0.00/0.03	YES
0.00/0.03	
0.00/0.03	DP problem for innermost termination.
0.00/0.03	P =
0.00/0.03	  f#(x) -> f#(x) [x * x < 0]
0.00/0.03	R = 
0.00/0.03	  f(x) -> f(x) [x * x < 0]
0.00/0.03	
0.00/0.03	The dependency graph for this problem is:
0.00/0.03	  0 -> 
0.00/0.03	Where:
0.00/0.03	  0) f#(x) -> f#(x) [x * x < 0]
0.00/0.03	
0.00/0.03	We have the following SCCs.
0.00/0.03	  
0.00/3.01	EOF