0.00/0.01	YES
0.00/0.01	
0.00/0.01	DP problem for innermost termination.
0.00/0.01	P =
0.00/0.01	  f3#(x1, x2, x3) -> f1#(x1, x2, x3) 
0.00/0.01	R = 
0.00/0.01	  f3(x1, x2, x3) -> f1(x1, x2, x3) 
0.00/0.01	  f1(I0, I1, I2) -> f2(rnd1, rnd2, rnd3) [y1 = -1 /\ rnd3 = y1 /\ rnd2 = rnd3 /\ rnd1 = rnd2]
0.00/0.01	
0.00/0.01	The dependency graph for this problem is:
0.00/0.01	  0 -> 
0.00/0.01	Where:
0.00/0.01	  0) f3#(x1, x2, x3) -> f1#(x1, x2, x3) 
0.00/0.01	
0.00/0.01	We have the following SCCs.
0.00/0.01	  
0.00/0.01	EOF