0.00/0.01 YES 0.00/0.01 0.00/0.01 DP problem for innermost termination. 0.00/0.01 P = 0.00/0.01 f3#(x1) -> f1#(x1) 0.00/0.01 R = 0.00/0.01 f3(x1) -> f1(x1) 0.00/0.01 f1(I0) -> f2(1) 0.00/0.01 0.00/0.01 The dependency graph for this problem is: 0.00/0.01 0 -> 0.00/0.01 Where: 0.00/0.01 0) f3#(x1) -> f1#(x1) 0.00/0.01 0.00/0.01 We have the following SCCs. 0.00/0.01 0.00/0.01 EOF