1.29/1.31	MAYBE
1.29/1.31	
1.29/1.31	DP problem for innermost termination.
1.29/1.31	P =
1.29/1.31	  init#(x1, x2) -> f1#(rnd1, rnd2) 
1.29/1.31	  f2#(I0, I1) -> f2#(0, 9) [10 = I1]
1.29/1.31	  f2#(I2, I3) -> f2#(0, I3 - 1) [0 = I2 /\ 10 <= I3 - 1]
1.29/1.31	  f2#(I4, I5) -> f2#(1, I5 + 1) [1 = I4 /\ 10 <= I5 - 1]
1.29/1.31	  f2#(I6, I7) -> f2#(0, I7 - 1) [0 = I6 /\ 1 <= I7 - 1 /\ I7 <= 9]
1.29/1.31	  f2#(I8, I9) -> f2#(1, I9 + 1) [1 = I8 /\ 1 <= I9 - 1 /\ I9 <= 9]
1.29/1.31	  f2#(I10, I11) -> f2#(1, 2) [1 = I11]
1.29/1.31	  f1#(I12, I13) -> f2#(0, I13) [-1 <= I13 - 1 /\ 0 <= I12 - 1]
1.29/1.31	R = 
1.29/1.31	  init(x1, x2) -> f1(rnd1, rnd2) 
1.29/1.31	  f2(I0, I1) -> f2(0, 9) [10 = I1]
1.29/1.31	  f2(I2, I3) -> f2(0, I3 - 1) [0 = I2 /\ 10 <= I3 - 1]
1.29/1.31	  f2(I4, I5) -> f2(1, I5 + 1) [1 = I4 /\ 10 <= I5 - 1]
1.29/1.31	  f2(I6, I7) -> f2(0, I7 - 1) [0 = I6 /\ 1 <= I7 - 1 /\ I7 <= 9]
1.29/1.31	  f2(I8, I9) -> f2(1, I9 + 1) [1 = I8 /\ 1 <= I9 - 1 /\ I9 <= 9]
1.29/1.31	  f2(I10, I11) -> f2(1, 2) [1 = I11]
1.29/1.31	  f1(I12, I13) -> f2(0, I13) [-1 <= I13 - 1 /\ 0 <= I12 - 1]
1.29/1.31	
1.29/1.31	The dependency graph for this problem is:
1.29/1.31	  0 -> 7
1.29/1.31	  1 -> 4
1.29/1.31	  2 -> 1, 2
1.29/1.31	  3 -> 3
1.29/1.31	  4 -> 4, 6
1.29/1.31	  5 -> 1, 5
1.29/1.31	  6 -> 5
1.29/1.31	  7 -> 1, 2, 4, 6
1.29/1.31	Where:
1.29/1.31	  0) init#(x1, x2) -> f1#(rnd1, rnd2) 
1.29/1.31	  1) f2#(I0, I1) -> f2#(0, 9) [10 = I1]
1.29/1.31	  2) f2#(I2, I3) -> f2#(0, I3 - 1) [0 = I2 /\ 10 <= I3 - 1]
1.29/1.31	  3) f2#(I4, I5) -> f2#(1, I5 + 1) [1 = I4 /\ 10 <= I5 - 1]
1.29/1.31	  4) f2#(I6, I7) -> f2#(0, I7 - 1) [0 = I6 /\ 1 <= I7 - 1 /\ I7 <= 9]
1.29/1.31	  5) f2#(I8, I9) -> f2#(1, I9 + 1) [1 = I8 /\ 1 <= I9 - 1 /\ I9 <= 9]
1.29/1.31	  6) f2#(I10, I11) -> f2#(1, 2) [1 = I11]
1.29/1.31	  7) f1#(I12, I13) -> f2#(0, I13) [-1 <= I13 - 1 /\ 0 <= I12 - 1]
1.29/1.31	
1.29/1.31	We have the following SCCs.
1.29/1.31	  { 3 }
1.29/1.31	  { 2 }
1.29/1.31	  { 1, 4, 5, 6 }
1.29/1.31	
1.29/1.31	DP problem for innermost termination.
1.29/1.31	P =
1.29/1.31	  f2#(I0, I1) -> f2#(0, 9) [10 = I1]
1.29/1.31	  f2#(I6, I7) -> f2#(0, I7 - 1) [0 = I6 /\ 1 <= I7 - 1 /\ I7 <= 9]
1.29/1.31	  f2#(I8, I9) -> f2#(1, I9 + 1) [1 = I8 /\ 1 <= I9 - 1 /\ I9 <= 9]
1.29/1.31	  f2#(I10, I11) -> f2#(1, 2) [1 = I11]
1.29/1.31	R = 
1.29/1.31	  init(x1, x2) -> f1(rnd1, rnd2) 
1.29/1.31	  f2(I0, I1) -> f2(0, 9) [10 = I1]
1.29/1.31	  f2(I2, I3) -> f2(0, I3 - 1) [0 = I2 /\ 10 <= I3 - 1]
1.29/1.31	  f2(I4, I5) -> f2(1, I5 + 1) [1 = I4 /\ 10 <= I5 - 1]
1.29/1.31	  f2(I6, I7) -> f2(0, I7 - 1) [0 = I6 /\ 1 <= I7 - 1 /\ I7 <= 9]
1.29/1.31	  f2(I8, I9) -> f2(1, I9 + 1) [1 = I8 /\ 1 <= I9 - 1 /\ I9 <= 9]
1.29/1.32	  f2(I10, I11) -> f2(1, 2) [1 = I11]
1.29/1.32	  f1(I12, I13) -> f2(0, I13) [-1 <= I13 - 1 /\ 0 <= I12 - 1]
1.29/1.32	
1.29/4.29	EOF