4.69/2.27 MAYBE 4.69/2.28 proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml 4.69/2.28 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 4.69/2.28 4.69/2.28 4.69/2.28 Quasi decreasingness of the given CTRS could not be shown: 4.69/2.28 4.69/2.28 (0) CTRS 4.69/2.28 (1) CTRSToQTRSProof [SOUND, 0 ms] 4.69/2.28 (2) QTRS 4.69/2.28 (3) QTRSRRRProof [EQUIVALENT, 0 ms] 4.69/2.28 (4) QTRS 4.69/2.28 (5) Overlay + Local Confluence [EQUIVALENT, 0 ms] 4.69/2.28 (6) QTRS 4.69/2.28 (7) DependencyPairsProof [EQUIVALENT, 0 ms] 4.69/2.28 (8) QDP 4.69/2.28 (9) UsableRulesProof [EQUIVALENT, 0 ms] 4.69/2.28 (10) QDP 4.69/2.28 (11) QReductionProof [EQUIVALENT, 0 ms] 4.69/2.28 (12) QDP 4.69/2.28 (13) NonTerminationLoopProof [COMPLETE, 0 ms] 4.69/2.28 (14) NO 4.69/2.28 4.69/2.28 4.69/2.28 ---------------------------------------- 4.69/2.28 4.69/2.28 (0) 4.69/2.28 Obligation: 4.69/2.28 Conditional term rewrite system: 4.69/2.28 The TRS R consists of the following rules: 4.69/2.28 4.69/2.28 a -> b 4.69/2.28 a -> c 4.69/2.28 4.69/2.28 The conditional TRS C consists of the following conditional rules: 4.69/2.28 4.69/2.28 b -> c <= b -> c 4.69/2.28 4.69/2.28 4.69/2.28 ---------------------------------------- 4.69/2.28 4.69/2.28 (1) CTRSToQTRSProof (SOUND) 4.69/2.28 The conditional rules have been transormed into unconditional rules according to [CTRS,AAECCNOC]. 4.69/2.28 ---------------------------------------- 4.69/2.28 4.69/2.28 (2) 4.69/2.28 Obligation: 4.69/2.28 Q restricted rewrite system: 4.69/2.28 The TRS R consists of the following rules: 4.69/2.28 4.69/2.28 b -> U1(b) 4.69/2.28 U1(c) -> c 4.69/2.28 a -> b 4.69/2.28 a -> c 4.69/2.28 4.69/2.28 Q is empty. 4.69/2.28 4.69/2.28 ---------------------------------------- 4.69/2.28 4.69/2.28 (3) QTRSRRRProof (EQUIVALENT) 4.69/2.28 Used ordering: 4.69/2.28 Polynomial interpretation [POLO]: 4.69/2.28 4.69/2.28 POL(U1(x_1)) = 2*x_1 4.69/2.28 POL(a) = 2 4.69/2.28 POL(b) = 0 4.69/2.28 POL(c) = 1 4.69/2.28 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: 4.69/2.28 4.69/2.28 U1(c) -> c 4.69/2.28 a -> b 4.69/2.28 a -> c 4.69/2.28 4.69/2.28 4.69/2.28 4.69/2.28 4.69/2.28 ---------------------------------------- 4.69/2.28 4.69/2.28 (4) 4.69/2.28 Obligation: 4.69/2.28 Q restricted rewrite system: 4.69/2.28 The TRS R consists of the following rules: 4.69/2.28 4.69/2.28 b -> U1(b) 4.69/2.28 4.69/2.28 Q is empty. 4.69/2.28 4.69/2.28 ---------------------------------------- 4.69/2.28 4.69/2.28 (5) Overlay + Local Confluence (EQUIVALENT) 4.69/2.28 The TRS is overlay and locally confluent. By [NOC] we can switch to innermost. 4.69/2.28 ---------------------------------------- 4.69/2.28 4.69/2.28 (6) 4.69/2.28 Obligation: 4.69/2.28 Q restricted rewrite system: 4.69/2.28 The TRS R consists of the following rules: 4.69/2.28 4.69/2.28 b -> U1(b) 4.69/2.28 4.69/2.28 The set Q consists of the following terms: 4.69/2.28 4.69/2.28 b 4.69/2.28 4.69/2.28 4.69/2.28 ---------------------------------------- 4.69/2.28 4.69/2.28 (7) DependencyPairsProof (EQUIVALENT) 4.69/2.28 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 4.69/2.28 ---------------------------------------- 4.69/2.28 4.69/2.28 (8) 4.69/2.28 Obligation: 4.69/2.28 Q DP problem: 4.69/2.28 The TRS P consists of the following rules: 4.69/2.28 4.69/2.28 B -> B 4.69/2.28 4.69/2.28 The TRS R consists of the following rules: 4.69/2.28 4.69/2.28 b -> U1(b) 4.69/2.28 4.69/2.28 The set Q consists of the following terms: 4.69/2.28 4.69/2.28 b 4.69/2.28 4.69/2.28 We have to consider all minimal (P,Q,R)-chains. 4.69/2.28 ---------------------------------------- 4.69/2.28 4.69/2.28 (9) UsableRulesProof (EQUIVALENT) 4.69/2.28 As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R. 4.69/2.28 ---------------------------------------- 4.69/2.28 4.69/2.28 (10) 4.69/2.28 Obligation: 4.69/2.28 Q DP problem: 4.69/2.28 The TRS P consists of the following rules: 4.69/2.28 4.69/2.28 B -> B 4.69/2.28 4.69/2.28 R is empty. 4.69/2.28 The set Q consists of the following terms: 4.69/2.28 4.69/2.28 b 4.69/2.28 4.69/2.28 We have to consider all minimal (P,Q,R)-chains. 4.69/2.28 ---------------------------------------- 4.69/2.28 4.69/2.28 (11) QReductionProof (EQUIVALENT) 4.69/2.28 We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN]. 4.69/2.28 4.69/2.28 b 4.69/2.28 4.69/2.28 4.69/2.28 ---------------------------------------- 4.69/2.28 4.69/2.28 (12) 4.69/2.28 Obligation: 4.69/2.28 Q DP problem: 4.69/2.28 The TRS P consists of the following rules: 4.69/2.28 4.69/2.28 B -> B 4.69/2.28 4.69/2.28 R is empty. 4.69/2.28 Q is empty. 4.69/2.28 We have to consider all minimal (P,Q,R)-chains. 4.69/2.28 ---------------------------------------- 4.69/2.28 4.69/2.28 (13) NonTerminationLoopProof (COMPLETE) 4.69/2.28 We used the non-termination processor [FROCOS05] to show that the DP problem is infinite. 4.69/2.28 Found a loop by semiunifying a rule from P directly. 4.69/2.28 4.69/2.28 s = B evaluates to t =B 4.69/2.28 4.69/2.28 Thus s starts an infinite chain as s semiunifies with t with the following substitutions: 4.69/2.28 * Matcher: [ ] 4.69/2.28 * Semiunifier: [ ] 4.69/2.28 4.69/2.28 -------------------------------------------------------------------------------- 4.69/2.28 Rewriting sequence 4.69/2.28 4.69/2.28 The DP semiunifies directly so there is only one rewrite step from B to B. 4.69/2.28 4.69/2.28 4.69/2.28 4.69/2.28 4.69/2.28 ---------------------------------------- 4.69/2.28 4.69/2.28 (14) 4.69/2.28 NO 4.69/2.31 EOF