0.00/0.58	MAYBE
0.00/0.58	
0.00/0.58	DP problem for innermost termination.
0.00/0.58	P =
0.00/0.58	  init#(x1, x2, x3) -> f1#(rnd1, rnd2, rnd3) 
0.00/0.58	  f2#(I0, I1, I2) -> f2#(I0 + I1, I1 - 1, I0 + I1) [I0 = I2 /\ I1 - 1 <= I1 - 1 /\ 0 <= I0 - 1]
0.00/0.58	  f1#(I3, I4, I5) -> f2#(I6, I7, I8) [I6 = I8 /\ 0 <= I3 - 1 /\ -1 <= I6 - 1 /\ 1 <= I4 - 1 /\ -1 <= I7 - 1]
0.00/0.58	  f1#(I9, I10, I11) -> f2#(I12, 0, I13) [I12 = I13 /\ 1 = I10 /\ -1 <= I12 - 1 /\ 0 <= I9 - 1]
0.00/0.58	  f1#(I14, I15, I16) -> f2#(0, 0, 0) [0 = I15 /\ 0 <= I14 - 1]
0.00/0.58	R = 
0.00/0.58	  init(x1, x2, x3) -> f1(rnd1, rnd2, rnd3) 
0.00/0.58	  f2(I0, I1, I2) -> f2(I0 + I1, I1 - 1, I0 + I1) [I0 = I2 /\ I1 - 1 <= I1 - 1 /\ 0 <= I0 - 1]
0.00/0.58	  f1(I3, I4, I5) -> f2(I6, I7, I8) [I6 = I8 /\ 0 <= I3 - 1 /\ -1 <= I6 - 1 /\ 1 <= I4 - 1 /\ -1 <= I7 - 1]
0.00/0.58	  f1(I9, I10, I11) -> f2(I12, 0, I13) [I12 = I13 /\ 1 = I10 /\ -1 <= I12 - 1 /\ 0 <= I9 - 1]
0.00/0.58	  f1(I14, I15, I16) -> f2(0, 0, 0) [0 = I15 /\ 0 <= I14 - 1]
0.00/0.58	
0.00/0.58	The dependency graph for this problem is:
0.00/0.58	  0 -> 2, 3, 4
0.00/0.58	  1 -> 1
0.00/0.58	  2 -> 1
0.00/0.58	  3 -> 1
0.00/0.58	  4 -> 
0.00/0.58	Where:
0.00/0.58	  0) init#(x1, x2, x3) -> f1#(rnd1, rnd2, rnd3) 
0.00/0.58	  1) f2#(I0, I1, I2) -> f2#(I0 + I1, I1 - 1, I0 + I1) [I0 = I2 /\ I1 - 1 <= I1 - 1 /\ 0 <= I0 - 1]
0.00/0.58	  2) f1#(I3, I4, I5) -> f2#(I6, I7, I8) [I6 = I8 /\ 0 <= I3 - 1 /\ -1 <= I6 - 1 /\ 1 <= I4 - 1 /\ -1 <= I7 - 1]
0.00/0.58	  3) f1#(I9, I10, I11) -> f2#(I12, 0, I13) [I12 = I13 /\ 1 = I10 /\ -1 <= I12 - 1 /\ 0 <= I9 - 1]
0.00/0.58	  4) f1#(I14, I15, I16) -> f2#(0, 0, 0) [0 = I15 /\ 0 <= I14 - 1]
0.00/0.58	
0.00/0.58	We have the following SCCs.
0.00/0.58	  { 1 }
0.00/0.58	
0.00/0.58	DP problem for innermost termination.
0.00/0.58	P =
0.00/0.58	  f2#(I0, I1, I2) -> f2#(I0 + I1, I1 - 1, I0 + I1) [I0 = I2 /\ I1 - 1 <= I1 - 1 /\ 0 <= I0 - 1]
0.00/0.58	R = 
0.00/0.58	  init(x1, x2, x3) -> f1(rnd1, rnd2, rnd3) 
0.00/0.58	  f2(I0, I1, I2) -> f2(I0 + I1, I1 - 1, I0 + I1) [I0 = I2 /\ I1 - 1 <= I1 - 1 /\ 0 <= I0 - 1]
0.00/0.58	  f1(I3, I4, I5) -> f2(I6, I7, I8) [I6 = I8 /\ 0 <= I3 - 1 /\ -1 <= I6 - 1 /\ 1 <= I4 - 1 /\ -1 <= I7 - 1]
0.00/0.58	  f1(I9, I10, I11) -> f2(I12, 0, I13) [I12 = I13 /\ 1 = I10 /\ -1 <= I12 - 1 /\ 0 <= I9 - 1]
0.00/0.58	  f1(I14, I15, I16) -> f2(0, 0, 0) [0 = I15 /\ 0 <= I14 - 1]
0.00/0.58	
0.00/3.56	EOF