15.37/15.21	MAYBE
15.37/15.21	
15.37/15.21	DP problem for innermost termination.
15.37/15.21	P =
15.37/15.21	  f5#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) 
15.37/15.21	  f4#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) 
15.37/15.21	  f2#(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) -> f4#(I10, I11, I12, I13, I14, rnd6, rnd7, rnd8, I18, I19) [y2 = I13 /\ y3 = I14 /\ 0 <= -1 - y2 + y3 /\ rnd7 = rnd7 /\ rnd8 = rnd8 /\ y1 = I13 /\ rnd6 = rnd6]
15.37/15.21	  f1#(I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f2#(I34, rnd2, rnd3, I37, I38, I39, I40, I41, rnd9, rnd10) [rnd10 = rnd10 /\ rnd9 = rnd9 /\ B0 = B0 /\ rnd3 = rnd3 /\ B1 = B1 /\ rnd2 = rnd2]
15.37/15.21	R = 
15.37/15.21	  f5(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) -> f1(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) 
15.37/15.21	  f4(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f2(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) 
15.37/15.21	  f2(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) -> f4(I10, I11, I12, I13, I14, rnd6, rnd7, rnd8, I18, I19) [y2 = I13 /\ y3 = I14 /\ 0 <= -1 - y2 + y3 /\ rnd7 = rnd7 /\ rnd8 = rnd8 /\ y1 = I13 /\ rnd6 = rnd6]
15.37/15.21	  f2(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) -> f3(rnd1, I21, I22, I23, I24, I25, I30, I31, I28, I29) [I32 = I23 /\ I33 = I24 /\ -1 * I32 + I33 <= 0 /\ I30 = I30 /\ I31 = I31 /\ rnd1 = rnd1]
15.37/15.21	  f1(I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f2(I34, rnd2, rnd3, I37, I38, I39, I40, I41, rnd9, rnd10) [rnd10 = rnd10 /\ rnd9 = rnd9 /\ B0 = B0 /\ rnd3 = rnd3 /\ B1 = B1 /\ rnd2 = rnd2]
15.37/15.21	
15.37/15.21	The dependency graph for this problem is:
15.37/15.21	  0 -> 3
15.37/15.21	  1 -> 2
15.37/15.21	  2 -> 1
15.37/15.21	  3 -> 2
15.37/15.21	Where:
15.37/15.21	  0) f5#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) 
15.37/15.21	  1) f4#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) 
15.37/15.21	  2) f2#(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) -> f4#(I10, I11, I12, I13, I14, rnd6, rnd7, rnd8, I18, I19) [y2 = I13 /\ y3 = I14 /\ 0 <= -1 - y2 + y3 /\ rnd7 = rnd7 /\ rnd8 = rnd8 /\ y1 = I13 /\ rnd6 = rnd6]
15.37/15.21	  3) f1#(I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f2#(I34, rnd2, rnd3, I37, I38, I39, I40, I41, rnd9, rnd10) [rnd10 = rnd10 /\ rnd9 = rnd9 /\ B0 = B0 /\ rnd3 = rnd3 /\ B1 = B1 /\ rnd2 = rnd2]
15.37/15.21	
15.37/15.21	We have the following SCCs.
15.37/15.21	  { 1, 2 }
15.37/15.21	
15.37/15.21	DP problem for innermost termination.
15.37/15.21	P =
15.37/15.21	  f4#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) 
15.37/15.21	  f2#(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) -> f4#(I10, I11, I12, I13, I14, rnd6, rnd7, rnd8, I18, I19) [y2 = I13 /\ y3 = I14 /\ 0 <= -1 - y2 + y3 /\ rnd7 = rnd7 /\ rnd8 = rnd8 /\ y1 = I13 /\ rnd6 = rnd6]
15.37/15.21	R = 
15.37/15.21	  f5(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) -> f1(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) 
15.37/15.21	  f4(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f2(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) 
15.37/15.21	  f2(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) -> f4(I10, I11, I12, I13, I14, rnd6, rnd7, rnd8, I18, I19) [y2 = I13 /\ y3 = I14 /\ 0 <= -1 - y2 + y3 /\ rnd7 = rnd7 /\ rnd8 = rnd8 /\ y1 = I13 /\ rnd6 = rnd6]
15.37/15.21	  f2(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) -> f3(rnd1, I21, I22, I23, I24, I25, I30, I31, I28, I29) [I32 = I23 /\ I33 = I24 /\ -1 * I32 + I33 <= 0 /\ I30 = I30 /\ I31 = I31 /\ rnd1 = rnd1]
15.37/15.21	  f1(I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f2(I34, rnd2, rnd3, I37, I38, I39, I40, I41, rnd9, rnd10) [rnd10 = rnd10 /\ rnd9 = rnd9 /\ B0 = B0 /\ rnd3 = rnd3 /\ B1 = B1 /\ rnd2 = rnd2]
15.37/15.21	
15.37/18.19	EOF