0.59/0.67	MAYBE
0.59/0.67	
0.59/0.67	DP problem for innermost termination.
0.59/0.67	P =
0.59/0.67	  init#(x1, x2) -> f1#(rnd1, rnd2) 
0.59/0.67	  f4#(I0, I1) -> f4#(I0 + 1, I2) [I0 <= -1]
0.59/0.67	  f4#(I3, I4) -> f3#(0, I5) [0 = I3]
0.59/0.67	  f3#(I6, I7) -> f3#(I6 - 1, I8) [0 <= I6 - 1]
0.59/0.67	  f3#(I9, I10) -> f3#(0, I11) [0 = I9]
0.59/0.67	  f2#(I12, I13) -> f4#(I14, I15) [-1 <= y1 - 1 /\ 1 <= I13 - 1 /\ -1 <= y2 - 1 /\ y2 - 2 * y3 = 0 /\ 0 <= I12 - 1 /\ y2 - 2 * y3 <= 1 /\ 0 <= y2 - 2 * y3 /\ 0 - y1 = I14]
0.59/0.67	  f1#(I16, I17) -> f2#(I16, I17) [-1 <= I18 - 1 /\ 1 <= I17 - 1 /\ -1 <= I19 - 1 /\ I19 - 2 * I20 = 0 /\ 0 <= I16 - 1]
0.59/0.67	  f2#(I21, I22) -> f3#(I23, I24) [-1 <= I23 - 1 /\ 1 <= I22 - 1 /\ I25 - 2 * I26 = 1 /\ -1 <= I25 - 1 /\ 0 <= I21 - 1 /\ I25 - 2 * I26 <= 1 /\ 0 <= I25 - 2 * I26]
0.59/0.67	  f1#(I27, I28) -> f2#(I27, I28) [-1 <= I29 - 1 /\ 1 <= I28 - 1 /\ I30 - 2 * I31 = 1 /\ -1 <= I30 - 1 /\ 0 <= I27 - 1]
0.59/0.67	R = 
0.59/0.67	  init(x1, x2) -> f1(rnd1, rnd2) 
0.59/0.67	  f4(I0, I1) -> f4(I0 + 1, I2) [I0 <= -1]
0.59/0.67	  f4(I3, I4) -> f3(0, I5) [0 = I3]
0.59/0.67	  f3(I6, I7) -> f3(I6 - 1, I8) [0 <= I6 - 1]
0.59/0.67	  f3(I9, I10) -> f3(0, I11) [0 = I9]
0.59/0.67	  f2(I12, I13) -> f4(I14, I15) [-1 <= y1 - 1 /\ 1 <= I13 - 1 /\ -1 <= y2 - 1 /\ y2 - 2 * y3 = 0 /\ 0 <= I12 - 1 /\ y2 - 2 * y3 <= 1 /\ 0 <= y2 - 2 * y3 /\ 0 - y1 = I14]
0.59/0.67	  f1(I16, I17) -> f2(I16, I17) [-1 <= I18 - 1 /\ 1 <= I17 - 1 /\ -1 <= I19 - 1 /\ I19 - 2 * I20 = 0 /\ 0 <= I16 - 1]
0.59/0.67	  f2(I21, I22) -> f3(I23, I24) [-1 <= I23 - 1 /\ 1 <= I22 - 1 /\ I25 - 2 * I26 = 1 /\ -1 <= I25 - 1 /\ 0 <= I21 - 1 /\ I25 - 2 * I26 <= 1 /\ 0 <= I25 - 2 * I26]
0.59/0.67	  f1(I27, I28) -> f2(I27, I28) [-1 <= I29 - 1 /\ 1 <= I28 - 1 /\ I30 - 2 * I31 = 1 /\ -1 <= I30 - 1 /\ 0 <= I27 - 1]
0.59/0.67	
0.59/0.67	The dependency graph for this problem is:
0.59/0.67	  0 -> 6, 8
0.59/0.67	  1 -> 1, 2
0.59/0.67	  2 -> 4
0.59/0.67	  3 -> 3, 4
0.59/0.67	  4 -> 4
0.59/0.67	  5 -> 1, 2
0.59/0.67	  6 -> 5, 7
0.59/0.67	  7 -> 3, 4
0.59/0.67	  8 -> 5, 7
0.59/0.67	Where:
0.59/0.67	  0) init#(x1, x2) -> f1#(rnd1, rnd2) 
0.59/0.67	  1) f4#(I0, I1) -> f4#(I0 + 1, I2) [I0 <= -1]
0.59/0.67	  2) f4#(I3, I4) -> f3#(0, I5) [0 = I3]
0.59/0.67	  3) f3#(I6, I7) -> f3#(I6 - 1, I8) [0 <= I6 - 1]
0.59/0.67	  4) f3#(I9, I10) -> f3#(0, I11) [0 = I9]
0.59/0.67	  5) f2#(I12, I13) -> f4#(I14, I15) [-1 <= y1 - 1 /\ 1 <= I13 - 1 /\ -1 <= y2 - 1 /\ y2 - 2 * y3 = 0 /\ 0 <= I12 - 1 /\ y2 - 2 * y3 <= 1 /\ 0 <= y2 - 2 * y3 /\ 0 - y1 = I14]
0.59/0.67	  6) f1#(I16, I17) -> f2#(I16, I17) [-1 <= I18 - 1 /\ 1 <= I17 - 1 /\ -1 <= I19 - 1 /\ I19 - 2 * I20 = 0 /\ 0 <= I16 - 1]
0.59/0.67	  7) f2#(I21, I22) -> f3#(I23, I24) [-1 <= I23 - 1 /\ 1 <= I22 - 1 /\ I25 - 2 * I26 = 1 /\ -1 <= I25 - 1 /\ 0 <= I21 - 1 /\ I25 - 2 * I26 <= 1 /\ 0 <= I25 - 2 * I26]
0.59/0.67	  8) f1#(I27, I28) -> f2#(I27, I28) [-1 <= I29 - 1 /\ 1 <= I28 - 1 /\ I30 - 2 * I31 = 1 /\ -1 <= I30 - 1 /\ 0 <= I27 - 1]
0.59/0.67	
0.59/0.67	We have the following SCCs.
0.59/0.67	  { 3 }
0.59/0.67	  { 1 }
0.59/0.67	  { 4 }
0.59/0.67	
0.59/0.67	DP problem for innermost termination.
0.59/0.67	P =
0.59/0.67	  f3#(I9, I10) -> f3#(0, I11) [0 = I9]
0.59/0.67	R = 
0.59/0.67	  init(x1, x2) -> f1(rnd1, rnd2) 
0.59/0.67	  f4(I0, I1) -> f4(I0 + 1, I2) [I0 <= -1]
0.59/0.67	  f4(I3, I4) -> f3(0, I5) [0 = I3]
0.59/0.67	  f3(I6, I7) -> f3(I6 - 1, I8) [0 <= I6 - 1]
0.59/0.67	  f3(I9, I10) -> f3(0, I11) [0 = I9]
0.59/0.67	  f2(I12, I13) -> f4(I14, I15) [-1 <= y1 - 1 /\ 1 <= I13 - 1 /\ -1 <= y2 - 1 /\ y2 - 2 * y3 = 0 /\ 0 <= I12 - 1 /\ y2 - 2 * y3 <= 1 /\ 0 <= y2 - 2 * y3 /\ 0 - y1 = I14]
0.59/0.67	  f1(I16, I17) -> f2(I16, I17) [-1 <= I18 - 1 /\ 1 <= I17 - 1 /\ -1 <= I19 - 1 /\ I19 - 2 * I20 = 0 /\ 0 <= I16 - 1]
0.59/0.67	  f2(I21, I22) -> f3(I23, I24) [-1 <= I23 - 1 /\ 1 <= I22 - 1 /\ I25 - 2 * I26 = 1 /\ -1 <= I25 - 1 /\ 0 <= I21 - 1 /\ I25 - 2 * I26 <= 1 /\ 0 <= I25 - 2 * I26]
0.59/0.67	  f1(I27, I28) -> f2(I27, I28) [-1 <= I29 - 1 /\ 1 <= I28 - 1 /\ I30 - 2 * I31 = 1 /\ -1 <= I30 - 1 /\ 0 <= I27 - 1]
0.59/0.67	
0.59/3.65	EOF