0.65/0.68	MAYBE
0.65/0.68	
0.65/0.68	DP problem for innermost termination.
0.65/0.68	P =
0.65/0.68	  init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) 
0.65/0.68	  f2#(I0, I1, I2, I3) -> f2#(I0 - 1, I0, I2, I3 + 1) [I3 <= I2 - 1 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1 /\ 0 <= I1 - 1]
0.65/0.68	  f2#(I4, I5, I6, I7) -> f2#(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1]
0.65/0.68	  f1#(I8, I9, I10, I11) -> f2#(I12, I13, I9, 2) [-1 <= y2 - 1 /\ 1 <= I9 - 1 /\ -1 <= y1 - 1 /\ 0 <= I8 - 1 /\ y1 * y2 - 1 = I12 /\ y1 * y2 = I13]
0.65/0.68	  f1#(I14, I15, I16, I17) -> f2#(-1, 0, 1, 1) [0 <= I14 - 1 /\ -1 <= I18 - 1 /\ 1 = I15]
0.65/0.68	  f1#(I19, I20, I21, I22) -> f2#(-1, 0, 0, 0) [0 = I20 /\ 0 <= I19 - 1]
0.65/0.68	R = 
0.65/0.68	  init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) 
0.65/0.68	  f2(I0, I1, I2, I3) -> f2(I0 - 1, I0, I2, I3 + 1) [I3 <= I2 - 1 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1 /\ 0 <= I1 - 1]
0.65/0.68	  f2(I4, I5, I6, I7) -> f2(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1]
0.65/0.68	  f1(I8, I9, I10, I11) -> f2(I12, I13, I9, 2) [-1 <= y2 - 1 /\ 1 <= I9 - 1 /\ -1 <= y1 - 1 /\ 0 <= I8 - 1 /\ y1 * y2 - 1 = I12 /\ y1 * y2 = I13]
0.65/0.68	  f1(I14, I15, I16, I17) -> f2(-1, 0, 1, 1) [0 <= I14 - 1 /\ -1 <= I18 - 1 /\ 1 = I15]
0.65/0.68	  f1(I19, I20, I21, I22) -> f2(-1, 0, 0, 0) [0 = I20 /\ 0 <= I19 - 1]
0.65/0.68	
0.65/0.68	The dependency graph for this problem is:
0.65/0.68	  0 -> 3, 4, 5
0.65/0.68	  1 -> 1, 2
0.65/0.68	  2 -> 2
0.65/0.68	  3 -> 1, 2
0.65/0.68	  4 -> 
0.65/0.68	  5 -> 
0.65/0.68	Where:
0.65/0.68	  0) init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) 
0.65/0.68	  1) f2#(I0, I1, I2, I3) -> f2#(I0 - 1, I0, I2, I3 + 1) [I3 <= I2 - 1 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1 /\ 0 <= I1 - 1]
0.65/0.68	  2) f2#(I4, I5, I6, I7) -> f2#(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1]
0.65/0.68	  3) f1#(I8, I9, I10, I11) -> f2#(I12, I13, I9, 2) [-1 <= y2 - 1 /\ 1 <= I9 - 1 /\ -1 <= y1 - 1 /\ 0 <= I8 - 1 /\ y1 * y2 - 1 = I12 /\ y1 * y2 = I13]
0.65/0.68	  4) f1#(I14, I15, I16, I17) -> f2#(-1, 0, 1, 1) [0 <= I14 - 1 /\ -1 <= I18 - 1 /\ 1 = I15]
0.65/0.68	  5) f1#(I19, I20, I21, I22) -> f2#(-1, 0, 0, 0) [0 = I20 /\ 0 <= I19 - 1]
0.65/0.68	
0.65/0.68	We have the following SCCs.
0.65/0.68	  { 1 }
0.65/0.68	  { 2 }
0.65/0.68	
0.65/0.68	DP problem for innermost termination.
0.65/0.68	P =
0.65/0.68	  f2#(I4, I5, I6, I7) -> f2#(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1]
0.65/0.68	R = 
0.65/0.68	  init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) 
0.65/0.68	  f2(I0, I1, I2, I3) -> f2(I0 - 1, I0, I2, I3 + 1) [I3 <= I2 - 1 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1 /\ 0 <= I1 - 1]
0.65/0.68	  f2(I4, I5, I6, I7) -> f2(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1]
0.65/0.68	  f1(I8, I9, I10, I11) -> f2(I12, I13, I9, 2) [-1 <= y2 - 1 /\ 1 <= I9 - 1 /\ -1 <= y1 - 1 /\ 0 <= I8 - 1 /\ y1 * y2 - 1 = I12 /\ y1 * y2 = I13]
0.65/0.68	  f1(I14, I15, I16, I17) -> f2(-1, 0, 1, 1) [0 <= I14 - 1 /\ -1 <= I18 - 1 /\ 1 = I15]
0.65/0.68	  f1(I19, I20, I21, I22) -> f2(-1, 0, 0, 0) [0 = I20 /\ 0 <= I19 - 1]
0.65/0.68	
0.65/3.66	EOF