2.28/2.35	MAYBE
2.28/2.35	
2.28/2.35	DP problem for innermost termination.
2.28/2.35	P =
2.28/2.35	  init#(x1, x2) -> f1#(rnd1, rnd2) 
2.28/2.35	  f3#(I0, I1) -> f2#(I0 + 3, I2) [I0 - 2 * y1 = 1 /\ 0 <= I0 - 1 /\ I0 - 2 * y1 <= 1 /\ 0 <= I0 - 2 * y1]
2.28/2.35	  f2#(I3, I4) -> f3#(I3, I5) [0 <= I3 - 1 /\ I3 - 2 * I6 = 1]
2.28/2.35	  f3#(I7, I8) -> f2#(I7 - 1, I9) [0 <= I7 - 1 /\ I7 - 2 * I10 = 0 /\ I7 - 2 * I10 <= 1 /\ 0 <= I7 - 2 * I10]
2.28/2.35	  f2#(I11, I12) -> f3#(I11, I13) [I11 - 2 * I14 = 0 /\ 0 <= I11 - 1]
2.28/2.35	  f1#(I15, I16) -> f2#(I16, I17) [-1 <= I16 - 1 /\ 0 <= I15 - 1]
2.28/2.35	R = 
2.28/2.35	  init(x1, x2) -> f1(rnd1, rnd2) 
2.28/2.35	  f3(I0, I1) -> f2(I0 + 3, I2) [I0 - 2 * y1 = 1 /\ 0 <= I0 - 1 /\ I0 - 2 * y1 <= 1 /\ 0 <= I0 - 2 * y1]
2.28/2.35	  f2(I3, I4) -> f3(I3, I5) [0 <= I3 - 1 /\ I3 - 2 * I6 = 1]
2.28/2.35	  f3(I7, I8) -> f2(I7 - 1, I9) [0 <= I7 - 1 /\ I7 - 2 * I10 = 0 /\ I7 - 2 * I10 <= 1 /\ 0 <= I7 - 2 * I10]
2.28/2.35	  f2(I11, I12) -> f3(I11, I13) [I11 - 2 * I14 = 0 /\ 0 <= I11 - 1]
2.28/2.35	  f1(I15, I16) -> f2(I16, I17) [-1 <= I16 - 1 /\ 0 <= I15 - 1]
2.28/2.35	
2.28/2.35	The dependency graph for this problem is:
2.28/2.35	  0 -> 5
2.28/2.35	  1 -> 4
2.28/2.35	  2 -> 1
2.28/2.35	  3 -> 2
2.28/2.35	  4 -> 3
2.28/2.35	  5 -> 2, 4
2.28/2.35	Where:
2.28/2.35	  0) init#(x1, x2) -> f1#(rnd1, rnd2) 
2.28/2.35	  1) f3#(I0, I1) -> f2#(I0 + 3, I2) [I0 - 2 * y1 = 1 /\ 0 <= I0 - 1 /\ I0 - 2 * y1 <= 1 /\ 0 <= I0 - 2 * y1]
2.28/2.35	  2) f2#(I3, I4) -> f3#(I3, I5) [0 <= I3 - 1 /\ I3 - 2 * I6 = 1]
2.28/2.35	  3) f3#(I7, I8) -> f2#(I7 - 1, I9) [0 <= I7 - 1 /\ I7 - 2 * I10 = 0 /\ I7 - 2 * I10 <= 1 /\ 0 <= I7 - 2 * I10]
2.28/2.35	  4) f2#(I11, I12) -> f3#(I11, I13) [I11 - 2 * I14 = 0 /\ 0 <= I11 - 1]
2.28/2.35	  5) f1#(I15, I16) -> f2#(I16, I17) [-1 <= I16 - 1 /\ 0 <= I15 - 1]
2.28/2.35	
2.28/2.35	We have the following SCCs.
2.28/2.35	  { 1, 2, 3, 4 }
2.28/2.35	
2.28/2.35	DP problem for innermost termination.
2.28/2.35	P =
2.28/2.35	  f3#(I0, I1) -> f2#(I0 + 3, I2) [I0 - 2 * y1 = 1 /\ 0 <= I0 - 1 /\ I0 - 2 * y1 <= 1 /\ 0 <= I0 - 2 * y1]
2.28/2.35	  f2#(I3, I4) -> f3#(I3, I5) [0 <= I3 - 1 /\ I3 - 2 * I6 = 1]
2.28/2.35	  f3#(I7, I8) -> f2#(I7 - 1, I9) [0 <= I7 - 1 /\ I7 - 2 * I10 = 0 /\ I7 - 2 * I10 <= 1 /\ 0 <= I7 - 2 * I10]
2.28/2.35	  f2#(I11, I12) -> f3#(I11, I13) [I11 - 2 * I14 = 0 /\ 0 <= I11 - 1]
2.28/2.35	R = 
2.28/2.35	  init(x1, x2) -> f1(rnd1, rnd2) 
2.28/2.35	  f3(I0, I1) -> f2(I0 + 3, I2) [I0 - 2 * y1 = 1 /\ 0 <= I0 - 1 /\ I0 - 2 * y1 <= 1 /\ 0 <= I0 - 2 * y1]
2.28/2.35	  f2(I3, I4) -> f3(I3, I5) [0 <= I3 - 1 /\ I3 - 2 * I6 = 1]
2.28/2.35	  f3(I7, I8) -> f2(I7 - 1, I9) [0 <= I7 - 1 /\ I7 - 2 * I10 = 0 /\ I7 - 2 * I10 <= 1 /\ 0 <= I7 - 2 * I10]
2.28/2.35	  f2(I11, I12) -> f3(I11, I13) [I11 - 2 * I14 = 0 /\ 0 <= I11 - 1]
2.28/2.35	  f1(I15, I16) -> f2(I16, I17) [-1 <= I16 - 1 /\ 0 <= I15 - 1]
2.28/2.35	
2.28/5.33	EOF