0.00/0.04	YES
0.00/0.04	
0.00/0.04	DP problem for innermost termination.
0.00/0.04	P =
0.00/0.04	  eval#(x) -> eval#(x - 1) [x % 2 = 0 && x > 0]
0.00/0.04	R = 
0.00/0.04	  eval(x) -> eval(x - 1) [x % 2 = 0 && x > 0]
0.00/0.04	
0.00/0.04	The dependency graph for this problem is:
0.00/0.04	  0 -> 
0.00/0.04	Where:
0.00/0.04	  0) eval#(x) -> eval#(x - 1) [x % 2 = 0 && x > 0]
0.00/0.04	
0.00/0.04	We have the following SCCs.
0.00/0.04	  
0.00/3.02	EOF