0.00/0.01 YES 0.00/0.01 0.00/0.01 DP problem for innermost termination. 0.00/0.01 P = 0.00/0.01 f3#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) 0.00/0.01 R = 0.00/0.01 f3(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) -> f1(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) 0.00/0.01 f1(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9, I10) -> f2(rnd1, I1, rnd3, rnd4, rnd5, rnd6, rnd7, I1, rnd9, rnd10, rnd11) [rnd1 = rnd1 /\ rnd3 = rnd3 /\ rnd11 = rnd11 /\ rnd9 = rnd9 /\ rnd10 = rnd10 /\ rnd5 = rnd5 /\ rnd4 = rnd4 /\ rnd7 = rnd7 /\ rnd6 = rnd6] 0.00/0.01 0.00/0.01 The dependency graph for this problem is: 0.00/0.01 0 -> 0.00/0.01 Where: 0.00/0.01 0) f3#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) 0.00/0.01 0.00/0.01 We have the following SCCs. 0.00/0.01 0.00/0.01 EOF