5.08/5.08 MAYBE 5.08/5.08 5.08/5.08 DP problem for innermost termination. 5.08/5.08 P = 5.08/5.08 f4#(x1, x2, x3, x4, x5) -> f3#(x1, x2, x3, x4, x5) 5.08/5.08 f3#(I0, I1, I2, I3, I4) -> f2#(I0, I1, I2, I3, I0 + I4) [1 + I0 <= I0 + I4] 5.08/5.08 f3#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, I8, I6 + I9) [1 + I5 <= I6 + I9] 5.08/5.08 f2#(I10, I11, I12, I13, I14) -> f1#(I10, I11, I12, I13, I13 + I14) [1 + I10 <= I13 + I14] 5.08/5.08 f1#(I15, I16, I17, I18, I19) -> f2#(I15, I16, I17, I18, I17 + I19) [1 + I15 <= I17 + I19] 5.08/5.08 R = 5.08/5.08 f4(x1, x2, x3, x4, x5) -> f3(x1, x2, x3, x4, x5) 5.08/5.08 f3(I0, I1, I2, I3, I4) -> f2(I0, I1, I2, I3, I0 + I4) [1 + I0 <= I0 + I4] 5.08/5.08 f3(I5, I6, I7, I8, I9) -> f1(I5, I6, I7, I8, I6 + I9) [1 + I5 <= I6 + I9] 5.08/5.08 f2(I10, I11, I12, I13, I14) -> f1(I10, I11, I12, I13, I13 + I14) [1 + I10 <= I13 + I14] 5.08/5.08 f1(I15, I16, I17, I18, I19) -> f2(I15, I16, I17, I18, I17 + I19) [1 + I15 <= I17 + I19] 5.08/5.08 5.08/5.08 The dependency graph for this problem is: 5.08/5.08 0 -> 1, 2 5.08/5.08 1 -> 3 5.08/5.08 2 -> 4 5.08/5.08 3 -> 4 5.08/5.08 4 -> 3 5.08/5.08 Where: 5.08/5.08 0) f4#(x1, x2, x3, x4, x5) -> f3#(x1, x2, x3, x4, x5) 5.08/5.08 1) f3#(I0, I1, I2, I3, I4) -> f2#(I0, I1, I2, I3, I0 + I4) [1 + I0 <= I0 + I4] 5.08/5.08 2) f3#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, I8, I6 + I9) [1 + I5 <= I6 + I9] 5.08/5.08 3) f2#(I10, I11, I12, I13, I14) -> f1#(I10, I11, I12, I13, I13 + I14) [1 + I10 <= I13 + I14] 5.08/5.08 4) f1#(I15, I16, I17, I18, I19) -> f2#(I15, I16, I17, I18, I17 + I19) [1 + I15 <= I17 + I19] 5.08/5.08 5.08/5.08 We have the following SCCs. 5.08/5.08 { 3, 4 } 5.08/5.08 5.08/5.08 DP problem for innermost termination. 5.08/5.08 P = 5.08/5.08 f2#(I10, I11, I12, I13, I14) -> f1#(I10, I11, I12, I13, I13 + I14) [1 + I10 <= I13 + I14] 5.08/5.08 f1#(I15, I16, I17, I18, I19) -> f2#(I15, I16, I17, I18, I17 + I19) [1 + I15 <= I17 + I19] 5.08/5.08 R = 5.08/5.08 f4(x1, x2, x3, x4, x5) -> f3(x1, x2, x3, x4, x5) 5.08/5.08 f3(I0, I1, I2, I3, I4) -> f2(I0, I1, I2, I3, I0 + I4) [1 + I0 <= I0 + I4] 5.08/5.08 f3(I5, I6, I7, I8, I9) -> f1(I5, I6, I7, I8, I6 + I9) [1 + I5 <= I6 + I9] 5.08/5.08 f2(I10, I11, I12, I13, I14) -> f1(I10, I11, I12, I13, I13 + I14) [1 + I10 <= I13 + I14] 5.08/5.08 f1(I15, I16, I17, I18, I19) -> f2(I15, I16, I17, I18, I17 + I19) [1 + I15 <= I17 + I19] 5.08/5.08 5.08/8.05 EOF