0.00/0.46	MAYBE
0.00/0.46	
0.00/0.46	DP problem for innermost termination.
0.00/0.46	P =
0.00/0.46	  init#(x1, x2) -> f3#(rnd1, rnd2) 
0.00/0.46	  f4#(I0, I1) -> f4#(I0 - 1, I1 + 1) [0 <= I1 - 1 /\ 0 <= I0 - 1]
0.00/0.46	  f3#(I2, I3) -> f4#(I4, 1) [0 <= I2 - 1 /\ -1 <= I4 - 1 /\ -1 <= I3 - 1]
0.00/0.46	  f2#(I5, I6) -> f2#(I7, I8) [I7 <= I5 /\ 0 <= y1 - 1 /\ 0 <= I5 - 1 /\ 0 <= I7 - 1]
0.00/0.46	  f3#(I9, I10) -> f2#(I11, I12) [-1 <= I11 - 1 /\ 0 <= I9 - 1]
0.00/0.46	  f1#(I13, I14) -> f2#(I15, I16) [-1 <= I15 - 1 /\ -1 <= I13 - 1 /\ I15 <= I13]
0.00/0.46	R = 
0.00/0.46	  init(x1, x2) -> f3(rnd1, rnd2) 
0.00/0.46	  f4(I0, I1) -> f4(I0 - 1, I1 + 1) [0 <= I1 - 1 /\ 0 <= I0 - 1]
0.00/0.46	  f3(I2, I3) -> f4(I4, 1) [0 <= I2 - 1 /\ -1 <= I4 - 1 /\ -1 <= I3 - 1]
0.00/0.46	  f2(I5, I6) -> f2(I7, I8) [I7 <= I5 /\ 0 <= y1 - 1 /\ 0 <= I5 - 1 /\ 0 <= I7 - 1]
0.00/0.46	  f3(I9, I10) -> f2(I11, I12) [-1 <= I11 - 1 /\ 0 <= I9 - 1]
0.00/0.46	  f1(I13, I14) -> f2(I15, I16) [-1 <= I15 - 1 /\ -1 <= I13 - 1 /\ I15 <= I13]
0.00/0.46	
0.00/0.46	The dependency graph for this problem is:
0.00/0.46	  0 -> 2, 4
0.00/0.46	  1 -> 1
0.00/0.46	  2 -> 1
0.00/0.46	  3 -> 3
0.00/0.46	  4 -> 3
0.00/0.46	  5 -> 3
0.00/0.46	Where:
0.00/0.46	  0) init#(x1, x2) -> f3#(rnd1, rnd2) 
0.00/0.46	  1) f4#(I0, I1) -> f4#(I0 - 1, I1 + 1) [0 <= I1 - 1 /\ 0 <= I0 - 1]
0.00/0.46	  2) f3#(I2, I3) -> f4#(I4, 1) [0 <= I2 - 1 /\ -1 <= I4 - 1 /\ -1 <= I3 - 1]
0.00/0.46	  3) f2#(I5, I6) -> f2#(I7, I8) [I7 <= I5 /\ 0 <= y1 - 1 /\ 0 <= I5 - 1 /\ 0 <= I7 - 1]
0.00/0.46	  4) f3#(I9, I10) -> f2#(I11, I12) [-1 <= I11 - 1 /\ 0 <= I9 - 1]
0.00/0.46	  5) f1#(I13, I14) -> f2#(I15, I16) [-1 <= I15 - 1 /\ -1 <= I13 - 1 /\ I15 <= I13]
0.00/0.46	
0.00/0.46	We have the following SCCs.
0.00/0.46	  { 1 }
0.00/0.46	  { 3 }
0.00/0.46	
0.00/0.46	DP problem for innermost termination.
0.00/0.46	P =
0.00/0.46	  f2#(I5, I6) -> f2#(I7, I8) [I7 <= I5 /\ 0 <= y1 - 1 /\ 0 <= I5 - 1 /\ 0 <= I7 - 1]
0.00/0.46	R = 
0.00/0.46	  init(x1, x2) -> f3(rnd1, rnd2) 
0.00/0.46	  f4(I0, I1) -> f4(I0 - 1, I1 + 1) [0 <= I1 - 1 /\ 0 <= I0 - 1]
0.00/0.46	  f3(I2, I3) -> f4(I4, 1) [0 <= I2 - 1 /\ -1 <= I4 - 1 /\ -1 <= I3 - 1]
0.00/0.46	  f2(I5, I6) -> f2(I7, I8) [I7 <= I5 /\ 0 <= y1 - 1 /\ 0 <= I5 - 1 /\ 0 <= I7 - 1]
0.00/0.46	  f3(I9, I10) -> f2(I11, I12) [-1 <= I11 - 1 /\ 0 <= I9 - 1]
0.00/0.46	  f1(I13, I14) -> f2(I15, I16) [-1 <= I15 - 1 /\ -1 <= I13 - 1 /\ I15 <= I13]
0.00/0.46	
0.00/3.44	EOF