0.00/0.44	MAYBE
0.00/0.44	
0.00/0.44	DP problem for innermost termination.
0.00/0.44	P =
0.00/0.44	  init#(x1, x2) -> f1#(rnd1, rnd2) 
0.00/0.44	  f4#(I0, I1) -> f2#(I0 + 1, I2) [14 <= I1 - 1]
0.00/0.44	  f4#(I3, I4) -> f4#(I3, I4 + 1) [I4 <= 14]
0.00/0.44	  f2#(I5, I6) -> f4#(I5, 0) [I5 <= 99 /\ I5 <= 9]
0.00/0.44	  f2#(I7, I8) -> f3#(I7, I9) [49 <= I7 - 1 /\ I7 <= 99]
0.00/0.44	  f3#(I10, I11) -> f3#(I10, I12) 
0.00/0.44	  f2#(I13, I14) -> f2#(I13 + 1, I15) [I13 <= 99 /\ 9 <= I13 - 1 /\ I13 <= 49]
0.00/0.44	  f1#(I16, I17) -> f2#(0, I18) 
0.00/0.44	R = 
0.00/0.44	  init(x1, x2) -> f1(rnd1, rnd2) 
0.00/0.44	  f4(I0, I1) -> f2(I0 + 1, I2) [14 <= I1 - 1]
0.00/0.44	  f4(I3, I4) -> f4(I3, I4 + 1) [I4 <= 14]
0.00/0.44	  f2(I5, I6) -> f4(I5, 0) [I5 <= 99 /\ I5 <= 9]
0.00/0.44	  f2(I7, I8) -> f3(I7, I9) [49 <= I7 - 1 /\ I7 <= 99]
0.00/0.44	  f3(I10, I11) -> f3(I10, I12) 
0.00/0.44	  f2(I13, I14) -> f2(I13 + 1, I15) [I13 <= 99 /\ 9 <= I13 - 1 /\ I13 <= 49]
0.00/0.44	  f1(I16, I17) -> f2(0, I18) 
0.00/0.44	
0.00/0.44	The dependency graph for this problem is:
0.00/0.44	  0 -> 7
0.00/0.44	  1 -> 3, 4, 6
0.00/0.44	  2 -> 1, 2
0.00/0.44	  3 -> 2
0.00/0.44	  4 -> 5
0.00/0.44	  5 -> 5
0.00/0.44	  6 -> 4, 6
0.00/0.44	  7 -> 3
0.00/0.44	Where:
0.00/0.44	  0) init#(x1, x2) -> f1#(rnd1, rnd2) 
0.00/0.44	  1) f4#(I0, I1) -> f2#(I0 + 1, I2) [14 <= I1 - 1]
0.00/0.44	  2) f4#(I3, I4) -> f4#(I3, I4 + 1) [I4 <= 14]
0.00/0.44	  3) f2#(I5, I6) -> f4#(I5, 0) [I5 <= 99 /\ I5 <= 9]
0.00/0.44	  4) f2#(I7, I8) -> f3#(I7, I9) [49 <= I7 - 1 /\ I7 <= 99]
0.00/0.44	  5) f3#(I10, I11) -> f3#(I10, I12) 
0.00/0.44	  6) f2#(I13, I14) -> f2#(I13 + 1, I15) [I13 <= 99 /\ 9 <= I13 - 1 /\ I13 <= 49]
0.00/0.44	  7) f1#(I16, I17) -> f2#(0, I18) 
0.00/0.44	
0.00/0.44	We have the following SCCs.
0.00/0.44	  { 1, 2, 3 }
0.00/0.44	  { 6 }
0.00/0.44	  { 5 }
0.00/0.44	
0.00/0.44	DP problem for innermost termination.
0.00/0.44	P =
0.00/0.44	  f3#(I10, I11) -> f3#(I10, I12) 
0.00/0.44	R = 
0.00/0.44	  init(x1, x2) -> f1(rnd1, rnd2) 
0.00/0.44	  f4(I0, I1) -> f2(I0 + 1, I2) [14 <= I1 - 1]
0.00/0.44	  f4(I3, I4) -> f4(I3, I4 + 1) [I4 <= 14]
0.00/0.44	  f2(I5, I6) -> f4(I5, 0) [I5 <= 99 /\ I5 <= 9]
0.00/0.44	  f2(I7, I8) -> f3(I7, I9) [49 <= I7 - 1 /\ I7 <= 99]
0.00/0.44	  f3(I10, I11) -> f3(I10, I12) 
0.00/0.44	  f2(I13, I14) -> f2(I13 + 1, I15) [I13 <= 99 /\ 9 <= I13 - 1 /\ I13 <= 49]
0.00/0.44	  f1(I16, I17) -> f2(0, I18) 
0.00/0.44	
0.00/3.42	EOF