0.62/0.95 MAYBE 0.62/0.95 0.62/0.95 DP problem for innermost termination. 0.62/0.95 P = 0.62/0.95 init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) 0.62/0.95 f2#(I0, I1, I2, I3) -> f2#(I0 - 1, I0, I2, I3 + 1) [I3 <= I2 - 1 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1 /\ 0 <= I1 - 1] 0.62/0.95 f2#(I4, I5, I6, I7) -> f2#(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1] 0.62/0.95 f1#(I8, I9, I10, I11) -> f2#(I12, I13, I9, 1) [-1 <= y1 - 1 /\ 0 <= I9 - 1 /\ 0 <= I8 - 1 /\ 3 * y1 - 1 = I12 /\ 3 * y1 = I13] 0.62/0.95 f1#(I14, I15, I16, I17) -> f2#(-1, 0, 0, 0) [0 = I15 /\ 0 <= I14 - 1] 0.62/0.95 R = 0.62/0.95 init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) 0.62/0.95 f2(I0, I1, I2, I3) -> f2(I0 - 1, I0, I2, I3 + 1) [I3 <= I2 - 1 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1 /\ 0 <= I1 - 1] 0.62/0.95 f2(I4, I5, I6, I7) -> f2(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1] 0.62/0.95 f1(I8, I9, I10, I11) -> f2(I12, I13, I9, 1) [-1 <= y1 - 1 /\ 0 <= I9 - 1 /\ 0 <= I8 - 1 /\ 3 * y1 - 1 = I12 /\ 3 * y1 = I13] 0.62/0.95 f1(I14, I15, I16, I17) -> f2(-1, 0, 0, 0) [0 = I15 /\ 0 <= I14 - 1] 0.62/0.95 0.62/0.95 The dependency graph for this problem is: 0.62/0.95 0 -> 3, 4 0.62/0.95 1 -> 1, 2 0.62/0.95 2 -> 2 0.62/0.95 3 -> 1, 2 0.62/0.95 4 -> 0.62/0.95 Where: 0.62/0.95 0) init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) 0.62/0.95 1) f2#(I0, I1, I2, I3) -> f2#(I0 - 1, I0, I2, I3 + 1) [I3 <= I2 - 1 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1 /\ 0 <= I1 - 1] 0.62/0.95 2) f2#(I4, I5, I6, I7) -> f2#(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1] 0.62/0.95 3) f1#(I8, I9, I10, I11) -> f2#(I12, I13, I9, 1) [-1 <= y1 - 1 /\ 0 <= I9 - 1 /\ 0 <= I8 - 1 /\ 3 * y1 - 1 = I12 /\ 3 * y1 = I13] 0.62/0.95 4) f1#(I14, I15, I16, I17) -> f2#(-1, 0, 0, 0) [0 = I15 /\ 0 <= I14 - 1] 0.62/0.95 0.62/0.95 We have the following SCCs. 0.62/0.95 { 1 } 0.62/0.95 { 2 } 0.62/0.95 0.62/0.95 DP problem for innermost termination. 0.62/0.95 P = 0.62/0.95 f2#(I4, I5, I6, I7) -> f2#(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1] 0.62/0.95 R = 0.62/0.95 init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) 0.62/0.95 f2(I0, I1, I2, I3) -> f2(I0 - 1, I0, I2, I3 + 1) [I3 <= I2 - 1 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1 /\ 0 <= I1 - 1] 0.62/0.95 f2(I4, I5, I6, I7) -> f2(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1] 0.62/0.95 f1(I8, I9, I10, I11) -> f2(I12, I13, I9, 1) [-1 <= y1 - 1 /\ 0 <= I9 - 1 /\ 0 <= I8 - 1 /\ 3 * y1 - 1 = I12 /\ 3 * y1 = I13] 0.62/0.95 f1(I14, I15, I16, I17) -> f2(-1, 0, 0, 0) [0 = I15 /\ 0 <= I14 - 1] 0.62/0.95 0.62/3.93 EOF