3.84/3.85	MAYBE
3.84/3.85	
3.84/3.85	DP problem for innermost termination.
3.84/3.85	P =
3.84/3.85	  f6#(x1, x2) -> f1#(x1, x2) 
3.84/3.85	  f2#(I0, I1) -> f5#(-1 + I0, 1 + I1) [1 <= I0]
3.84/3.85	  f5#(I2, I3) -> f2#(I2, I3) 
3.84/3.85	  f5#(I4, I5) -> f3#(I4, -1 + I5) [1 <= I5]
3.84/3.85	  f3#(I6, I7) -> f5#(-1 + I6, 1 + I7) [1 <= I6]
3.84/3.85	  f4#(I8, I9) -> f3#(I8, I9) 
3.84/3.85	  f3#(I10, I11) -> f4#(1 + I10, -1 + I11) [1 <= I11]
3.84/3.85	  f1#(I12, I13) -> f2#(I12, I13) [0 <= I12 /\ 0 <= I13 /\ I13 <= 0]
3.84/3.85	R = 
3.84/3.85	  f6(x1, x2) -> f1(x1, x2) 
3.84/3.85	  f2(I0, I1) -> f5(-1 + I0, 1 + I1) [1 <= I0]
3.84/3.85	  f5(I2, I3) -> f2(I2, I3) 
3.84/3.85	  f5(I4, I5) -> f3(I4, -1 + I5) [1 <= I5]
3.84/3.85	  f3(I6, I7) -> f5(-1 + I6, 1 + I7) [1 <= I6]
3.84/3.85	  f4(I8, I9) -> f3(I8, I9) 
3.84/3.85	  f3(I10, I11) -> f4(1 + I10, -1 + I11) [1 <= I11]
3.84/3.85	  f1(I12, I13) -> f2(I12, I13) [0 <= I12 /\ 0 <= I13 /\ I13 <= 0]
3.84/3.85	
3.84/3.85	The dependency graph for this problem is:
3.84/3.85	  0 -> 7
3.84/3.85	  1 -> 2, 3
3.84/3.85	  2 -> 1
3.84/3.85	  3 -> 4, 6
3.84/3.85	  4 -> 2, 3
3.84/3.85	  5 -> 4, 6
3.84/3.85	  6 -> 5
3.84/3.85	  7 -> 1
3.84/3.85	Where:
3.84/3.85	  0) f6#(x1, x2) -> f1#(x1, x2) 
3.84/3.85	  1) f2#(I0, I1) -> f5#(-1 + I0, 1 + I1) [1 <= I0]
3.84/3.85	  2) f5#(I2, I3) -> f2#(I2, I3) 
3.84/3.85	  3) f5#(I4, I5) -> f3#(I4, -1 + I5) [1 <= I5]
3.84/3.85	  4) f3#(I6, I7) -> f5#(-1 + I6, 1 + I7) [1 <= I6]
3.84/3.85	  5) f4#(I8, I9) -> f3#(I8, I9) 
3.84/3.85	  6) f3#(I10, I11) -> f4#(1 + I10, -1 + I11) [1 <= I11]
3.84/3.85	  7) f1#(I12, I13) -> f2#(I12, I13) [0 <= I12 /\ 0 <= I13 /\ I13 <= 0]
3.84/3.85	
3.84/3.85	We have the following SCCs.
3.84/3.85	  { 1, 2, 3, 4, 5, 6 }
3.84/3.85	
3.84/3.85	DP problem for innermost termination.
3.84/3.85	P =
3.84/3.85	  f2#(I0, I1) -> f5#(-1 + I0, 1 + I1) [1 <= I0]
3.84/3.85	  f5#(I2, I3) -> f2#(I2, I3) 
3.84/3.85	  f5#(I4, I5) -> f3#(I4, -1 + I5) [1 <= I5]
3.84/3.85	  f3#(I6, I7) -> f5#(-1 + I6, 1 + I7) [1 <= I6]
3.84/3.85	  f4#(I8, I9) -> f3#(I8, I9) 
3.84/3.85	  f3#(I10, I11) -> f4#(1 + I10, -1 + I11) [1 <= I11]
3.84/3.85	R = 
3.84/3.85	  f6(x1, x2) -> f1(x1, x2) 
3.84/3.85	  f2(I0, I1) -> f5(-1 + I0, 1 + I1) [1 <= I0]
3.84/3.85	  f5(I2, I3) -> f2(I2, I3) 
3.84/3.85	  f5(I4, I5) -> f3(I4, -1 + I5) [1 <= I5]
3.84/3.85	  f3(I6, I7) -> f5(-1 + I6, 1 + I7) [1 <= I6]
3.84/3.85	  f4(I8, I9) -> f3(I8, I9) 
3.84/3.85	  f3(I10, I11) -> f4(1 + I10, -1 + I11) [1 <= I11]
3.84/3.85	  f1(I12, I13) -> f2(I12, I13) [0 <= I12 /\ 0 <= I13 /\ I13 <= 0]
3.84/3.85	
3.84/6.82	EOF