0.00/0.05	YES
0.00/0.05	
0.00/0.05	Problem 1: 
0.00/0.05	
0.00/0.05	(VAR x)
0.00/0.05	(THEORY 
0.00/0.05	(AC plus))
0.00/0.05	(RULES
0.00/0.05	f(x) -> plus(g(x),a)
0.00/0.05	plus(f(x),g(x)) -> plus(g(x),plus(g(x),g(x)))
0.00/0.05	)
0.00/0.05	
0.00/0.05	Problem 1: 
0.00/0.05	
0.00/0.05	Reduction Order Processor:
0.00/0.05	-> Rules:
0.00/0.05	 f(x) -> plus(g(x),a)
0.00/0.05	 plus(f(x),g(x)) -> plus(g(x),plus(g(x),g(x)))
0.00/0.05	->Interpretation type:
0.00/0.05	 Linear
0.00/0.05	->Coefficients:
0.00/0.05	 Natural Numbers
0.00/0.05	->Dimension:
0.00/0.05	 1
0.00/0.05	->Bound:
0.00/0.05	 2
0.00/0.05	->Interpretation:
0.00/0.05	 
0.00/0.05	[f](X) = 2.X + 1
0.00/0.05	[plus](X1,X2) = X1 + X2
0.00/0.05	[a] = 0
0.00/0.05	[g](X) = X
0.00/0.05	
0.00/0.05	Problem 1: 
0.00/0.05	
0.00/0.05	Reduction Order Processor:
0.00/0.05	-> Rules:
0.00/0.05	 plus(f(x),g(x)) -> plus(g(x),plus(g(x),g(x)))
0.00/0.05	->Interpretation type:
0.00/0.05	 Linear
0.00/0.05	->Coefficients:
0.00/0.05	 Natural Numbers
0.00/0.05	->Dimension:
0.00/0.05	 1
0.00/0.05	->Bound:
0.00/0.05	 2
0.00/0.05	->Interpretation:
0.00/0.05	 
0.00/0.05	[f](X) = 2.X + 2
0.00/0.05	[plus](X1,X2) = X1 + X2
0.00/0.05	[a] = 0
0.00/0.05	[g](X) = X
0.00/0.05	
0.00/0.05	Problem 1: 
0.00/0.05	
0.00/0.05	Dependency Pairs Processor:
0.00/0.05	-> FAxioms:
0.00/0.05	 PLUS(plus(x1,x2),x3) = PLUS(x1,plus(x2,x3))
0.00/0.05	 PLUS(x1,x2) = PLUS(x2,x1)
0.00/0.05	-> Pairs:
0.00/0.05	 Empty
0.00/0.05	-> EAxioms:
0.00/0.05	 plus(plus(x1,x2),x3) = plus(x1,plus(x2,x3))
0.00/0.05	 plus(x1,x2) = plus(x2,x1)
0.00/0.05	-> Rules:
0.00/0.05	 Empty
0.00/0.05	-> SRules:
0.00/0.05	 PLUS(plus(x1,x2),x3) -> PLUS(x1,x2)
0.00/0.05	 PLUS(x1,plus(x2,x3)) -> PLUS(x2,x3)
0.00/0.05	
0.00/0.05	Problem 1: 
0.00/0.05	
0.00/0.05	SCC Processor:
0.00/0.05	-> FAxioms:
0.00/0.05	 PLUS(plus(x1,x2),x3) = PLUS(x1,plus(x2,x3))
0.00/0.05	 PLUS(x1,x2) = PLUS(x2,x1)
0.00/0.05	-> Pairs:
0.00/0.05	 Empty
0.00/0.05	-> EAxioms:
0.00/0.05	 plus(plus(x1,x2),x3) = plus(x1,plus(x2,x3))
0.00/0.05	 plus(x1,x2) = plus(x2,x1)
0.00/0.05	-> Rules:
0.00/0.05	 Empty
0.00/0.05	-> SRules:
0.00/0.05	 PLUS(plus(x1,x2),x3) -> PLUS(x1,x2)
0.00/0.05	 PLUS(x1,plus(x2,x3)) -> PLUS(x2,x3)
0.00/0.05	->Strongly Connected Components:
0.00/0.05	 There is no strongly connected component
0.00/0.05	
0.00/0.05	The problem is finite.
0.00/0.05	EOF