9.34/3.15 NO 9.34/3.17 proof of /export/starexec/sandbox/benchmark/theBenchmark.c 9.34/3.17 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 9.34/3.17 9.34/3.17 9.34/3.17 Termination of the given C Problem could be disproven: 9.34/3.17 9.34/3.17 (0) C Problem 9.34/3.17 (1) CToIRSProof [EQUIVALENT, 0 ms] 9.34/3.17 (2) IntTRS 9.34/3.17 (3) IRS2T2 [EQUIVALENT, 0 ms] 9.34/3.17 (4) T2IntSys 9.34/3.17 (5) T2 [COMPLETE, 1443 ms] 9.34/3.17 (6) NO 9.34/3.17 9.34/3.17 9.34/3.17 ---------------------------------------- 9.34/3.17 9.34/3.17 (0) 9.34/3.17 Obligation: 9.34/3.17 c file /export/starexec/sandbox/benchmark/theBenchmark.c 9.34/3.17 ---------------------------------------- 9.34/3.17 9.34/3.17 (1) CToIRSProof (EQUIVALENT) 9.34/3.17 Parsed C Integer Program as IRS. 9.34/3.17 ---------------------------------------- 9.34/3.17 9.34/3.17 (2) 9.34/3.17 Obligation: 9.34/3.17 Rules: 9.34/3.17 f1(i, j) -> f2(x_1, j) :|: TRUE 9.34/3.17 f3(x, x1) -> f4(x, x) :|: TRUE 9.34/3.17 f5(x2, x3) -> f6(x2, arith) :|: TRUE && arith = x3 + 1 9.34/3.17 f4(x4, x5) -> f5(x4, x5) :|: x5 > 5 9.34/3.17 f6(x6, x7) -> f4(x6, x7) :|: TRUE 9.34/3.17 f4(x8, x9) -> f7(x8, x9) :|: x9 <= 5 9.34/3.17 f7(x18, x19) -> f8(x20, x19) :|: TRUE && x20 = x18 + 1 9.34/3.17 f2(x12, x13) -> f3(x12, x13) :|: x12 < 10 9.34/3.17 f8(x14, x15) -> f2(x14, x15) :|: TRUE 9.34/3.17 f2(x16, x17) -> f9(x16, x17) :|: x16 >= 10 9.34/3.17 Start term: f1(i, j) 9.34/3.17 9.34/3.17 ---------------------------------------- 9.34/3.17 9.34/3.17 (3) IRS2T2 (EQUIVALENT) 9.34/3.17 Transformed input IRS into an integer transition system.Used the following mapping from defined symbols to location IDs: 9.34/3.17 9.34/3.17 (f1_2,1) 9.34/3.17 (f2_2,2) 9.34/3.17 (f3_2,3) 9.34/3.17 (f4_2,4) 9.34/3.17 (f5_2,5) 9.34/3.17 (f6_2,6) 9.34/3.17 (f7_2,7) 9.34/3.17 (f8_2,8) 9.34/3.17 (f9_2,9) 9.34/3.17 9.34/3.17 ---------------------------------------- 9.34/3.17 9.34/3.17 (4) 9.34/3.17 Obligation: 9.34/3.17 START: 1; 9.34/3.17 9.34/3.17 FROM: 1; 9.34/3.17 oldX0 := x0; 9.34/3.17 oldX1 := x1; 9.34/3.17 oldX2 := nondet(); 9.34/3.17 assume(0 = 0); 9.34/3.17 x0 := oldX2; 9.34/3.17 x1 := oldX1; 9.34/3.17 TO: 2; 9.34/3.17 9.34/3.17 FROM: 3; 9.34/3.17 oldX0 := x0; 9.34/3.17 oldX1 := x1; 9.34/3.17 assume(0 = 0); 9.34/3.17 x0 := oldX0; 9.34/3.17 x1 := oldX0; 9.34/3.17 TO: 4; 9.34/3.17 9.34/3.17 FROM: 5; 9.34/3.17 oldX0 := x0; 9.34/3.17 oldX1 := x1; 9.34/3.17 oldX2 := -(-(oldX1 + 1)); 9.34/3.17 assume(0 = 0 && oldX2 = oldX1 + 1); 9.34/3.17 x0 := oldX0; 9.34/3.17 x1 := -(-(oldX1 + 1)); 9.34/3.17 TO: 6; 9.34/3.17 9.34/3.17 FROM: 4; 9.34/3.17 oldX0 := x0; 9.34/3.17 oldX1 := x1; 9.34/3.17 assume(oldX1 > 5); 9.34/3.17 x0 := oldX0; 9.34/3.17 x1 := oldX1; 9.34/3.17 TO: 5; 9.34/3.17 9.34/3.17 FROM: 6; 9.34/3.17 oldX0 := x0; 9.34/3.17 oldX1 := x1; 9.34/3.17 assume(0 = 0); 9.34/3.17 x0 := oldX0; 9.34/3.17 x1 := oldX1; 9.34/3.17 TO: 4; 9.34/3.17 9.34/3.17 FROM: 4; 9.34/3.17 oldX0 := x0; 9.34/3.17 oldX1 := x1; 9.34/3.17 assume(oldX1 <= 5); 9.34/3.17 x0 := oldX0; 9.34/3.17 x1 := oldX1; 9.34/3.17 TO: 7; 9.34/3.17 9.34/3.17 FROM: 7; 9.34/3.17 oldX0 := x0; 9.34/3.17 oldX1 := x1; 9.34/3.17 oldX2 := -(-(oldX0 + 1)); 9.34/3.17 assume(0 = 0 && oldX2 = oldX0 + 1); 9.34/3.17 x0 := -(-(oldX0 + 1)); 9.34/3.17 x1 := oldX1; 9.34/3.17 TO: 8; 9.34/3.17 9.34/3.17 FROM: 2; 9.34/3.17 oldX0 := x0; 9.34/3.17 oldX1 := x1; 9.34/3.17 assume(oldX0 < 10); 9.34/3.17 x0 := oldX0; 9.34/3.17 x1 := oldX1; 9.34/3.17 TO: 3; 9.34/3.17 9.34/3.17 FROM: 8; 9.34/3.17 oldX0 := x0; 9.34/3.17 oldX1 := x1; 9.34/3.17 assume(0 = 0); 9.34/3.17 x0 := oldX0; 9.34/3.17 x1 := oldX1; 9.34/3.17 TO: 2; 9.34/3.17 9.34/3.17 FROM: 2; 9.34/3.17 oldX0 := x0; 9.34/3.17 oldX1 := x1; 9.34/3.17 assume(oldX0 >= 10); 9.34/3.17 x0 := oldX0; 9.34/3.17 x1 := oldX1; 9.34/3.17 TO: 9; 9.34/3.17 9.34/3.17 9.34/3.17 ---------------------------------------- 9.34/3.17 9.34/3.17 (5) T2 (COMPLETE) 9.34/3.17 Found this recurrent set for cutpoint 8: oldX0 <= 9 and oldX2 <= 9 and x0 <= 9 and oldX0-x1 <= 0 and oldX2-oldX0 <= 0 and oldX0-oldX2 <= 0 and oldX2+oldX0 <= 18 and oldX2-x0 <= 0 and x0-oldX2 <= 0 and oldX2+x0 <= 18 and oldX2-x1 <= 0 and x0-oldX0 <= 0 and oldX0-x0 <= 0 and x0+oldX0 <= 18 and x0-x1 <= 0 and -x1+6 <= 0 9.34/3.17 9.34/3.17 ---------------------------------------- 9.34/3.17 9.34/3.17 (6) 9.34/3.17 NO 9.61/3.24 EOF