 1 3.99/1.90 3.99/1.90 2: start -> zip3 : [], cost: 1 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 Removed unreachable and leaf rules: 3.99/1.90 3.99/1.90 Start location: start 3.99/1.90 3.99/1.90 0: zip3 -> zip3 : A'=-1+A, B'=-1+B, C'=-1+C, [ A>=1 && B>=1 && C>=1 ], cost: 1 3.99/1.90 3.99/1.90 2: start -> zip3 : [], cost: 1 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 ### Simplification by acceleration and chaining ### 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 Accelerating simple loops of location 0. 3.99/1.90 3.99/1.90 Accelerating the following rules: 3.99/1.90 3.99/1.90 0: zip3 -> zip3 : A'=-1+A, B'=-1+B, C'=-1+C, [ A>=1 && B>=1 && C>=1 ], cost: 1 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 Accelerated rule 0 with backward acceleration, yielding the new rule 3. 3.99/1.90 3.99/1.90 Accelerated rule 0 with backward acceleration, yielding the new rule 4. 3.99/1.90 3.99/1.90 Accelerated rule 0 with backward acceleration, yielding the new rule 5. 3.99/1.90 3.99/1.90 Removing the simple loops: 0. 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 Accelerated all simple loops using metering functions (where possible): 3.99/1.90 3.99/1.90 Start location: start 3.99/1.90 3.99/1.90 3: zip3 -> zip3 : A'=0, B'=-A+B, C'=C-A, [ A>=1 && B>=1 && C>=1 && 1-A+B>=1 && 1+C-A>=1 ], cost: A 3.99/1.90 3.99/1.90 4: zip3 -> zip3 : A'=A-B, B'=0, C'=C-B, [ A>=1 && B>=1 && C>=1 && 1+A-B>=1 && 1+C-B>=1 ], cost: B 3.99/1.90 3.99/1.90 5: zip3 -> zip3 : A'=-C+A, B'=-C+B, C'=0, [ A>=1 && B>=1 && C>=1 && 1-C+A>=1 && 1-C+B>=1 ], cost: C 3.99/1.90 3.99/1.90 2: start -> zip3 : [], cost: 1 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 Chained accelerated rules (with incoming rules): 3.99/1.90 3.99/1.90 Start location: start 3.99/1.90 3.99/1.90 2: start -> zip3 : [], cost: 1 3.99/1.90 3.99/1.90 6: start -> zip3 : A'=0, B'=-A+B, C'=C-A, [ A>=1 && B>=1 && C>=1 && 1-A+B>=1 && 1+C-A>=1 ], cost: 1+A 3.99/1.90 3.99/1.90 7: start -> zip3 : A'=A-B, B'=0, C'=C-B, [ A>=1 && B>=1 && C>=1 && 1+A-B>=1 && 1+C-B>=1 ], cost: 1+B 3.99/1.90 3.99/1.90 8: start -> zip3 : A'=-C+A, B'=-C+B, C'=0, [ A>=1 && B>=1 && C>=1 && 1-C+A>=1 && 1-C+B>=1 ], cost: 1+C 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 Removed unreachable locations (and leaf rules with constant cost): 3.99/1.90 3.99/1.90 Start location: start 3.99/1.90 3.99/1.90 6: start -> zip3 : A'=0, B'=-A+B, C'=C-A, [ A>=1 && B>=1 && C>=1 && 1-A+B>=1 && 1+C-A>=1 ], cost: 1+A 3.99/1.90 3.99/1.90 7: start -> zip3 : A'=A-B, B'=0, C'=C-B, [ A>=1 && B>=1 && C>=1 && 1+A-B>=1 && 1+C-B>=1 ], cost: 1+B 3.99/1.90 3.99/1.90 8: start -> zip3 : A'=-C+A, B'=-C+B, C'=0, [ A>=1 && B>=1 && C>=1 && 1-C+A>=1 && 1-C+B>=1 ], cost: 1+C 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 ### Computing asymptotic complexity ### 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 Fully simplified ITS problem 3.99/1.90 3.99/1.90 Start location: start 3.99/1.90 3.99/1.90 6: start -> zip3 : A'=0, B'=-A+B, C'=C-A, [ A>=1 && B>=1 && C>=1 && 1-A+B>=1 && 1+C-A>=1 ], cost: 1+A 3.99/1.90 3.99/1.90 7: start -> zip3 : A'=A-B, B'=0, C'=C-B, [ A>=1 && B>=1 && C>=1 && 1+A-B>=1 && 1+C-B>=1 ], cost: 1+B 3.99/1.90 3.99/1.90 8: start -> zip3 : A'=-C+A, B'=-C+B, C'=0, [ A>=1 && B>=1 && C>=1 && 1-C+A>=1 && 1-C+B>=1 ], cost: 1+C 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 Computing asymptotic complexity for rule 6 3.99/1.90 3.99/1.90 Solved the limit problem by the following transformations: 3.99/1.90 3.99/1.90 Created initial limit problem: 3.99/1.90 3.99/1.90 C (+/+!), A (+/+!), 1-A+B (+/+!), 1+C-A (+/+!), B (+/+!), 1+A (+) [not solved] 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 removing all constraints (solved by SMT) 3.99/1.90 3.99/1.90 resulting limit problem: [solved] 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 applying transformation rule (C) using substitution {C==2*n,A==n,B==1+n} 3.99/1.90 3.99/1.90 resulting limit problem: 3.99/1.90 3.99/1.90 [solved] 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 Solution: 3.99/1.90 3.99/1.90 C / 2*n 3.99/1.90 3.99/1.90 A / n 3.99/1.90 3.99/1.90 B / 1+n 3.99/1.90 3.99/1.90 Resulting cost 1+n has complexity: Poly(n^1) 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 Found new complexity Poly(n^1). 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 Obtained the following overall complexity (w.r.t. the length of the input n): 3.99/1.90 3.99/1.90 Complexity: Poly(n^1) 3.99/1.90 3.99/1.90 Cpx degree: 1 3.99/1.90 3.99/1.90 Solved cost: 1+n 3.99/1.90 3.99/1.90 Rule cost: 1+A 3.99/1.90 3.99/1.90 Rule guard: [ A>=1 && B>=1 && C>=1 && 1-A+B>=1 && 1+C-A>=1 ] 3.99/1.90 3.99/1.90 3.99/1.90 3.99/1.90 WORST_CASE(Omega(n^1),?) 3.99/1.90 3.99/1.90 3.99/1.90 ---------------------------------------- 3.99/1.90 3.99/1.90 (4) 3.99/1.90 BOUNDS(n^1, INF) 3.99/1.92 EOF