9.23/3.33 NO 9.23/3.34 proof of /export/starexec/sandbox/benchmark/theBenchmark.c 9.23/3.34 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 9.23/3.34 9.23/3.34 9.23/3.34 Termination of the given C Problem could be disproven: 9.23/3.34 9.23/3.34 (0) C Problem 9.23/3.34 (1) CToIRSProof [EQUIVALENT, 0 ms] 9.23/3.34 (2) IntTRS 9.23/3.34 (3) IRS2T2 [EQUIVALENT, 0 ms] 9.23/3.34 (4) T2IntSys 9.23/3.34 (5) T2 [COMPLETE, 1277 ms] 9.23/3.34 (6) NO 9.23/3.34 9.23/3.34 9.23/3.34 ---------------------------------------- 9.23/3.34 9.23/3.34 (0) 9.23/3.34 Obligation: 9.23/3.34 c file /export/starexec/sandbox/benchmark/theBenchmark.c 9.23/3.34 ---------------------------------------- 9.23/3.34 9.23/3.34 (1) CToIRSProof (EQUIVALENT) 9.23/3.34 Parsed C Integer Program as IRS. 9.23/3.34 ---------------------------------------- 9.23/3.34 9.23/3.34 (2) 9.23/3.34 Obligation: 9.23/3.34 Rules: 9.23/3.34 f1(x) -> f2(x_1) :|: TRUE 9.23/3.34 f3(x1) -> f4(arith) :|: TRUE && arith = x1 + x2 9.23/3.34 f2(x3) -> f3(x3) :|: x3 >= 0 9.23/3.34 f4(x4) -> f2(x4) :|: TRUE 9.23/3.34 f2(x5) -> f5(x5) :|: x5 < 0 9.23/3.34 Start term: f1(x) 9.23/3.34 9.23/3.34 ---------------------------------------- 9.23/3.34 9.23/3.34 (3) IRS2T2 (EQUIVALENT) 9.23/3.34 Transformed input IRS into an integer transition system.Used the following mapping from defined symbols to location IDs: 9.23/3.34 9.23/3.34 (f1_1,1) 9.23/3.34 (f2_1,2) 9.23/3.34 (f3_1,3) 9.23/3.34 (f4_1,4) 9.23/3.34 (f5_1,5) 9.23/3.34 9.23/3.34 ---------------------------------------- 9.23/3.34 9.23/3.34 (4) 9.23/3.34 Obligation: 9.23/3.34 START: 1; 9.23/3.34 9.23/3.34 FROM: 1; 9.23/3.34 oldX0 := x0; 9.23/3.34 oldX1 := nondet(); 9.23/3.34 assume(0 = 0); 9.23/3.34 x0 := oldX1; 9.23/3.34 TO: 2; 9.23/3.34 9.23/3.34 FROM: 3; 9.23/3.34 oldX0 := x0; 9.23/3.34 oldX1 := nondet(); 9.23/3.34 oldX2 := nondet(); 9.23/3.34 assume(0 = 0 && oldX1 = oldX0 + oldX2); 9.23/3.34 x0 := oldX1; 9.23/3.34 TO: 4; 9.23/3.34 9.23/3.34 FROM: 2; 9.23/3.34 oldX0 := x0; 9.23/3.34 assume(oldX0 >= 0); 9.23/3.34 x0 := oldX0; 9.23/3.34 TO: 3; 9.23/3.34 9.23/3.34 FROM: 4; 9.23/3.34 oldX0 := x0; 9.23/3.34 assume(0 = 0); 9.23/3.34 x0 := oldX0; 9.23/3.34 TO: 2; 9.23/3.34 9.23/3.34 FROM: 2; 9.23/3.34 oldX0 := x0; 9.23/3.34 assume(oldX0 < 0); 9.23/3.34 x0 := oldX0; 9.23/3.34 TO: 5; 9.23/3.34 9.23/3.34 9.23/3.34 ---------------------------------------- 9.23/3.34 9.23/3.34 (5) T2 (COMPLETE) 9.23/3.34 Found this recurrent set for cutpoint 6: oldX1 == 0 and oldX2 == 0 and x0 == 0 9.23/3.34 9.23/3.34 ---------------------------------------- 9.23/3.34 9.23/3.34 (6) 9.23/3.34 NO 10.08/3.36 EOF