5.58/5.58	MAYBE
5.58/5.58	
5.58/5.58	DP problem for innermost termination.
5.58/5.58	P =
5.58/5.58	  f9#(x1, x2, x3, x4, x5, x6) -> f8#(x1, x2, x3, x4, x5, x6) 
5.58/5.58	  f8#(I0, I1, I2, I3, I4, I5) -> f1#(I0, rnd2, rnd3, rnd4, 0, 4) [rnd4 = 4 /\ 1 <= rnd3 /\ rnd3 = rnd2 /\ rnd2 = rnd2]
5.58/5.58	  f2#(I6, I7, I8, I9, I10, I11) -> f5#(I6, I7, I8, I9, I10, I11) [I9 <= 0]
5.58/5.58	  f2#(I12, I13, I14, I15, I16, I17) -> f7#(rnd1, I13, I14, I15, I16, I17) [rnd1 = rnd1 /\ 1 <= I15]
5.58/5.58	  f7#(I18, I19, I20, I21, I22, I23) -> f1#(I18, I19, -1 + I20, -1 + I21, 1 + I22, I23) [1 <= I18]
5.58/5.58	  f7#(I24, I25, I26, I27, I28, I29) -> f1#(I24, I25, I26, -1 + I27, I28, I29) [1 + I26 <= I27 /\ I24 <= 0]
5.58/5.58	  f6#(I30, I31, I32, I33, I34, I35) -> f5#(I30, I31, I32, I33, I34, I35) 
5.58/5.58	  f5#(I36, I37, I38, I39, I40, I41) -> f6#(I36, I37, I38, I39, I40, I41) 
5.58/5.58	  f1#(I48, I49, I50, I51, I52, I53) -> f2#(I48, I49, I50, I51, I52, I53) 
5.58/5.58	R = 
5.58/5.58	  f9(x1, x2, x3, x4, x5, x6) -> f8(x1, x2, x3, x4, x5, x6) 
5.58/5.58	  f8(I0, I1, I2, I3, I4, I5) -> f1(I0, rnd2, rnd3, rnd4, 0, 4) [rnd4 = 4 /\ 1 <= rnd3 /\ rnd3 = rnd2 /\ rnd2 = rnd2]
5.58/5.58	  f2(I6, I7, I8, I9, I10, I11) -> f5(I6, I7, I8, I9, I10, I11) [I9 <= 0]
5.58/5.58	  f2(I12, I13, I14, I15, I16, I17) -> f7(rnd1, I13, I14, I15, I16, I17) [rnd1 = rnd1 /\ 1 <= I15]
5.58/5.58	  f7(I18, I19, I20, I21, I22, I23) -> f1(I18, I19, -1 + I20, -1 + I21, 1 + I22, I23) [1 <= I18]
5.58/5.58	  f7(I24, I25, I26, I27, I28, I29) -> f1(I24, I25, I26, -1 + I27, I28, I29) [1 + I26 <= I27 /\ I24 <= 0]
5.58/5.58	  f6(I30, I31, I32, I33, I34, I35) -> f5(I30, I31, I32, I33, I34, I35) 
5.58/5.58	  f5(I36, I37, I38, I39, I40, I41) -> f6(I36, I37, I38, I39, I40, I41) 
5.58/5.58	  f3(I42, I43, I44, I45, I46, I47) -> f4(I42, I43, I44, I45, I46, I47) 
5.58/5.58	  f1(I48, I49, I50, I51, I52, I53) -> f2(I48, I49, I50, I51, I52, I53) 
5.58/5.58	
5.58/5.58	The dependency graph for this problem is:
5.58/5.58	  0 -> 1
5.58/5.58	  1 -> 8
5.58/5.58	  2 -> 7
5.58/5.58	  3 -> 4, 5
5.58/5.58	  4 -> 8
5.58/5.58	  5 -> 8
5.58/5.58	  6 -> 7
5.58/5.58	  7 -> 6
5.58/5.58	  8 -> 2, 3
5.58/5.58	Where:
5.58/5.58	  0) f9#(x1, x2, x3, x4, x5, x6) -> f8#(x1, x2, x3, x4, x5, x6) 
5.58/5.58	  1) f8#(I0, I1, I2, I3, I4, I5) -> f1#(I0, rnd2, rnd3, rnd4, 0, 4) [rnd4 = 4 /\ 1 <= rnd3 /\ rnd3 = rnd2 /\ rnd2 = rnd2]
5.58/5.58	  2) f2#(I6, I7, I8, I9, I10, I11) -> f5#(I6, I7, I8, I9, I10, I11) [I9 <= 0]
5.58/5.58	  3) f2#(I12, I13, I14, I15, I16, I17) -> f7#(rnd1, I13, I14, I15, I16, I17) [rnd1 = rnd1 /\ 1 <= I15]
5.58/5.58	  4) f7#(I18, I19, I20, I21, I22, I23) -> f1#(I18, I19, -1 + I20, -1 + I21, 1 + I22, I23) [1 <= I18]
5.58/5.58	  5) f7#(I24, I25, I26, I27, I28, I29) -> f1#(I24, I25, I26, -1 + I27, I28, I29) [1 + I26 <= I27 /\ I24 <= 0]
5.58/5.58	  6) f6#(I30, I31, I32, I33, I34, I35) -> f5#(I30, I31, I32, I33, I34, I35) 
5.58/5.58	  7) f5#(I36, I37, I38, I39, I40, I41) -> f6#(I36, I37, I38, I39, I40, I41) 
5.58/5.58	  8) f1#(I48, I49, I50, I51, I52, I53) -> f2#(I48, I49, I50, I51, I52, I53) 
5.58/5.58	
5.58/5.58	We have the following SCCs.
5.58/5.58	  { 3, 4, 5, 8 }
5.58/5.58	  { 6, 7 }
5.58/5.58	
5.58/5.58	DP problem for innermost termination.
5.58/5.58	P =
5.58/5.58	  f6#(I30, I31, I32, I33, I34, I35) -> f5#(I30, I31, I32, I33, I34, I35) 
5.58/5.58	  f5#(I36, I37, I38, I39, I40, I41) -> f6#(I36, I37, I38, I39, I40, I41) 
5.58/5.58	R = 
5.58/5.58	  f9(x1, x2, x3, x4, x5, x6) -> f8(x1, x2, x3, x4, x5, x6) 
5.58/5.58	  f8(I0, I1, I2, I3, I4, I5) -> f1(I0, rnd2, rnd3, rnd4, 0, 4) [rnd4 = 4 /\ 1 <= rnd3 /\ rnd3 = rnd2 /\ rnd2 = rnd2]
5.58/5.58	  f2(I6, I7, I8, I9, I10, I11) -> f5(I6, I7, I8, I9, I10, I11) [I9 <= 0]
5.58/5.58	  f2(I12, I13, I14, I15, I16, I17) -> f7(rnd1, I13, I14, I15, I16, I17) [rnd1 = rnd1 /\ 1 <= I15]
5.58/5.58	  f7(I18, I19, I20, I21, I22, I23) -> f1(I18, I19, -1 + I20, -1 + I21, 1 + I22, I23) [1 <= I18]
5.58/5.58	  f7(I24, I25, I26, I27, I28, I29) -> f1(I24, I25, I26, -1 + I27, I28, I29) [1 + I26 <= I27 /\ I24 <= 0]
5.58/5.58	  f6(I30, I31, I32, I33, I34, I35) -> f5(I30, I31, I32, I33, I34, I35) 
5.58/5.58	  f5(I36, I37, I38, I39, I40, I41) -> f6(I36, I37, I38, I39, I40, I41) 
5.58/5.58	  f3(I42, I43, I44, I45, I46, I47) -> f4(I42, I43, I44, I45, I46, I47) 
5.58/5.58	  f1(I48, I49, I50, I51, I52, I53) -> f2(I48, I49, I50, I51, I52, I53) 
5.58/5.58	
5.58/8.55	EOF