3.35/1.62 YES 3.35/1.63 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 3.35/1.63 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 3.35/1.63 3.35/1.63 3.35/1.63 Termination w.r.t. Q of the given QTRS could be proven: 3.35/1.63 3.35/1.63 (0) QTRS 3.35/1.63 (1) QTRSRRRProof [EQUIVALENT, 37 ms] 3.35/1.63 (2) QTRS 3.35/1.63 (3) RisEmptyProof [EQUIVALENT, 0 ms] 3.35/1.63 (4) YES 3.35/1.63 3.35/1.63 3.35/1.63 ---------------------------------------- 3.35/1.63 3.35/1.63 (0) 3.35/1.63 Obligation: 3.35/1.63 Q restricted rewrite system: 3.35/1.63 The TRS R consists of the following rules: 3.35/1.63 3.35/1.63 first(0, X) -> nil 3.35/1.63 first(s(X), cons(Y)) -> cons(Y) 3.35/1.63 from(X) -> cons(X) 3.35/1.63 3.35/1.63 The set Q consists of the following terms: 3.35/1.63 3.35/1.63 first(0, x0) 3.35/1.63 first(s(x0), cons(x1)) 3.35/1.63 from(x0) 3.35/1.63 3.35/1.63 3.35/1.63 ---------------------------------------- 3.35/1.63 3.35/1.63 (1) QTRSRRRProof (EQUIVALENT) 3.35/1.63 Used ordering: 3.35/1.63 Knuth-Bendix order [KBO] with precedence:first_2 > from_1 > cons_1 > s_1 > nil > 0 3.35/1.63 3.35/1.63 and weight map: 3.35/1.63 3.35/1.63 0=1 3.35/1.63 nil=2 3.35/1.63 s_1=1 3.35/1.63 cons_1=1 3.35/1.63 from_1=1 3.35/1.63 first_2=0 3.35/1.63 3.35/1.63 The variable weight is 1With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: 3.35/1.63 3.35/1.63 first(0, X) -> nil 3.35/1.63 first(s(X), cons(Y)) -> cons(Y) 3.35/1.63 from(X) -> cons(X) 3.35/1.63 3.35/1.63 3.35/1.63 3.35/1.63 3.35/1.63 ---------------------------------------- 3.35/1.63 3.35/1.63 (2) 3.35/1.63 Obligation: 3.35/1.63 Q restricted rewrite system: 3.35/1.63 R is empty. 3.35/1.63 The set Q consists of the following terms: 3.35/1.63 3.35/1.63 first(0, x0) 3.35/1.63 first(s(x0), cons(x1)) 3.35/1.63 from(x0) 3.35/1.63 3.35/1.63 3.35/1.63 ---------------------------------------- 3.35/1.63 3.35/1.63 (3) RisEmptyProof (EQUIVALENT) 3.35/1.63 The TRS R is empty. Hence, termination is trivially proven. 3.35/1.63 ---------------------------------------- 3.35/1.63 3.35/1.63 (4) 3.35/1.63 YES 3.35/1.66 EOF