0.67/0.71 MAYBE 0.67/0.71 0.67/0.71 DP problem for innermost termination. 0.67/0.71 P = 0.67/0.71 init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) 0.67/0.71 f2#(I0, I1, I2, I3) -> f2#(I4, I2, I2 + I1, I3) [0 <= I4 - 1 /\ 0 <= I0 - 1 /\ I4 <= I0 /\ 0 <= I2 - 1 /\ -1 <= I1 - 1 /\ I3 <= I2 - 1] 0.67/0.71 f2#(I5, I6, I7, I8) -> f2#(I9, I7, I7 + I6, I8) [0 <= I9 - 1 /\ 0 <= I5 - 1 /\ I9 <= I5 /\ 0 <= I7 - 1 /\ -1 <= I6 - 1 /\ I7 <= I8 - 1] 0.67/0.71 f1#(I10, I11, I12, I13) -> f2#(I14, 0, 1, I11) [0 <= I14 - 1 /\ 0 <= I10 - 1 /\ -1 <= I11 - 1 /\ I14 <= I10] 0.67/0.71 R = 0.67/0.71 init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) 0.67/0.71 f2(I0, I1, I2, I3) -> f2(I4, I2, I2 + I1, I3) [0 <= I4 - 1 /\ 0 <= I0 - 1 /\ I4 <= I0 /\ 0 <= I2 - 1 /\ -1 <= I1 - 1 /\ I3 <= I2 - 1] 0.67/0.71 f2(I5, I6, I7, I8) -> f2(I9, I7, I7 + I6, I8) [0 <= I9 - 1 /\ 0 <= I5 - 1 /\ I9 <= I5 /\ 0 <= I7 - 1 /\ -1 <= I6 - 1 /\ I7 <= I8 - 1] 0.67/0.71 f1(I10, I11, I12, I13) -> f2(I14, 0, 1, I11) [0 <= I14 - 1 /\ 0 <= I10 - 1 /\ -1 <= I11 - 1 /\ I14 <= I10] 0.67/0.71 0.67/0.71 The dependency graph for this problem is: 0.67/0.71 0 -> 3 0.67/0.71 1 -> 1 0.67/0.71 2 -> 1, 2 0.67/0.71 3 -> 1, 2 0.67/0.71 Where: 0.67/0.71 0) init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) 0.67/0.71 1) f2#(I0, I1, I2, I3) -> f2#(I4, I2, I2 + I1, I3) [0 <= I4 - 1 /\ 0 <= I0 - 1 /\ I4 <= I0 /\ 0 <= I2 - 1 /\ -1 <= I1 - 1 /\ I3 <= I2 - 1] 0.67/0.71 2) f2#(I5, I6, I7, I8) -> f2#(I9, I7, I7 + I6, I8) [0 <= I9 - 1 /\ 0 <= I5 - 1 /\ I9 <= I5 /\ 0 <= I7 - 1 /\ -1 <= I6 - 1 /\ I7 <= I8 - 1] 0.67/0.71 3) f1#(I10, I11, I12, I13) -> f2#(I14, 0, 1, I11) [0 <= I14 - 1 /\ 0 <= I10 - 1 /\ -1 <= I11 - 1 /\ I14 <= I10] 0.67/0.71 0.67/0.71 We have the following SCCs. 0.67/0.71 { 2 } 0.67/0.71 { 1 } 0.67/0.71 0.67/0.71 DP problem for innermost termination. 0.67/0.71 P = 0.67/0.71 f2#(I0, I1, I2, I3) -> f2#(I4, I2, I2 + I1, I3) [0 <= I4 - 1 /\ 0 <= I0 - 1 /\ I4 <= I0 /\ 0 <= I2 - 1 /\ -1 <= I1 - 1 /\ I3 <= I2 - 1] 0.67/0.71 R = 0.67/0.71 init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) 0.67/0.71 f2(I0, I1, I2, I3) -> f2(I4, I2, I2 + I1, I3) [0 <= I4 - 1 /\ 0 <= I0 - 1 /\ I4 <= I0 /\ 0 <= I2 - 1 /\ -1 <= I1 - 1 /\ I3 <= I2 - 1] 0.67/0.71 f2(I5, I6, I7, I8) -> f2(I9, I7, I7 + I6, I8) [0 <= I9 - 1 /\ 0 <= I5 - 1 /\ I9 <= I5 /\ 0 <= I7 - 1 /\ -1 <= I6 - 1 /\ I7 <= I8 - 1] 0.67/0.71 f1(I10, I11, I12, I13) -> f2(I14, 0, 1, I11) [0 <= I14 - 1 /\ 0 <= I10 - 1 /\ -1 <= I11 - 1 /\ I14 <= I10] 0.67/0.71 0.67/3.69 EOF