5.22/5.61	MAYBE
5.22/5.61	
5.22/5.61	DP problem for innermost termination.
5.22/5.61	P =
5.22/5.61	  f10#(x1, x2, x3, x4, x5, x6) -> f9#(x1, x2, x3, x4, x5, x6) 
5.22/5.61	  f9#(I0, I1, I2, I3, I4, I5) -> f1#(0, 0, rnd3, I3, rnd5, I5) [rnd5 = rnd3 /\ rnd3 = rnd3]
5.22/5.61	  f2#(I6, I7, I8, I9, I10, I11) -> f7#(I6, I7, I8, I9, I10, I11) [1 <= I10]
5.22/5.61	  f2#(I12, I13, I14, I15, I16, I17) -> f3#(0, I13, I14, rnd4, I16, rnd6) [I16 <= 0 /\ y1 = 1 /\ rnd4 = rnd4 /\ rnd6 = rnd4]
5.22/5.61	  f4#(I18, I19, I20, I21, I22, I23) -> f1#(I18, 0, I24, I21, I25, I23) [I23 <= 0 /\ I26 = 1 /\ I24 = I24 /\ I25 = I24]
5.22/5.61	  f4#(I27, I28, I29, I30, I31, I32) -> f3#(I27, I28, I29, I30, I31, I32) [1 <= I32]
5.22/5.61	  f8#(I33, I34, I35, I36, I37, I38) -> f7#(I33, I34, I35, I36, I37, I38) 
5.22/5.61	  f7#(I39, I40, I41, I42, I43, I44) -> f8#(I39, I40, I41, I42, I43, I44) 
5.22/5.61	  f3#(I51, I52, I53, I54, I55, I56) -> f4#(I51, I52, I53, I54, I55, I56) 
5.22/5.61	  f1#(I57, I58, I59, I60, I61, I62) -> f2#(I57, I58, I59, I60, I61, I62) 
5.22/5.61	R = 
5.22/5.61	  f10(x1, x2, x3, x4, x5, x6) -> f9(x1, x2, x3, x4, x5, x6) 
5.22/5.61	  f9(I0, I1, I2, I3, I4, I5) -> f1(0, 0, rnd3, I3, rnd5, I5) [rnd5 = rnd3 /\ rnd3 = rnd3]
5.22/5.61	  f2(I6, I7, I8, I9, I10, I11) -> f7(I6, I7, I8, I9, I10, I11) [1 <= I10]
5.22/5.61	  f2(I12, I13, I14, I15, I16, I17) -> f3(0, I13, I14, rnd4, I16, rnd6) [I16 <= 0 /\ y1 = 1 /\ rnd4 = rnd4 /\ rnd6 = rnd4]
5.22/5.61	  f4(I18, I19, I20, I21, I22, I23) -> f1(I18, 0, I24, I21, I25, I23) [I23 <= 0 /\ I26 = 1 /\ I24 = I24 /\ I25 = I24]
5.22/5.61	  f4(I27, I28, I29, I30, I31, I32) -> f3(I27, I28, I29, I30, I31, I32) [1 <= I32]
5.22/5.61	  f8(I33, I34, I35, I36, I37, I38) -> f7(I33, I34, I35, I36, I37, I38) 
5.22/5.61	  f7(I39, I40, I41, I42, I43, I44) -> f8(I39, I40, I41, I42, I43, I44) 
5.22/5.61	  f5(I45, I46, I47, I48, I49, I50) -> f6(I45, I46, I47, I48, I49, I50) 
5.22/5.61	  f3(I51, I52, I53, I54, I55, I56) -> f4(I51, I52, I53, I54, I55, I56) 
5.22/5.61	  f1(I57, I58, I59, I60, I61, I62) -> f2(I57, I58, I59, I60, I61, I62) 
5.22/5.61	
5.22/5.61	The dependency graph for this problem is:
5.22/5.61	  0 -> 1
5.22/5.61	  1 -> 9
5.22/5.61	  2 -> 7
5.22/5.61	  3 -> 8
5.22/5.61	  4 -> 9
5.22/5.61	  5 -> 8
5.22/5.61	  6 -> 7
5.22/5.61	  7 -> 6
5.22/5.61	  8 -> 4, 5
5.22/5.61	  9 -> 2, 3
5.22/5.61	Where:
5.22/5.61	  0) f10#(x1, x2, x3, x4, x5, x6) -> f9#(x1, x2, x3, x4, x5, x6) 
5.22/5.61	  1) f9#(I0, I1, I2, I3, I4, I5) -> f1#(0, 0, rnd3, I3, rnd5, I5) [rnd5 = rnd3 /\ rnd3 = rnd3]
5.22/5.61	  2) f2#(I6, I7, I8, I9, I10, I11) -> f7#(I6, I7, I8, I9, I10, I11) [1 <= I10]
5.22/5.61	  3) f2#(I12, I13, I14, I15, I16, I17) -> f3#(0, I13, I14, rnd4, I16, rnd6) [I16 <= 0 /\ y1 = 1 /\ rnd4 = rnd4 /\ rnd6 = rnd4]
5.22/5.61	  4) f4#(I18, I19, I20, I21, I22, I23) -> f1#(I18, 0, I24, I21, I25, I23) [I23 <= 0 /\ I26 = 1 /\ I24 = I24 /\ I25 = I24]
5.22/5.61	  5) f4#(I27, I28, I29, I30, I31, I32) -> f3#(I27, I28, I29, I30, I31, I32) [1 <= I32]
5.22/5.61	  6) f8#(I33, I34, I35, I36, I37, I38) -> f7#(I33, I34, I35, I36, I37, I38) 
5.22/5.61	  7) f7#(I39, I40, I41, I42, I43, I44) -> f8#(I39, I40, I41, I42, I43, I44) 
5.22/5.61	  8) f3#(I51, I52, I53, I54, I55, I56) -> f4#(I51, I52, I53, I54, I55, I56) 
5.22/5.61	  9) f1#(I57, I58, I59, I60, I61, I62) -> f2#(I57, I58, I59, I60, I61, I62) 
5.22/5.61	
5.22/5.61	We have the following SCCs.
5.22/5.61	  { 3, 4, 5, 8, 9 }
5.22/5.61	  { 6, 7 }
5.22/5.61	
5.22/5.61	DP problem for innermost termination.
5.22/5.61	P =
5.22/5.61	  f8#(I33, I34, I35, I36, I37, I38) -> f7#(I33, I34, I35, I36, I37, I38) 
5.22/5.61	  f7#(I39, I40, I41, I42, I43, I44) -> f8#(I39, I40, I41, I42, I43, I44) 
5.22/5.61	R = 
5.22/5.61	  f10(x1, x2, x3, x4, x5, x6) -> f9(x1, x2, x3, x4, x5, x6) 
5.22/5.61	  f9(I0, I1, I2, I3, I4, I5) -> f1(0, 0, rnd3, I3, rnd5, I5) [rnd5 = rnd3 /\ rnd3 = rnd3]
5.22/5.61	  f2(I6, I7, I8, I9, I10, I11) -> f7(I6, I7, I8, I9, I10, I11) [1 <= I10]
5.22/5.61	  f2(I12, I13, I14, I15, I16, I17) -> f3(0, I13, I14, rnd4, I16, rnd6) [I16 <= 0 /\ y1 = 1 /\ rnd4 = rnd4 /\ rnd6 = rnd4]
5.22/5.61	  f4(I18, I19, I20, I21, I22, I23) -> f1(I18, 0, I24, I21, I25, I23) [I23 <= 0 /\ I26 = 1 /\ I24 = I24 /\ I25 = I24]
5.22/5.61	  f4(I27, I28, I29, I30, I31, I32) -> f3(I27, I28, I29, I30, I31, I32) [1 <= I32]
5.22/5.61	  f8(I33, I34, I35, I36, I37, I38) -> f7(I33, I34, I35, I36, I37, I38) 
5.22/5.61	  f7(I39, I40, I41, I42, I43, I44) -> f8(I39, I40, I41, I42, I43, I44) 
5.22/5.61	  f5(I45, I46, I47, I48, I49, I50) -> f6(I45, I46, I47, I48, I49, I50) 
5.22/5.61	  f3(I51, I52, I53, I54, I55, I56) -> f4(I51, I52, I53, I54, I55, I56) 
5.22/5.61	  f1(I57, I58, I59, I60, I61, I62) -> f2(I57, I58, I59, I60, I61, I62) 
5.22/5.61	
5.22/8.59	EOF