0.00/0.06 MAYBE 0.00/0.06 0.00/0.06 DP problem for innermost termination. 0.00/0.06 P = 0.00/0.06 init# -> f1# 0.00/0.06 f2# -> f2# 0.00/0.06 f1# -> f2# 0.00/0.06 R = 0.00/0.06 init -> f1 0.00/0.06 f2 -> f2 0.00/0.06 f1 -> f2 0.00/0.06 0.00/0.06 The dependency graph for this problem is: 0.00/0.06 0 -> 2 0.00/0.06 1 -> 1 0.00/0.06 2 -> 1 0.00/0.06 Where: 0.00/0.06 0) init# -> f1# 0.00/0.06 1) f2# -> f2# 0.00/0.06 2) f1# -> f2# 0.00/0.06 0.00/0.06 We have the following SCCs. 0.00/0.06 { 1 } 0.00/0.06 0.00/0.06 DP problem for innermost termination. 0.00/0.06 P = 0.00/0.06 f2# -> f2# 0.00/0.06 R = 0.00/0.06 init -> f1 0.00/0.06 f2 -> f2 0.00/0.06 f1 -> f2 0.00/0.06 0.00/3.04 EOF