0.00/0.30	MAYBE
0.00/0.30	
0.00/0.30	DP problem for innermost termination.
0.00/0.30	P =
0.00/0.30	  init#(x1, x2) -> f1#(rnd1, rnd2) 
0.00/0.30	  f2#(I0, I1) -> f2#(I0 + 1, I1 + 1) [I0 <= I1 - 1]
0.00/0.30	  f1#(I2, I3) -> f2#(0, 100) 
0.00/0.30	R = 
0.00/0.30	  init(x1, x2) -> f1(rnd1, rnd2) 
0.00/0.30	  f2(I0, I1) -> f2(I0 + 1, I1 + 1) [I0 <= I1 - 1]
0.00/0.30	  f1(I2, I3) -> f2(0, 100) 
0.00/0.30	
0.00/0.30	The dependency graph for this problem is:
0.00/0.30	  0 -> 2
0.00/0.30	  1 -> 1
0.00/0.30	  2 -> 1
0.00/0.30	Where:
0.00/0.30	  0) init#(x1, x2) -> f1#(rnd1, rnd2) 
0.00/0.30	  1) f2#(I0, I1) -> f2#(I0 + 1, I1 + 1) [I0 <= I1 - 1]
0.00/0.30	  2) f1#(I2, I3) -> f2#(0, 100) 
0.00/0.30	
0.00/0.30	We have the following SCCs.
0.00/0.30	  { 1 }
0.00/0.30	
0.00/0.30	DP problem for innermost termination.
0.00/0.30	P =
0.00/0.30	  f2#(I0, I1) -> f2#(I0 + 1, I1 + 1) [I0 <= I1 - 1]
0.00/0.30	R = 
0.00/0.30	  init(x1, x2) -> f1(rnd1, rnd2) 
0.00/0.30	  f2(I0, I1) -> f2(I0 + 1, I1 + 1) [I0 <= I1 - 1]
0.00/0.30	  f1(I2, I3) -> f2(0, 100) 
0.00/0.30	
0.00/3.28	EOF