27.01/26.63	MAYBE
27.01/26.63	
27.01/26.63	DP problem for innermost termination.
27.01/26.63	P =
27.01/26.63	  f5#(x1, x2) -> f4#(x1, x2) 
27.01/26.63	  f4#(I0, I1) -> f2#(I0, I1) 
27.01/26.63	  f3#(I2, I3) -> f1#(I2, I3) [1 <= I3]
27.01/26.63	  f3#(I4, I5) -> f1#(I4, I5) [1 + I5 <= 0]
27.01/26.63	  f2#(I6, I7) -> f3#(I6, I7) [1 <= I6]
27.01/26.63	  f2#(I8, I9) -> f3#(I8, I9) [1 + I8 <= 0]
27.01/26.63	  f1#(I10, I11) -> f2#(I10, -1 + I11) [2 - I11 <= I10 /\ I11 <= I10]
27.01/26.63	  f1#(I12, I13) -> f2#(-1 + I12, I13) [1 + I13 <= I12 /\ I13 <= 1 - I12]
27.01/26.63	  f1#(I14, I15) -> f2#(I14, 1 + I15) [1 + I14 <= -1 * I15 /\ I14 <= I15]
27.01/26.63	  f1#(I16, I17) -> f2#(1 + I16, I17) [1 + I16 <= I17 /\ -1 * I16 <= I17]
27.01/26.63	R = 
27.01/26.63	  f5(x1, x2) -> f4(x1, x2) 
27.01/26.63	  f4(I0, I1) -> f2(I0, I1) 
27.01/26.63	  f3(I2, I3) -> f1(I2, I3) [1 <= I3]
27.01/26.63	  f3(I4, I5) -> f1(I4, I5) [1 + I5 <= 0]
27.01/26.63	  f2(I6, I7) -> f3(I6, I7) [1 <= I6]
27.01/26.63	  f2(I8, I9) -> f3(I8, I9) [1 + I8 <= 0]
27.01/26.63	  f1(I10, I11) -> f2(I10, -1 + I11) [2 - I11 <= I10 /\ I11 <= I10]
27.01/26.63	  f1(I12, I13) -> f2(-1 + I12, I13) [1 + I13 <= I12 /\ I13 <= 1 - I12]
27.01/26.63	  f1(I14, I15) -> f2(I14, 1 + I15) [1 + I14 <= -1 * I15 /\ I14 <= I15]
27.01/26.63	  f1(I16, I17) -> f2(1 + I16, I17) [1 + I16 <= I17 /\ -1 * I16 <= I17]
27.01/26.63	
27.01/26.63	The dependency graph for this problem is:
27.01/26.63	  0 -> 1
27.01/26.63	  1 -> 4, 5
27.01/26.63	  2 -> 6, 8, 9
27.01/26.63	  3 -> 6, 7, 8
27.01/26.63	  4 -> 2, 3
27.01/26.63	  5 -> 2, 3
27.01/26.63	  6 -> 4
27.01/26.63	  7 -> 4, 5
27.01/26.63	  8 -> 5
27.01/26.63	  9 -> 4, 5
27.01/26.63	Where:
27.01/26.63	  0) f5#(x1, x2) -> f4#(x1, x2) 
27.01/26.63	  1) f4#(I0, I1) -> f2#(I0, I1) 
27.01/26.63	  2) f3#(I2, I3) -> f1#(I2, I3) [1 <= I3]
27.01/26.63	  3) f3#(I4, I5) -> f1#(I4, I5) [1 + I5 <= 0]
27.01/26.63	  4) f2#(I6, I7) -> f3#(I6, I7) [1 <= I6]
27.01/26.63	  5) f2#(I8, I9) -> f3#(I8, I9) [1 + I8 <= 0]
27.01/26.63	  6) f1#(I10, I11) -> f2#(I10, -1 + I11) [2 - I11 <= I10 /\ I11 <= I10]
27.01/26.63	  7) f1#(I12, I13) -> f2#(-1 + I12, I13) [1 + I13 <= I12 /\ I13 <= 1 - I12]
27.01/26.63	  8) f1#(I14, I15) -> f2#(I14, 1 + I15) [1 + I14 <= -1 * I15 /\ I14 <= I15]
27.01/26.63	  9) f1#(I16, I17) -> f2#(1 + I16, I17) [1 + I16 <= I17 /\ -1 * I16 <= I17]
27.01/26.63	
27.01/26.63	We have the following SCCs.
27.01/26.63	  { 2, 3, 4, 5, 6, 7, 8, 9 }
27.01/26.63	
27.01/26.63	DP problem for innermost termination.
27.01/26.63	P =
27.01/26.63	  f3#(I2, I3) -> f1#(I2, I3) [1 <= I3]
27.01/26.63	  f3#(I4, I5) -> f1#(I4, I5) [1 + I5 <= 0]
27.01/26.63	  f2#(I6, I7) -> f3#(I6, I7) [1 <= I6]
27.01/26.63	  f2#(I8, I9) -> f3#(I8, I9) [1 + I8 <= 0]
27.01/26.63	  f1#(I10, I11) -> f2#(I10, -1 + I11) [2 - I11 <= I10 /\ I11 <= I10]
27.01/26.63	  f1#(I12, I13) -> f2#(-1 + I12, I13) [1 + I13 <= I12 /\ I13 <= 1 - I12]
27.01/26.63	  f1#(I14, I15) -> f2#(I14, 1 + I15) [1 + I14 <= -1 * I15 /\ I14 <= I15]
27.01/26.63	  f1#(I16, I17) -> f2#(1 + I16, I17) [1 + I16 <= I17 /\ -1 * I16 <= I17]
27.01/26.63	R = 
27.01/26.63	  f5(x1, x2) -> f4(x1, x2) 
27.01/26.63	  f4(I0, I1) -> f2(I0, I1) 
27.01/26.63	  f3(I2, I3) -> f1(I2, I3) [1 <= I3]
27.01/26.63	  f3(I4, I5) -> f1(I4, I5) [1 + I5 <= 0]
27.01/26.63	  f2(I6, I7) -> f3(I6, I7) [1 <= I6]
27.01/26.63	  f2(I8, I9) -> f3(I8, I9) [1 + I8 <= 0]
27.01/26.63	  f1(I10, I11) -> f2(I10, -1 + I11) [2 - I11 <= I10 /\ I11 <= I10]
27.01/26.63	  f1(I12, I13) -> f2(-1 + I12, I13) [1 + I13 <= I12 /\ I13 <= 1 - I12]
27.01/26.63	  f1(I14, I15) -> f2(I14, 1 + I15) [1 + I14 <= -1 * I15 /\ I14 <= I15]
27.01/26.63	  f1(I16, I17) -> f2(1 + I16, I17) [1 + I16 <= I17 /\ -1 * I16 <= I17]
27.01/26.63	
27.01/29.60	EOF