3.58/1.71 YES 3.61/1.72 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 3.61/1.72 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 3.61/1.72 3.61/1.72 3.61/1.72 Quasi decreasingness of the given CTRS could be proven: 3.61/1.72 3.61/1.72 (0) CTRS 3.61/1.72 (1) CTRSToQTRSProof [SOUND, 0 ms] 3.61/1.72 (2) QTRS 3.61/1.72 (3) QTRSRRRProof [EQUIVALENT, 51 ms] 3.61/1.72 (4) QTRS 3.61/1.72 (5) QTRSRRRProof [EQUIVALENT, 0 ms] 3.61/1.72 (6) QTRS 3.61/1.72 (7) AAECC Innermost [EQUIVALENT, 0 ms] 3.61/1.72 (8) QTRS 3.61/1.72 (9) DependencyPairsProof [EQUIVALENT, 0 ms] 3.61/1.72 (10) QDP 3.61/1.72 (11) DependencyGraphProof [EQUIVALENT, 0 ms] 3.61/1.72 (12) TRUE 3.61/1.72 3.61/1.72 3.61/1.72 ---------------------------------------- 3.61/1.72 3.61/1.72 (0) 3.61/1.72 Obligation: 3.61/1.72 Conditional term rewrite system: 3.61/1.72 The TRS R consists of the following rules: 3.61/1.72 3.61/1.72 b -> c 3.61/1.72 f(b) -> f(a) 3.61/1.72 3.61/1.72 The conditional TRS C consists of the following conditional rules: 3.61/1.72 3.61/1.72 a -> c <= b -> c 3.61/1.72 3.61/1.72 3.61/1.72 ---------------------------------------- 3.61/1.72 3.61/1.72 (1) CTRSToQTRSProof (SOUND) 3.61/1.72 The conditional rules have been transormed into unconditional rules according to [CTRS,AAECCNOC]. 3.61/1.72 ---------------------------------------- 3.61/1.72 3.61/1.72 (2) 3.61/1.72 Obligation: 3.61/1.72 Q restricted rewrite system: 3.61/1.72 The TRS R consists of the following rules: 3.61/1.72 3.61/1.72 a -> U1(b) 3.61/1.72 U1(c) -> c 3.61/1.72 b -> c 3.61/1.72 f(b) -> f(a) 3.61/1.72 3.61/1.72 Q is empty. 3.61/1.72 3.61/1.72 ---------------------------------------- 3.61/1.72 3.61/1.72 (3) QTRSRRRProof (EQUIVALENT) 3.61/1.72 Used ordering: 3.61/1.72 Polynomial interpretation [POLO]: 3.61/1.72 3.61/1.72 POL(U1(x_1)) = x_1 3.61/1.72 POL(a) = 1 3.61/1.72 POL(b) = 1 3.61/1.72 POL(c) = 0 3.61/1.72 POL(f(x_1)) = x_1 3.61/1.72 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: 3.61/1.72 3.61/1.72 b -> c 3.61/1.72 3.61/1.72 3.61/1.72 3.61/1.72 3.61/1.72 ---------------------------------------- 3.61/1.72 3.61/1.72 (4) 3.61/1.72 Obligation: 3.61/1.72 Q restricted rewrite system: 3.61/1.72 The TRS R consists of the following rules: 3.61/1.72 3.61/1.72 a -> U1(b) 3.61/1.72 U1(c) -> c 3.61/1.72 f(b) -> f(a) 3.61/1.72 3.61/1.72 Q is empty. 3.61/1.72 3.61/1.72 ---------------------------------------- 3.61/1.72 3.61/1.72 (5) QTRSRRRProof (EQUIVALENT) 3.61/1.72 Used ordering: 3.61/1.72 Polynomial interpretation [POLO]: 3.61/1.72 3.61/1.72 POL(U1(x_1)) = 2*x_1 3.61/1.72 POL(a) = 0 3.61/1.72 POL(b) = 0 3.61/1.72 POL(c) = 2 3.61/1.72 POL(f(x_1)) = 2*x_1 3.61/1.72 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: 3.61/1.72 3.61/1.72 U1(c) -> c 3.61/1.72 3.61/1.72 3.61/1.72 3.61/1.72 3.61/1.72 ---------------------------------------- 3.61/1.72 3.61/1.72 (6) 3.61/1.72 Obligation: 3.61/1.72 Q restricted rewrite system: 3.61/1.72 The TRS R consists of the following rules: 3.61/1.72 3.61/1.72 a -> U1(b) 3.61/1.72 f(b) -> f(a) 3.61/1.72 3.61/1.72 Q is empty. 3.61/1.72 3.61/1.72 ---------------------------------------- 3.61/1.72 3.61/1.72 (7) AAECC Innermost (EQUIVALENT) 3.61/1.72 We have applied [NOC,AAECCNOC] to switch to innermost. The TRS R 1 is 3.61/1.72 a -> U1(b) 3.61/1.72 3.61/1.72 The TRS R 2 is 3.61/1.72 f(b) -> f(a) 3.61/1.72 3.61/1.72 The signature Sigma is {f_1} 3.61/1.72 ---------------------------------------- 3.61/1.72 3.61/1.72 (8) 3.61/1.72 Obligation: 3.61/1.72 Q restricted rewrite system: 3.61/1.72 The TRS R consists of the following rules: 3.61/1.72 3.61/1.72 a -> U1(b) 3.61/1.72 f(b) -> f(a) 3.61/1.72 3.61/1.72 The set Q consists of the following terms: 3.61/1.72 3.61/1.72 a 3.61/1.72 f(b) 3.61/1.72 3.61/1.72 3.61/1.72 ---------------------------------------- 3.61/1.72 3.61/1.72 (9) DependencyPairsProof (EQUIVALENT) 3.61/1.72 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 3.61/1.72 ---------------------------------------- 3.61/1.72 3.61/1.72 (10) 3.61/1.72 Obligation: 3.61/1.72 Q DP problem: 3.61/1.72 The TRS P consists of the following rules: 3.61/1.72 3.61/1.72 F(b) -> F(a) 3.61/1.72 F(b) -> A 3.61/1.72 3.61/1.72 The TRS R consists of the following rules: 3.61/1.72 3.61/1.72 a -> U1(b) 3.61/1.72 f(b) -> f(a) 3.61/1.72 3.61/1.72 The set Q consists of the following terms: 3.61/1.72 3.61/1.72 a 3.61/1.72 f(b) 3.61/1.72 3.61/1.72 We have to consider all minimal (P,Q,R)-chains. 3.61/1.72 ---------------------------------------- 3.61/1.72 3.61/1.72 (11) DependencyGraphProof (EQUIVALENT) 3.61/1.72 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 0 SCCs with 2 less nodes. 3.61/1.72 ---------------------------------------- 3.61/1.72 3.61/1.72 (12) 3.61/1.72 TRUE 3.64/1.75 EOF