0.56/0.64	MAYBE
0.56/0.64	
0.56/0.64	DP problem for innermost termination.
0.56/0.64	P =
0.56/0.64	  init#(x1, x2) -> f1#(rnd1, rnd2) 
0.56/0.64	  f2#(I0, I1) -> f2#(2 * I0 + 1, I1 + 1) [0 <= 2 * I0 /\ I0 - I1 = 0 /\ I1 <= I0 /\ -1 <= I1 - 1 /\ -1 <= I0 - 1]
0.56/0.64	  f2#(I2, I3) -> f2#(I2 - 1, I3) [0 <= I2 - I3 - 1 /\ I3 <= I2 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1]
0.56/0.64	  f1#(I4, I5) -> f2#(I6, I7) [0 <= I4 - 1 /\ -1 <= I6 - 1 /\ 1 <= I5 - 1 /\ -1 <= I7 - 1]
0.56/0.64	R = 
0.56/0.64	  init(x1, x2) -> f1(rnd1, rnd2) 
0.56/0.64	  f2(I0, I1) -> f2(2 * I0 + 1, I1 + 1) [0 <= 2 * I0 /\ I0 - I1 = 0 /\ I1 <= I0 /\ -1 <= I1 - 1 /\ -1 <= I0 - 1]
0.56/0.64	  f2(I2, I3) -> f2(I2 - 1, I3) [0 <= I2 - I3 - 1 /\ I3 <= I2 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1]
0.56/0.64	  f1(I4, I5) -> f2(I6, I7) [0 <= I4 - 1 /\ -1 <= I6 - 1 /\ 1 <= I5 - 1 /\ -1 <= I7 - 1]
0.56/0.64	
0.56/0.64	The dependency graph for this problem is:
0.56/0.64	  0 -> 3
0.56/0.64	  1 -> 1, 2
0.56/0.64	  2 -> 1, 2
0.56/0.64	  3 -> 1, 2
0.56/0.64	Where:
0.56/0.64	  0) init#(x1, x2) -> f1#(rnd1, rnd2) 
0.56/0.64	  1) f2#(I0, I1) -> f2#(2 * I0 + 1, I1 + 1) [0 <= 2 * I0 /\ I0 - I1 = 0 /\ I1 <= I0 /\ -1 <= I1 - 1 /\ -1 <= I0 - 1]
0.56/0.64	  2) f2#(I2, I3) -> f2#(I2 - 1, I3) [0 <= I2 - I3 - 1 /\ I3 <= I2 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1]
0.56/0.64	  3) f1#(I4, I5) -> f2#(I6, I7) [0 <= I4 - 1 /\ -1 <= I6 - 1 /\ 1 <= I5 - 1 /\ -1 <= I7 - 1]
0.56/0.64	
0.56/0.64	We have the following SCCs.
0.56/0.64	  { 1, 2 }
0.56/0.64	
0.56/0.64	DP problem for innermost termination.
0.56/0.64	P =
0.56/0.64	  f2#(I0, I1) -> f2#(2 * I0 + 1, I1 + 1) [0 <= 2 * I0 /\ I0 - I1 = 0 /\ I1 <= I0 /\ -1 <= I1 - 1 /\ -1 <= I0 - 1]
0.56/0.64	  f2#(I2, I3) -> f2#(I2 - 1, I3) [0 <= I2 - I3 - 1 /\ I3 <= I2 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1]
0.56/0.64	R = 
0.56/0.64	  init(x1, x2) -> f1(rnd1, rnd2) 
0.56/0.64	  f2(I0, I1) -> f2(2 * I0 + 1, I1 + 1) [0 <= 2 * I0 /\ I0 - I1 = 0 /\ I1 <= I0 /\ -1 <= I1 - 1 /\ -1 <= I0 - 1]
0.56/0.64	  f2(I2, I3) -> f2(I2 - 1, I3) [0 <= I2 - I3 - 1 /\ I3 <= I2 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1]
0.56/0.64	  f1(I4, I5) -> f2(I6, I7) [0 <= I4 - 1 /\ -1 <= I6 - 1 /\ 1 <= I5 - 1 /\ -1 <= I7 - 1]
0.56/0.64	
0.56/0.64	EOF