12.34/12.18 MAYBE 12.34/12.18 12.34/12.18 DP problem for innermost termination. 12.34/12.18 P = 12.34/12.18 f8#(x1, x2, x3, x4, x5) -> f7#(x1, x2, x3, x4, x5) 12.34/12.18 f7#(I0, I1, I2, I3, I4) -> f1#(I0, I1, I2, I3, I4) 12.34/12.18 f6#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, I8, I9) 12.34/12.18 f5#(I10, I11, I12, I13, I14) -> f6#(I10, I11, I12, 1 + I13, I14) 12.34/12.18 f4#(I15, I16, I17, I18, I19) -> f5#(I15, I16, I17, I18, I19) [I16 = I16] 12.34/12.18 f1#(I20, I21, I22, I23, I24) -> f4#(I20, I21, rnd3, I23, I24) [rnd3 = rnd3 /\ 0 <= -1 - I23 + I24] 12.34/12.18 f3#(I25, I26, I27, I28, I29) -> f1#(I25, I26, I27, I28, I29) 12.34/12.18 f1#(I30, I31, I32, I33, I34) -> f3#(I30, I31, I35, I33, 1 + I34) [0 <= I35 /\ I35 <= 0 /\ I35 = I35 /\ 0 <= -1 - I33 + I34] 12.34/12.18 R = 12.34/12.18 f8(x1, x2, x3, x4, x5) -> f7(x1, x2, x3, x4, x5) 12.34/12.18 f7(I0, I1, I2, I3, I4) -> f1(I0, I1, I2, I3, I4) 12.34/12.18 f6(I5, I6, I7, I8, I9) -> f1(I5, I6, I7, I8, I9) 12.34/12.18 f5(I10, I11, I12, I13, I14) -> f6(I10, I11, I12, 1 + I13, I14) 12.34/12.18 f4(I15, I16, I17, I18, I19) -> f5(I15, I16, I17, I18, I19) [I16 = I16] 12.34/12.18 f1(I20, I21, I22, I23, I24) -> f4(I20, I21, rnd3, I23, I24) [rnd3 = rnd3 /\ 0 <= -1 - I23 + I24] 12.34/12.18 f3(I25, I26, I27, I28, I29) -> f1(I25, I26, I27, I28, I29) 12.34/12.18 f1(I30, I31, I32, I33, I34) -> f3(I30, I31, I35, I33, 1 + I34) [0 <= I35 /\ I35 <= 0 /\ I35 = I35 /\ 0 <= -1 - I33 + I34] 12.34/12.18 f1(I36, I37, I38, I39, I40) -> f2(rnd1, I37, I38, I39, I40) [rnd1 = rnd1 /\ -1 * I39 + I40 <= 0] 12.34/12.18 12.34/12.18 The dependency graph for this problem is: 12.34/12.18 0 -> 1 12.34/12.18 1 -> 5, 7 12.34/12.18 2 -> 5, 7 12.34/12.18 3 -> 2 12.34/12.18 4 -> 3 12.34/12.18 5 -> 4 12.34/12.18 6 -> 5, 7 12.34/12.18 7 -> 6 12.34/12.18 Where: 12.34/12.18 0) f8#(x1, x2, x3, x4, x5) -> f7#(x1, x2, x3, x4, x5) 12.34/12.18 1) f7#(I0, I1, I2, I3, I4) -> f1#(I0, I1, I2, I3, I4) 12.34/12.18 2) f6#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, I8, I9) 12.34/12.18 3) f5#(I10, I11, I12, I13, I14) -> f6#(I10, I11, I12, 1 + I13, I14) 12.34/12.18 4) f4#(I15, I16, I17, I18, I19) -> f5#(I15, I16, I17, I18, I19) [I16 = I16] 12.34/12.18 5) f1#(I20, I21, I22, I23, I24) -> f4#(I20, I21, rnd3, I23, I24) [rnd3 = rnd3 /\ 0 <= -1 - I23 + I24] 12.34/12.18 6) f3#(I25, I26, I27, I28, I29) -> f1#(I25, I26, I27, I28, I29) 12.34/12.18 7) f1#(I30, I31, I32, I33, I34) -> f3#(I30, I31, I35, I33, 1 + I34) [0 <= I35 /\ I35 <= 0 /\ I35 = I35 /\ 0 <= -1 - I33 + I34] 12.34/12.18 12.34/12.18 We have the following SCCs. 12.34/12.18 { 2, 3, 4, 5, 6, 7 } 12.34/12.18 12.34/12.18 DP problem for innermost termination. 12.34/12.18 P = 12.34/12.18 f6#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, I8, I9) 12.34/12.18 f5#(I10, I11, I12, I13, I14) -> f6#(I10, I11, I12, 1 + I13, I14) 12.34/12.18 f4#(I15, I16, I17, I18, I19) -> f5#(I15, I16, I17, I18, I19) [I16 = I16] 12.34/12.18 f1#(I20, I21, I22, I23, I24) -> f4#(I20, I21, rnd3, I23, I24) [rnd3 = rnd3 /\ 0 <= -1 - I23 + I24] 12.34/12.18 f3#(I25, I26, I27, I28, I29) -> f1#(I25, I26, I27, I28, I29) 12.34/12.18 f1#(I30, I31, I32, I33, I34) -> f3#(I30, I31, I35, I33, 1 + I34) [0 <= I35 /\ I35 <= 0 /\ I35 = I35 /\ 0 <= -1 - I33 + I34] 12.34/12.18 R = 12.34/12.18 f8(x1, x2, x3, x4, x5) -> f7(x1, x2, x3, x4, x5) 12.34/12.18 f7(I0, I1, I2, I3, I4) -> f1(I0, I1, I2, I3, I4) 12.34/12.18 f6(I5, I6, I7, I8, I9) -> f1(I5, I6, I7, I8, I9) 12.34/12.18 f5(I10, I11, I12, I13, I14) -> f6(I10, I11, I12, 1 + I13, I14) 12.34/12.18 f4(I15, I16, I17, I18, I19) -> f5(I15, I16, I17, I18, I19) [I16 = I16] 12.34/12.18 f1(I20, I21, I22, I23, I24) -> f4(I20, I21, rnd3, I23, I24) [rnd3 = rnd3 /\ 0 <= -1 - I23 + I24] 12.34/12.18 f3(I25, I26, I27, I28, I29) -> f1(I25, I26, I27, I28, I29) 12.34/12.18 f1(I30, I31, I32, I33, I34) -> f3(I30, I31, I35, I33, 1 + I34) [0 <= I35 /\ I35 <= 0 /\ I35 = I35 /\ 0 <= -1 - I33 + I34] 12.34/12.18 f1(I36, I37, I38, I39, I40) -> f2(rnd1, I37, I38, I39, I40) [rnd1 = rnd1 /\ -1 * I39 + I40 <= 0] 12.34/12.18 12.34/15.16 EOF