0.86/1.19	MAYBE
0.86/1.19	
0.86/1.19	DP problem for innermost termination.
0.86/1.19	P =
0.86/1.19	  init#(x1, x2) -> f1#(rnd1, rnd2) 
0.86/1.19	  f4#(I0, I1) -> f3#(I0 + 1, I2) [0 <= I1 - 1 /\ I0 + 1 - 3 * y1 <= 2 /\ 0 <= I0 + 1 - 3 * y1 /\ I0 + 1 - 3 * y1 = I2]
0.86/1.19	  f3#(I3, I4) -> f4#(I3, I4) [0 <= I4 - 1]
0.86/1.19	  f2#(I5, I6) -> f3#(I7, I8) [-1 <= I6 - 1 /\ -1 <= I7 - 1 /\ 0 <= I5 - 1 /\ I7 - 3 * I9 <= 2 /\ 0 <= I7 - 3 * I9 /\ I7 - 3 * I9 = I8]
0.86/1.19	  f1#(I10, I11) -> f2#(I10, I11) [-1 <= I11 - 1 /\ -1 <= I12 - 1 /\ 0 <= I10 - 1]
0.86/1.19	R = 
0.86/1.19	  init(x1, x2) -> f1(rnd1, rnd2) 
0.86/1.19	  f4(I0, I1) -> f3(I0 + 1, I2) [0 <= I1 - 1 /\ I0 + 1 - 3 * y1 <= 2 /\ 0 <= I0 + 1 - 3 * y1 /\ I0 + 1 - 3 * y1 = I2]
0.86/1.19	  f3(I3, I4) -> f4(I3, I4) [0 <= I4 - 1]
0.86/1.19	  f2(I5, I6) -> f3(I7, I8) [-1 <= I6 - 1 /\ -1 <= I7 - 1 /\ 0 <= I5 - 1 /\ I7 - 3 * I9 <= 2 /\ 0 <= I7 - 3 * I9 /\ I7 - 3 * I9 = I8]
0.86/1.19	  f1(I10, I11) -> f2(I10, I11) [-1 <= I11 - 1 /\ -1 <= I12 - 1 /\ 0 <= I10 - 1]
0.86/1.19	
0.86/1.19	The dependency graph for this problem is:
0.86/1.19	  0 -> 4
0.86/1.19	  1 -> 2
0.86/1.19	  2 -> 1
0.86/1.19	  3 -> 2
0.86/1.19	  4 -> 3
0.86/1.19	Where:
0.86/1.19	  0) init#(x1, x2) -> f1#(rnd1, rnd2) 
0.86/1.19	  1) f4#(I0, I1) -> f3#(I0 + 1, I2) [0 <= I1 - 1 /\ I0 + 1 - 3 * y1 <= 2 /\ 0 <= I0 + 1 - 3 * y1 /\ I0 + 1 - 3 * y1 = I2]
0.86/1.19	  2) f3#(I3, I4) -> f4#(I3, I4) [0 <= I4 - 1]
0.86/1.19	  3) f2#(I5, I6) -> f3#(I7, I8) [-1 <= I6 - 1 /\ -1 <= I7 - 1 /\ 0 <= I5 - 1 /\ I7 - 3 * I9 <= 2 /\ 0 <= I7 - 3 * I9 /\ I7 - 3 * I9 = I8]
0.86/1.19	  4) f1#(I10, I11) -> f2#(I10, I11) [-1 <= I11 - 1 /\ -1 <= I12 - 1 /\ 0 <= I10 - 1]
0.86/1.19	
0.86/1.19	We have the following SCCs.
0.86/1.19	  { 1, 2 }
0.86/1.19	
0.86/1.19	DP problem for innermost termination.
0.86/1.19	P =
0.86/1.19	  f4#(I0, I1) -> f3#(I0 + 1, I2) [0 <= I1 - 1 /\ I0 + 1 - 3 * y1 <= 2 /\ 0 <= I0 + 1 - 3 * y1 /\ I0 + 1 - 3 * y1 = I2]
0.86/1.19	  f3#(I3, I4) -> f4#(I3, I4) [0 <= I4 - 1]
0.86/1.19	R = 
0.86/1.19	  init(x1, x2) -> f1(rnd1, rnd2) 
0.86/1.19	  f4(I0, I1) -> f3(I0 + 1, I2) [0 <= I1 - 1 /\ I0 + 1 - 3 * y1 <= 2 /\ 0 <= I0 + 1 - 3 * y1 /\ I0 + 1 - 3 * y1 = I2]
0.86/1.19	  f3(I3, I4) -> f4(I3, I4) [0 <= I4 - 1]
0.86/1.19	  f2(I5, I6) -> f3(I7, I8) [-1 <= I6 - 1 /\ -1 <= I7 - 1 /\ 0 <= I5 - 1 /\ I7 - 3 * I9 <= 2 /\ 0 <= I7 - 3 * I9 /\ I7 - 3 * I9 = I8]
0.86/1.19	  f1(I10, I11) -> f2(I10, I11) [-1 <= I11 - 1 /\ -1 <= I12 - 1 /\ 0 <= I10 - 1]
0.86/1.19	
0.86/4.17	EOF