7.93/8.27	MAYBE
7.93/8.27	
7.93/8.27	DP problem for innermost termination.
7.93/8.27	P =
7.93/8.27	  init#(x1, x2, x3) -> f1#(rnd1, rnd2, rnd3) 
7.93/8.27	  f3#(I0, I1, I2) -> f2#(I0 + 1, I1 - 2, I0 + 1 + I1 - 2) [-2 <= I0 - 1 /\ 0 <= I2 - 1 /\ I1 - 2 * y1 = 0 /\ I1 - 2 * y1 <= 1 /\ 0 <= I1 - 2 * y1]
7.93/8.27	  f2#(I3, I4, I5) -> f3#(I3, I4, I5) [-2 <= I3 - 1 /\ I4 - 2 * I6 = 0 /\ 0 <= I5 - 1]
7.93/8.27	  f3#(I7, I8, I9) -> f2#(I7 + 1, I8, I7 + 1 + I8) [0 <= I8 - 2 * I10 - 1 /\ -2 <= I7 - 1 /\ I8 - 2 * I10 <= 1 /\ 0 <= I9 - 1]
7.93/8.27	  f2#(I11, I12, I13) -> f3#(I11, I12, I13) [-2 <= I11 - 1 /\ 0 <= I12 - 2 * I14 - 1 /\ 0 <= I13 - 1]
7.93/8.27	  f2#(I15, I16, I17) -> f3#(I15, I16, I17) [-2 <= I15 - 1 /\ I16 - 2 * I18 <= -1 /\ 0 <= I17 - 1]
7.93/8.27	  f1#(I19, I20, I21) -> f2#(I22, I23, I24) [I22 + I23 = I24 /\ 0 <= I19 - 1 /\ -1 <= I23 - 1 /\ 1 <= I20 - 1 /\ -1 <= I22 - 1]
7.93/8.27	R = 
7.93/8.27	  init(x1, x2, x3) -> f1(rnd1, rnd2, rnd3) 
7.93/8.27	  f3(I0, I1, I2) -> f2(I0 + 1, I1 - 2, I0 + 1 + I1 - 2) [-2 <= I0 - 1 /\ 0 <= I2 - 1 /\ I1 - 2 * y1 = 0 /\ I1 - 2 * y1 <= 1 /\ 0 <= I1 - 2 * y1]
7.93/8.27	  f2(I3, I4, I5) -> f3(I3, I4, I5) [-2 <= I3 - 1 /\ I4 - 2 * I6 = 0 /\ 0 <= I5 - 1]
7.93/8.27	  f3(I7, I8, I9) -> f2(I7 + 1, I8, I7 + 1 + I8) [0 <= I8 - 2 * I10 - 1 /\ -2 <= I7 - 1 /\ I8 - 2 * I10 <= 1 /\ 0 <= I9 - 1]
7.93/8.27	  f2(I11, I12, I13) -> f3(I11, I12, I13) [-2 <= I11 - 1 /\ 0 <= I12 - 2 * I14 - 1 /\ 0 <= I13 - 1]
7.93/8.27	  f2(I15, I16, I17) -> f3(I15, I16, I17) [-2 <= I15 - 1 /\ I16 - 2 * I18 <= -1 /\ 0 <= I17 - 1]
7.93/8.27	  f1(I19, I20, I21) -> f2(I22, I23, I24) [I22 + I23 = I24 /\ 0 <= I19 - 1 /\ -1 <= I23 - 1 /\ 1 <= I20 - 1 /\ -1 <= I22 - 1]
7.93/8.27	
7.93/8.27	The dependency graph for this problem is:
7.93/8.27	  0 -> 6
7.93/8.27	  1 -> 2, 4, 5
7.93/8.27	  2 -> 1
7.93/8.27	  3 -> 4, 5
7.93/8.27	  4 -> 1, 3
7.93/8.27	  5 -> 1, 3
7.93/8.27	  6 -> 2, 4, 5
7.93/8.27	Where:
7.93/8.27	  0) init#(x1, x2, x3) -> f1#(rnd1, rnd2, rnd3) 
7.93/8.27	  1) f3#(I0, I1, I2) -> f2#(I0 + 1, I1 - 2, I0 + 1 + I1 - 2) [-2 <= I0 - 1 /\ 0 <= I2 - 1 /\ I1 - 2 * y1 = 0 /\ I1 - 2 * y1 <= 1 /\ 0 <= I1 - 2 * y1]
7.93/8.27	  2) f2#(I3, I4, I5) -> f3#(I3, I4, I5) [-2 <= I3 - 1 /\ I4 - 2 * I6 = 0 /\ 0 <= I5 - 1]
7.93/8.27	  3) f3#(I7, I8, I9) -> f2#(I7 + 1, I8, I7 + 1 + I8) [0 <= I8 - 2 * I10 - 1 /\ -2 <= I7 - 1 /\ I8 - 2 * I10 <= 1 /\ 0 <= I9 - 1]
7.93/8.27	  4) f2#(I11, I12, I13) -> f3#(I11, I12, I13) [-2 <= I11 - 1 /\ 0 <= I12 - 2 * I14 - 1 /\ 0 <= I13 - 1]
7.93/8.27	  5) f2#(I15, I16, I17) -> f3#(I15, I16, I17) [-2 <= I15 - 1 /\ I16 - 2 * I18 <= -1 /\ 0 <= I17 - 1]
7.93/8.27	  6) f1#(I19, I20, I21) -> f2#(I22, I23, I24) [I22 + I23 = I24 /\ 0 <= I19 - 1 /\ -1 <= I23 - 1 /\ 1 <= I20 - 1 /\ -1 <= I22 - 1]
7.93/8.27	
7.93/8.27	We have the following SCCs.
7.93/8.27	  { 1, 2, 3, 4, 5 }
7.93/8.27	
7.93/8.27	DP problem for innermost termination.
7.93/8.27	P =
7.93/8.27	  f3#(I0, I1, I2) -> f2#(I0 + 1, I1 - 2, I0 + 1 + I1 - 2) [-2 <= I0 - 1 /\ 0 <= I2 - 1 /\ I1 - 2 * y1 = 0 /\ I1 - 2 * y1 <= 1 /\ 0 <= I1 - 2 * y1]
7.93/8.27	  f2#(I3, I4, I5) -> f3#(I3, I4, I5) [-2 <= I3 - 1 /\ I4 - 2 * I6 = 0 /\ 0 <= I5 - 1]
7.93/8.27	  f3#(I7, I8, I9) -> f2#(I7 + 1, I8, I7 + 1 + I8) [0 <= I8 - 2 * I10 - 1 /\ -2 <= I7 - 1 /\ I8 - 2 * I10 <= 1 /\ 0 <= I9 - 1]
7.93/8.27	  f2#(I11, I12, I13) -> f3#(I11, I12, I13) [-2 <= I11 - 1 /\ 0 <= I12 - 2 * I14 - 1 /\ 0 <= I13 - 1]
7.93/8.27	  f2#(I15, I16, I17) -> f3#(I15, I16, I17) [-2 <= I15 - 1 /\ I16 - 2 * I18 <= -1 /\ 0 <= I17 - 1]
7.93/8.27	R = 
7.93/8.27	  init(x1, x2, x3) -> f1(rnd1, rnd2, rnd3) 
7.93/8.27	  f3(I0, I1, I2) -> f2(I0 + 1, I1 - 2, I0 + 1 + I1 - 2) [-2 <= I0 - 1 /\ 0 <= I2 - 1 /\ I1 - 2 * y1 = 0 /\ I1 - 2 * y1 <= 1 /\ 0 <= I1 - 2 * y1]
7.93/8.27	  f2(I3, I4, I5) -> f3(I3, I4, I5) [-2 <= I3 - 1 /\ I4 - 2 * I6 = 0 /\ 0 <= I5 - 1]
7.93/8.27	  f3(I7, I8, I9) -> f2(I7 + 1, I8, I7 + 1 + I8) [0 <= I8 - 2 * I10 - 1 /\ -2 <= I7 - 1 /\ I8 - 2 * I10 <= 1 /\ 0 <= I9 - 1]
7.93/8.27	  f2(I11, I12, I13) -> f3(I11, I12, I13) [-2 <= I11 - 1 /\ 0 <= I12 - 2 * I14 - 1 /\ 0 <= I13 - 1]
7.93/8.27	  f2(I15, I16, I17) -> f3(I15, I16, I17) [-2 <= I15 - 1 /\ I16 - 2 * I18 <= -1 /\ 0 <= I17 - 1]
7.93/8.27	  f1(I19, I20, I21) -> f2(I22, I23, I24) [I22 + I23 = I24 /\ 0 <= I19 - 1 /\ -1 <= I23 - 1 /\ 1 <= I20 - 1 /\ -1 <= I22 - 1]
7.93/8.27	
7.93/11.24	EOF