0.00/0.01 YES 0.00/0.01 0.00/0.01 Problem 1: 0.00/0.01 0.00/0.01 (VAR N X Y Z) 0.00/0.01 (STRATEGY CONTEXTSENSITIVE 0.00/0.01 (add 1 2) 0.00/0.01 (dbl 1) 0.00/0.01 (first 1 2) 0.00/0.01 (sqr 1) 0.00/0.01 (terms 1) 0.00/0.01 (0) 0.00/0.01 (cons 1) 0.00/0.01 (nil) 0.00/0.01 (recip 1) 0.00/0.01 (s 1) 0.00/0.01 ) 0.00/0.01 (RULES 0.00/0.01 add(0,X) -> X 0.00/0.01 add(s(X),Y) -> s(add(X,Y)) 0.00/0.01 dbl(0) -> 0 0.00/0.01 dbl(s(X)) -> s(s(dbl(X))) 0.00/0.01 first(0,X) -> nil 0.00/0.01 first(s(X),cons(Y,Z)) -> cons(Y,first(X,Z)) 0.00/0.01 sqr(0) -> 0 0.00/0.01 sqr(s(X)) -> s(add(sqr(X),dbl(X))) 0.00/0.01 terms(N) -> cons(recip(sqr(N)),terms(s(N))) 0.00/0.01 ) 0.00/0.01 0.00/0.01 Problem 1: 0.00/0.01 0.00/0.01 Innermost Equivalent Processor: 0.00/0.01 -> Rules: 0.00/0.01 add(0,X) -> X 0.00/0.01 add(s(X),Y) -> s(add(X,Y)) 0.00/0.01 dbl(0) -> 0 0.00/0.01 dbl(s(X)) -> s(s(dbl(X))) 0.00/0.01 first(0,X) -> nil 0.00/0.01 first(s(X),cons(Y,Z)) -> cons(Y,first(X,Z)) 0.00/0.01 sqr(0) -> 0 0.00/0.01 sqr(s(X)) -> s(add(sqr(X),dbl(X))) 0.00/0.01 terms(N) -> cons(recip(sqr(N)),terms(s(N))) 0.00/0.01 -> The context-sensitive term rewriting system is an orthogonal system. Therefore, innermost cs-termination implies cs-termination. 0.00/0.01 0.00/0.01 0.00/0.01 Problem 1: 0.00/0.01 0.00/0.01 Dependency Pairs Processor: 0.00/0.01 -> Pairs: 0.00/0.01 ADD(s(X),Y) -> ADD(X,Y) 0.00/0.01 DBL(s(X)) -> DBL(X) 0.00/0.01 SQR(s(X)) -> ADD(sqr(X),dbl(X)) 0.00/0.01 SQR(s(X)) -> DBL(X) 0.00/0.01 SQR(s(X)) -> SQR(X) 0.00/0.01 TERMS(N) -> SQR(N) 0.00/0.01 -> Rules: 0.00/0.01 add(0,X) -> X 0.00/0.01 add(s(X),Y) -> s(add(X,Y)) 0.00/0.01 dbl(0) -> 0 0.00/0.01 dbl(s(X)) -> s(s(dbl(X))) 0.00/0.01 first(0,X) -> nil 0.00/0.01 first(s(X),cons(Y,Z)) -> cons(Y,first(X,Z)) 0.00/0.01 sqr(0) -> 0 0.00/0.01 sqr(s(X)) -> s(add(sqr(X),dbl(X))) 0.00/0.01 terms(N) -> cons(recip(sqr(N)),terms(s(N))) 0.00/0.01 -> Unhiding Rules: 0.00/0.01 Empty 0.00/0.01 0.00/0.01 Problem 1: 0.00/0.01 0.00/0.01 SCC Processor: 0.00/0.01 -> Pairs: 0.00/0.01 ADD(s(X),Y) -> ADD(X,Y) 0.00/0.01 DBL(s(X)) -> DBL(X) 0.00/0.01 SQR(s(X)) -> ADD(sqr(X),dbl(X)) 0.00/0.01 SQR(s(X)) -> DBL(X) 0.00/0.01 SQR(s(X)) -> SQR(X) 0.00/0.01 TERMS(N) -> SQR(N) 0.00/0.01 -> Rules: 0.00/0.01 add(0,X) -> X 0.00/0.01 add(s(X),Y) -> s(add(X,Y)) 0.00/0.01 dbl(0) -> 0 0.00/0.01 dbl(s(X)) -> s(s(dbl(X))) 0.00/0.01 first(0,X) -> nil 0.00/0.01 first(s(X),cons(Y,Z)) -> cons(Y,first(X,Z)) 0.00/0.01 sqr(0) -> 0 0.00/0.01 sqr(s(X)) -> s(add(sqr(X),dbl(X))) 0.00/0.01 terms(N) -> cons(recip(sqr(N)),terms(s(N))) 0.00/0.01 -> Unhiding rules: 0.00/0.01 Empty 0.00/0.01 ->Strongly Connected Components: 0.00/0.01 ->->Cycle: 0.00/0.01 ->->-> Pairs: 0.00/0.01 DBL(s(X)) -> DBL(X) 0.00/0.01 ->->-> Rules: 0.00/0.01 add(0,X) -> X 0.00/0.01 add(s(X),Y) -> s(add(X,Y)) 0.00/0.01 dbl(0) -> 0 0.00/0.01 dbl(s(X)) -> s(s(dbl(X))) 0.00/0.01 first(0,X) -> nil 0.00/0.01 first(s(X),cons(Y,Z)) -> cons(Y,first(X,Z)) 0.00/0.01 sqr(0) -> 0 0.00/0.01 sqr(s(X)) -> s(add(sqr(X),dbl(X))) 0.00/0.01 terms(N) -> cons(recip(sqr(N)),terms(s(N))) 0.00/0.01 ->->-> Unhiding rules: 0.00/0.01 Empty 0.00/0.01 ->->Cycle: 0.00/0.01 ->->-> Pairs: 0.00/0.01 ADD(s(X),Y) -> ADD(X,Y) 0.00/0.01 ->->-> Rules: 0.00/0.01 add(0,X) -> X 0.00/0.01 add(s(X),Y) -> s(add(X,Y)) 0.00/0.01 dbl(0) -> 0 0.00/0.01 dbl(s(X)) -> s(s(dbl(X))) 0.00/0.01 first(0,X) -> nil 0.00/0.01 first(s(X),cons(Y,Z)) -> cons(Y,first(X,Z)) 0.00/0.01 sqr(0) -> 0 0.00/0.01 sqr(s(X)) -> s(add(sqr(X),dbl(X))) 0.00/0.01 terms(N) -> cons(recip(sqr(N)),terms(s(N))) 0.00/0.01 ->->-> Unhiding rules: 0.00/0.01 Empty 0.00/0.01 ->->Cycle: 0.00/0.01 ->->-> Pairs: 0.00/0.01 SQR(s(X)) -> SQR(X) 0.00/0.01 ->->-> Rules: 0.00/0.01 add(0,X) -> X 0.00/0.01 add(s(X),Y) -> s(add(X,Y)) 0.00/0.01 dbl(0) -> 0 0.00/0.01 dbl(s(X)) -> s(s(dbl(X))) 0.00/0.01 first(0,X) -> nil 0.00/0.01 first(s(X),cons(Y,Z)) -> cons(Y,first(X,Z)) 0.00/0.01 sqr(0) -> 0 0.00/0.01 sqr(s(X)) -> s(add(sqr(X),dbl(X))) 0.00/0.01 terms(N) -> cons(recip(sqr(N)),terms(s(N))) 0.00/0.01 ->->-> Unhiding rules: 0.00/0.01 Empty 0.00/0.01 0.00/0.01 0.00/0.01 The problem is decomposed in 3 subproblems. 0.00/0.01 0.00/0.01 Problem 1.1: 0.00/0.01 0.00/0.01 SubNColl Processor: 0.00/0.01 -> Pairs: 0.00/0.01 DBL(s(X)) -> DBL(X) 0.00/0.01 -> Rules: 0.00/0.01 add(0,X) -> X 0.00/0.01 add(s(X),Y) -> s(add(X,Y)) 0.00/0.01 dbl(0) -> 0 0.00/0.01 dbl(s(X)) -> s(s(dbl(X))) 0.00/0.01 first(0,X) -> nil 0.00/0.01 first(s(X),cons(Y,Z)) -> cons(Y,first(X,Z)) 0.00/0.01 sqr(0) -> 0 0.00/0.01 sqr(s(X)) -> s(add(sqr(X),dbl(X))) 0.00/0.01 terms(N) -> cons(recip(sqr(N)),terms(s(N))) 0.00/0.01 -> Unhiding rules: 0.00/0.01 Empty 0.00/0.01 ->Projection: 0.00/0.01 pi(DBL) = 1 0.00/0.01 0.00/0.01 Problem 1.1: 0.00/0.01 0.00/0.01 Basic Processor: 0.00/0.01 -> Pairs: 0.00/0.01 Empty 0.00/0.01 -> Rules: 0.00/0.01 add(0,X) -> X 0.00/0.01 add(s(X),Y) -> s(add(X,Y)) 0.00/0.01 dbl(0) -> 0 0.00/0.01 dbl(s(X)) -> s(s(dbl(X))) 0.00/0.01 first(0,X) -> nil 0.00/0.01 first(s(X),cons(Y,Z)) -> cons(Y,first(X,Z)) 0.00/0.01 sqr(0) -> 0 0.00/0.01 sqr(s(X)) -> s(add(sqr(X),dbl(X))) 0.00/0.01 terms(N) -> cons(recip(sqr(N)),terms(s(N))) 0.00/0.01 -> Unhiding rules: 0.00/0.01 Empty 0.00/0.01 -> Result: 0.00/0.01 Set P is empty 0.00/0.01 0.00/0.01 The problem is finite. 0.00/0.01 0.00/0.01 Problem 1.2: 0.00/0.01 0.00/0.01 SubNColl Processor: 0.00/0.01 -> Pairs: 0.00/0.01 ADD(s(X),Y) -> ADD(X,Y) 0.00/0.01 -> Rules: 0.00/0.01 add(0,X) -> X 0.00/0.01 add(s(X),Y) -> s(add(X,Y)) 0.00/0.01 dbl(0) -> 0 0.00/0.01 dbl(s(X)) -> s(s(dbl(X))) 0.00/0.01 first(0,X) -> nil 0.00/0.01 first(s(X),cons(Y,Z)) -> cons(Y,first(X,Z)) 0.00/0.01 sqr(0) -> 0 0.00/0.01 sqr(s(X)) -> s(add(sqr(X),dbl(X))) 0.00/0.01 terms(N) -> cons(recip(sqr(N)),terms(s(N))) 0.00/0.01 -> Unhiding rules: 0.00/0.01 Empty 0.00/0.01 ->Projection: 0.00/0.01 pi(ADD) = 1 0.00/0.01 0.00/0.01 Problem 1.2: 0.00/0.01 0.00/0.01 Basic Processor: 0.00/0.01 -> Pairs: 0.00/0.01 Empty 0.00/0.01 -> Rules: 0.00/0.01 add(0,X) -> X 0.00/0.01 add(s(X),Y) -> s(add(X,Y)) 0.00/0.01 dbl(0) -> 0 0.00/0.01 dbl(s(X)) -> s(s(dbl(X))) 0.00/0.01 first(0,X) -> nil 0.00/0.01 first(s(X),cons(Y,Z)) -> cons(Y,first(X,Z)) 0.00/0.01 sqr(0) -> 0 0.00/0.01 sqr(s(X)) -> s(add(sqr(X),dbl(X))) 0.00/0.01 terms(N) -> cons(recip(sqr(N)),terms(s(N))) 0.00/0.01 -> Unhiding rules: 0.00/0.01 Empty 0.00/0.01 -> Result: 0.00/0.01 Set P is empty 0.00/0.01 0.00/0.01 The problem is finite. 0.00/0.01 0.00/0.01 Problem 1.3: 0.00/0.01 0.00/0.01 SubNColl Processor: 0.00/0.01 -> Pairs: 0.00/0.01 SQR(s(X)) -> SQR(X) 0.00/0.01 -> Rules: 0.00/0.01 add(0,X) -> X 0.00/0.01 add(s(X),Y) -> s(add(X,Y)) 0.00/0.01 dbl(0) -> 0 0.00/0.01 dbl(s(X)) -> s(s(dbl(X))) 0.00/0.01 first(0,X) -> nil 0.00/0.01 first(s(X),cons(Y,Z)) -> cons(Y,first(X,Z)) 0.00/0.01 sqr(0) -> 0 0.00/0.01 sqr(s(X)) -> s(add(sqr(X),dbl(X))) 0.00/0.01 terms(N) -> cons(recip(sqr(N)),terms(s(N))) 0.00/0.01 -> Unhiding rules: 0.00/0.01 Empty 0.00/0.01 ->Projection: 0.00/0.01 pi(SQR) = 1 0.00/0.01 0.00/0.01 Problem 1.3: 0.00/0.01 0.00/0.01 Basic Processor: 0.00/0.01 -> Pairs: 0.00/0.01 Empty 0.00/0.01 -> Rules: 0.00/0.01 add(0,X) -> X 0.00/0.01 add(s(X),Y) -> s(add(X,Y)) 0.00/0.01 dbl(0) -> 0 0.00/0.01 dbl(s(X)) -> s(s(dbl(X))) 0.00/0.01 first(0,X) -> nil 0.00/0.01 first(s(X),cons(Y,Z)) -> cons(Y,first(X,Z)) 0.00/0.01 sqr(0) -> 0 0.00/0.01 sqr(s(X)) -> s(add(sqr(X),dbl(X))) 0.00/0.01 terms(N) -> cons(recip(sqr(N)),terms(s(N))) 0.00/0.01 -> Unhiding rules: 0.00/0.01 Empty 0.00/0.01 -> Result: 0.00/0.01 Set P is empty 0.00/0.01 0.00/0.01 The problem is finite. 0.00/0.01 EOF