25.81/25.42	MAYBE
25.81/25.42	
25.81/25.42	DP problem for innermost termination.
25.81/25.42	P =
25.81/25.42	  f7#(x1, x2, x3, x4, x5, x6, x7) -> f6#(x1, x2, x3, x4, x5, x6, x7) 
25.81/25.42	  f6#(I0, I1, I2, I3, I4, I5, I6) -> f3#(-1, 0, I2, I3, I4, 14, 8) 
25.81/25.42	  f2#(I7, I8, I9, I10, I11, I12, I13) -> f3#(I7, I8, I9, I10, I11, -1 + I9, I13) 
25.81/25.42	  f2#(I14, I15, I16, I17, I18, I19, I20) -> f3#(I14, 1 + I16, I16, I17, I18, I19, I20) 
25.81/25.42	  f3#(I21, I22, I23, I24, I25, I26, I27) -> f4#(I21, I22, I23, I24, I25, I26, I27) 
25.81/25.42	  f4#(I28, I29, I30, I31, I32, I33, I34) -> f1#(I28, I29, rnd3, I31, I32, I33, I34) [rnd3 = rnd3 /\ I29 <= I33]
25.81/25.42	  f1#(I42, I43, I44, I45, I46, I47, I48) -> f2#(I42, I43, I44, I45, I46, I47, I48) 
25.81/25.42	  f1#(I49, I50, I51, I52, I53, I54, I55) -> f3#(rnd1, I50, I51, I52, I53, -1 + I50, I55) [rnd1 = rnd1]
25.81/25.42	  f1#(I56, I57, I58, I59, I60, I61, I62) -> f2#(I56, I57, I58, I59, I60, I61, I62) 
25.81/25.42	R = 
25.81/25.42	  f7(x1, x2, x3, x4, x5, x6, x7) -> f6(x1, x2, x3, x4, x5, x6, x7) 
25.81/25.42	  f6(I0, I1, I2, I3, I4, I5, I6) -> f3(-1, 0, I2, I3, I4, 14, 8) 
25.81/25.42	  f2(I7, I8, I9, I10, I11, I12, I13) -> f3(I7, I8, I9, I10, I11, -1 + I9, I13) 
25.81/25.42	  f2(I14, I15, I16, I17, I18, I19, I20) -> f3(I14, 1 + I16, I16, I17, I18, I19, I20) 
25.81/25.42	  f3(I21, I22, I23, I24, I25, I26, I27) -> f4(I21, I22, I23, I24, I25, I26, I27) 
25.81/25.42	  f4(I28, I29, I30, I31, I32, I33, I34) -> f1(I28, I29, rnd3, I31, I32, I33, I34) [rnd3 = rnd3 /\ I29 <= I33]
25.81/25.42	  f4(I35, I36, I37, I38, I39, I40, I41) -> f5(I35, I36, I37, I35, I35, I40, I41) [1 + I40 <= I36]
25.81/25.42	  f1(I42, I43, I44, I45, I46, I47, I48) -> f2(I42, I43, I44, I45, I46, I47, I48) 
25.81/25.42	  f1(I49, I50, I51, I52, I53, I54, I55) -> f3(rnd1, I50, I51, I52, I53, -1 + I50, I55) [rnd1 = rnd1]
25.81/25.42	  f1(I56, I57, I58, I59, I60, I61, I62) -> f2(I56, I57, I58, I59, I60, I61, I62) 
25.81/25.42	
25.81/25.42	The dependency graph for this problem is:
25.81/25.42	  0 -> 1
25.81/25.42	  1 -> 4
25.81/25.42	  2 -> 4
25.81/25.42	  3 -> 4
25.81/25.42	  4 -> 5
25.81/25.42	  5 -> 6, 7, 8
25.81/25.42	  6 -> 2, 3
25.81/25.42	  7 -> 4
25.81/25.42	  8 -> 2, 3
25.81/25.42	Where:
25.81/25.42	  0) f7#(x1, x2, x3, x4, x5, x6, x7) -> f6#(x1, x2, x3, x4, x5, x6, x7) 
25.81/25.42	  1) f6#(I0, I1, I2, I3, I4, I5, I6) -> f3#(-1, 0, I2, I3, I4, 14, 8) 
25.81/25.42	  2) f2#(I7, I8, I9, I10, I11, I12, I13) -> f3#(I7, I8, I9, I10, I11, -1 + I9, I13) 
25.81/25.42	  3) f2#(I14, I15, I16, I17, I18, I19, I20) -> f3#(I14, 1 + I16, I16, I17, I18, I19, I20) 
25.81/25.42	  4) f3#(I21, I22, I23, I24, I25, I26, I27) -> f4#(I21, I22, I23, I24, I25, I26, I27) 
25.81/25.42	  5) f4#(I28, I29, I30, I31, I32, I33, I34) -> f1#(I28, I29, rnd3, I31, I32, I33, I34) [rnd3 = rnd3 /\ I29 <= I33]
25.81/25.42	  6) f1#(I42, I43, I44, I45, I46, I47, I48) -> f2#(I42, I43, I44, I45, I46, I47, I48) 
25.81/25.42	  7) f1#(I49, I50, I51, I52, I53, I54, I55) -> f3#(rnd1, I50, I51, I52, I53, -1 + I50, I55) [rnd1 = rnd1]
25.81/25.42	  8) f1#(I56, I57, I58, I59, I60, I61, I62) -> f2#(I56, I57, I58, I59, I60, I61, I62) 
25.81/25.42	
25.81/25.42	We have the following SCCs.
25.81/25.42	  { 2, 3, 4, 5, 6, 7, 8 }
25.81/25.42	
25.81/25.42	DP problem for innermost termination.
25.81/25.42	P =
25.81/25.42	  f2#(I7, I8, I9, I10, I11, I12, I13) -> f3#(I7, I8, I9, I10, I11, -1 + I9, I13) 
25.81/25.42	  f2#(I14, I15, I16, I17, I18, I19, I20) -> f3#(I14, 1 + I16, I16, I17, I18, I19, I20) 
25.81/25.42	  f3#(I21, I22, I23, I24, I25, I26, I27) -> f4#(I21, I22, I23, I24, I25, I26, I27) 
25.81/25.42	  f4#(I28, I29, I30, I31, I32, I33, I34) -> f1#(I28, I29, rnd3, I31, I32, I33, I34) [rnd3 = rnd3 /\ I29 <= I33]
25.81/25.42	  f1#(I42, I43, I44, I45, I46, I47, I48) -> f2#(I42, I43, I44, I45, I46, I47, I48) 
25.81/25.42	  f1#(I49, I50, I51, I52, I53, I54, I55) -> f3#(rnd1, I50, I51, I52, I53, -1 + I50, I55) [rnd1 = rnd1]
25.81/25.42	  f1#(I56, I57, I58, I59, I60, I61, I62) -> f2#(I56, I57, I58, I59, I60, I61, I62) 
25.81/25.42	R = 
25.81/25.42	  f7(x1, x2, x3, x4, x5, x6, x7) -> f6(x1, x2, x3, x4, x5, x6, x7) 
25.81/25.42	  f6(I0, I1, I2, I3, I4, I5, I6) -> f3(-1, 0, I2, I3, I4, 14, 8) 
25.81/25.42	  f2(I7, I8, I9, I10, I11, I12, I13) -> f3(I7, I8, I9, I10, I11, -1 + I9, I13) 
25.81/25.42	  f2(I14, I15, I16, I17, I18, I19, I20) -> f3(I14, 1 + I16, I16, I17, I18, I19, I20) 
25.81/25.42	  f3(I21, I22, I23, I24, I25, I26, I27) -> f4(I21, I22, I23, I24, I25, I26, I27) 
25.81/25.42	  f4(I28, I29, I30, I31, I32, I33, I34) -> f1(I28, I29, rnd3, I31, I32, I33, I34) [rnd3 = rnd3 /\ I29 <= I33]
25.81/25.42	  f4(I35, I36, I37, I38, I39, I40, I41) -> f5(I35, I36, I37, I35, I35, I40, I41) [1 + I40 <= I36]
25.81/25.42	  f1(I42, I43, I44, I45, I46, I47, I48) -> f2(I42, I43, I44, I45, I46, I47, I48) 
25.81/25.42	  f1(I49, I50, I51, I52, I53, I54, I55) -> f3(rnd1, I50, I51, I52, I53, -1 + I50, I55) [rnd1 = rnd1]
25.81/25.42	  f1(I56, I57, I58, I59, I60, I61, I62) -> f2(I56, I57, I58, I59, I60, I61, I62) 
25.81/25.42	
25.81/28.40	EOF