0.80/1.17	MAYBE
0.80/1.17	
0.80/1.17	DP problem for innermost termination.
0.80/1.17	P =
0.80/1.17	  init#(x1, x2, x3, x4, x5) -> f1#(rnd1, rnd2, rnd3, rnd4, rnd5) 
0.80/1.17	  f2#(I0, I1, I2, I3, I4) -> f2#(I0, I1 + 1, I0, I1 + 1, I0) [I2 = I4 /\ 0 = I3 /\ 0 <= I2 - 1]
0.80/1.17	  f2#(I5, I6, I7, I8, I9) -> f2#(I5, I6, I7 - 1, I8 - 1, I7 - 1) [I7 = I9 /\ 0 <= I8 - 1 /\ 0 <= I7 - 1]
0.80/1.17	  f1#(I10, I11, I12, I13, I14) -> f2#(I15, I16, I17, I18, I19) [I15 = I19 /\ I16 = I18 /\ I15 = I17 /\ 0 <= I10 - 1 /\ -1 <= I15 - 1 /\ -1 <= I11 - 1 /\ -1 <= I16 - 1]
0.80/1.17	R = 
0.80/1.17	  init(x1, x2, x3, x4, x5) -> f1(rnd1, rnd2, rnd3, rnd4, rnd5) 
0.80/1.17	  f2(I0, I1, I2, I3, I4) -> f2(I0, I1 + 1, I0, I1 + 1, I0) [I2 = I4 /\ 0 = I3 /\ 0 <= I2 - 1]
0.80/1.17	  f2(I5, I6, I7, I8, I9) -> f2(I5, I6, I7 - 1, I8 - 1, I7 - 1) [I7 = I9 /\ 0 <= I8 - 1 /\ 0 <= I7 - 1]
0.80/1.17	  f1(I10, I11, I12, I13, I14) -> f2(I15, I16, I17, I18, I19) [I15 = I19 /\ I16 = I18 /\ I15 = I17 /\ 0 <= I10 - 1 /\ -1 <= I15 - 1 /\ -1 <= I11 - 1 /\ -1 <= I16 - 1]
0.80/1.17	
0.80/1.17	The dependency graph for this problem is:
0.80/1.17	  0 -> 3
0.80/1.17	  1 -> 1, 2
0.80/1.17	  2 -> 1, 2
0.80/1.17	  3 -> 1, 2
0.80/1.17	Where:
0.80/1.17	  0) init#(x1, x2, x3, x4, x5) -> f1#(rnd1, rnd2, rnd3, rnd4, rnd5) 
0.80/1.17	  1) f2#(I0, I1, I2, I3, I4) -> f2#(I0, I1 + 1, I0, I1 + 1, I0) [I2 = I4 /\ 0 = I3 /\ 0 <= I2 - 1]
0.80/1.17	  2) f2#(I5, I6, I7, I8, I9) -> f2#(I5, I6, I7 - 1, I8 - 1, I7 - 1) [I7 = I9 /\ 0 <= I8 - 1 /\ 0 <= I7 - 1]
0.80/1.17	  3) f1#(I10, I11, I12, I13, I14) -> f2#(I15, I16, I17, I18, I19) [I15 = I19 /\ I16 = I18 /\ I15 = I17 /\ 0 <= I10 - 1 /\ -1 <= I15 - 1 /\ -1 <= I11 - 1 /\ -1 <= I16 - 1]
0.80/1.17	
0.80/1.17	We have the following SCCs.
0.80/1.17	  { 1, 2 }
0.80/1.17	
0.80/1.17	DP problem for innermost termination.
0.80/1.17	P =
0.80/1.17	  f2#(I0, I1, I2, I3, I4) -> f2#(I0, I1 + 1, I0, I1 + 1, I0) [I2 = I4 /\ 0 = I3 /\ 0 <= I2 - 1]
0.80/1.17	  f2#(I5, I6, I7, I8, I9) -> f2#(I5, I6, I7 - 1, I8 - 1, I7 - 1) [I7 = I9 /\ 0 <= I8 - 1 /\ 0 <= I7 - 1]
0.80/1.17	R = 
0.80/1.17	  init(x1, x2, x3, x4, x5) -> f1(rnd1, rnd2, rnd3, rnd4, rnd5) 
0.80/1.17	  f2(I0, I1, I2, I3, I4) -> f2(I0, I1 + 1, I0, I1 + 1, I0) [I2 = I4 /\ 0 = I3 /\ 0 <= I2 - 1]
0.80/1.17	  f2(I5, I6, I7, I8, I9) -> f2(I5, I6, I7 - 1, I8 - 1, I7 - 1) [I7 = I9 /\ 0 <= I8 - 1 /\ 0 <= I7 - 1]
0.80/1.17	  f1(I10, I11, I12, I13, I14) -> f2(I15, I16, I17, I18, I19) [I15 = I19 /\ I16 = I18 /\ I15 = I17 /\ 0 <= I10 - 1 /\ -1 <= I15 - 1 /\ -1 <= I11 - 1 /\ -1 <= I16 - 1]
0.80/1.17	
0.80/4.15	EOF