40.07/40.16	NO
40.07/40.16	
40.07/40.16	Problem 1: 
40.07/40.16	
40.07/40.16	(VAR v_NonEmpty:S x:S)
40.07/40.16	(RULES
40.07/40.16	a(x:S) -> b | p(x:S) ->* 0
40.07/40.16	c -> c
40.07/40.16	p(q(x:S)) -> 0
40.07/40.16	)
40.07/40.16	
40.07/40.16	Problem 1: 
40.07/40.16	Valid CTRS Processor:
40.07/40.16	-> Rules:
40.07/40.16	 a(x:S) -> b | p(x:S) ->* 0
40.07/40.16	 c -> c
40.07/40.16	 p(q(x:S)) -> 0
40.07/40.16	-> The system is a deterministic 3-CTRS.
40.07/40.16	
40.07/40.16	Problem 1: 
40.07/40.16	
40.07/40.16	Dependency Pairs Processor:
40.07/40.16	
40.07/40.16	Conditional Termination Problem 1:
40.07/40.16	-> Pairs:
40.07/40.16	 C -> C
40.07/40.16	-> QPairs:
40.07/40.16	 Empty
40.07/40.16	-> Rules:
40.07/40.16	 a(x:S) -> b | p(x:S) ->* 0
40.07/40.16	 c -> c
40.07/40.16	 p(q(x:S)) -> 0
40.07/40.16	
40.07/40.16	Conditional Termination Problem 2:
40.07/40.16	-> Pairs:
40.07/40.16	 A(x:S) -> P(x:S)
40.07/40.16	-> QPairs:
40.07/40.16	 Empty
40.07/40.16	-> Rules:
40.07/40.16	 a(x:S) -> b | p(x:S) ->* 0
40.07/40.16	 c -> c
40.07/40.16	 p(q(x:S)) -> 0
40.07/40.16	
40.07/40.16	Problem 1: 
40.07/40.16	
40.07/40.16	SCC Processor:
40.07/40.16	-> Pairs:
40.07/40.16	 C -> C
40.07/40.16	-> QPairs:
40.07/40.16	 Empty
40.07/40.16	-> Rules:
40.07/40.16	 a(x:S) -> b | p(x:S) ->* 0
40.07/40.16	 c -> c
40.07/40.16	 p(q(x:S)) -> 0
40.07/40.16	->Strongly Connected Components:
40.07/40.16	->->Cycle:
40.07/40.16	->->-> Pairs:
40.07/40.16	 C -> C
40.07/40.16	-> QPairs:
40.07/40.16	 Empty
40.07/40.16	->->-> Rules:
40.07/40.16	 a(x:S) -> b | p(x:S) ->* 0
40.07/40.16	 c -> c
40.07/40.16	 p(q(x:S)) -> 0
40.07/40.16	
40.07/40.16	Problem 1: 
40.07/40.16	
40.07/40.16	Infinite Processor:
40.07/40.16	-> Pairs:
40.07/40.16	 C -> C
40.07/40.16	-> QPairs:
40.07/40.16	 Empty
40.07/40.16	-> Rules:
40.07/40.16	 a(x:S) -> b | p(x:S) ->* 0
40.07/40.16	 c -> c
40.07/40.16	 p(q(x:S)) -> 0
40.07/40.16	-> Pairs in cycle:
40.07/40.16	 C -> C
40.07/40.16	
40.07/40.16	The problem is infinite.
40.07/40.16	EOF