5.85/5.80	MAYBE
5.85/5.80	
5.85/5.80	DP problem for innermost termination.
5.85/5.80	P =
5.85/5.80	  f6#(x1, x2, x3, x4, x5, x6) -> f1#(x1, x2, x3, x4, x5, x6) 
5.85/5.80	  f5#(I0, I1, I2, I3, I4, I5) -> f2#(I0, I1, I2, I3, I4, I5) 
5.85/5.80	  f2#(I6, I7, I8, I9, I10, I11) -> f5#(I6, I7, -1 + I8, rnd4, I10, I11) [1 + rnd4 <= I6 /\ -1 + rnd4 <= -1 + I8 /\ -1 + I8 <= -1 + rnd4 /\ 1 + I8 <= I6 /\ rnd4 = rnd4]
5.85/5.80	  f3#(I18, I19, I20, I21, I22, I23) -> f2#(I18, rnd2, rnd3, I21, I22, I23) [1 + I20 <= I18 /\ y1 = -1 + I20 /\ rnd3 = rnd3 /\ -1 <= rnd3 /\ rnd3 <= -1 /\ rnd2 = rnd2 /\ rnd2 <= rnd3 /\ rnd3 <= rnd2]
5.85/5.80	  f1#(I24, I25, I26, I27, I28, I29) -> f2#(I24, I25, 0, I27, I28, I29) [0 <= 0 /\ 0 <= 0]
5.85/5.80	R = 
5.85/5.80	  f6(x1, x2, x3, x4, x5, x6) -> f1(x1, x2, x3, x4, x5, x6) 
5.85/5.80	  f5(I0, I1, I2, I3, I4, I5) -> f2(I0, I1, I2, I3, I4, I5) 
5.85/5.80	  f2(I6, I7, I8, I9, I10, I11) -> f5(I6, I7, -1 + I8, rnd4, I10, I11) [1 + rnd4 <= I6 /\ -1 + rnd4 <= -1 + I8 /\ -1 + I8 <= -1 + rnd4 /\ 1 + I8 <= I6 /\ rnd4 = rnd4]
5.85/5.80	  f2(I12, I13, I14, I15, I16, I17) -> f4(I12, I13, I14, I15, I17, I17) [I12 <= I14]
5.85/5.80	  f3(I18, I19, I20, I21, I22, I23) -> f2(I18, rnd2, rnd3, I21, I22, I23) [1 + I20 <= I18 /\ y1 = -1 + I20 /\ rnd3 = rnd3 /\ -1 <= rnd3 /\ rnd3 <= -1 /\ rnd2 = rnd2 /\ rnd2 <= rnd3 /\ rnd3 <= rnd2]
5.85/5.80	  f1(I24, I25, I26, I27, I28, I29) -> f2(I24, I25, 0, I27, I28, I29) [0 <= 0 /\ 0 <= 0]
5.85/5.80	
5.85/5.80	The dependency graph for this problem is:
5.85/5.80	  0 -> 4
5.85/5.80	  1 -> 2
5.85/5.80	  2 -> 1
5.85/5.80	  3 -> 2
5.85/5.80	  4 -> 2
5.85/5.80	Where:
5.85/5.80	  0) f6#(x1, x2, x3, x4, x5, x6) -> f1#(x1, x2, x3, x4, x5, x6) 
5.85/5.80	  1) f5#(I0, I1, I2, I3, I4, I5) -> f2#(I0, I1, I2, I3, I4, I5) 
5.85/5.80	  2) f2#(I6, I7, I8, I9, I10, I11) -> f5#(I6, I7, -1 + I8, rnd4, I10, I11) [1 + rnd4 <= I6 /\ -1 + rnd4 <= -1 + I8 /\ -1 + I8 <= -1 + rnd4 /\ 1 + I8 <= I6 /\ rnd4 = rnd4]
5.85/5.80	  3) f3#(I18, I19, I20, I21, I22, I23) -> f2#(I18, rnd2, rnd3, I21, I22, I23) [1 + I20 <= I18 /\ y1 = -1 + I20 /\ rnd3 = rnd3 /\ -1 <= rnd3 /\ rnd3 <= -1 /\ rnd2 = rnd2 /\ rnd2 <= rnd3 /\ rnd3 <= rnd2]
5.85/5.80	  4) f1#(I24, I25, I26, I27, I28, I29) -> f2#(I24, I25, 0, I27, I28, I29) [0 <= 0 /\ 0 <= 0]
5.85/5.80	
5.85/5.80	We have the following SCCs.
5.85/5.80	  { 1, 2 }
5.85/5.80	
5.85/5.80	DP problem for innermost termination.
5.85/5.80	P =
5.85/5.80	  f5#(I0, I1, I2, I3, I4, I5) -> f2#(I0, I1, I2, I3, I4, I5) 
5.85/5.80	  f2#(I6, I7, I8, I9, I10, I11) -> f5#(I6, I7, -1 + I8, rnd4, I10, I11) [1 + rnd4 <= I6 /\ -1 + rnd4 <= -1 + I8 /\ -1 + I8 <= -1 + rnd4 /\ 1 + I8 <= I6 /\ rnd4 = rnd4]
5.85/5.80	R = 
5.85/5.80	  f6(x1, x2, x3, x4, x5, x6) -> f1(x1, x2, x3, x4, x5, x6) 
5.85/5.80	  f5(I0, I1, I2, I3, I4, I5) -> f2(I0, I1, I2, I3, I4, I5) 
5.85/5.80	  f2(I6, I7, I8, I9, I10, I11) -> f5(I6, I7, -1 + I8, rnd4, I10, I11) [1 + rnd4 <= I6 /\ -1 + rnd4 <= -1 + I8 /\ -1 + I8 <= -1 + rnd4 /\ 1 + I8 <= I6 /\ rnd4 = rnd4]
5.85/5.80	  f2(I12, I13, I14, I15, I16, I17) -> f4(I12, I13, I14, I15, I17, I17) [I12 <= I14]
5.85/5.80	  f3(I18, I19, I20, I21, I22, I23) -> f2(I18, rnd2, rnd3, I21, I22, I23) [1 + I20 <= I18 /\ y1 = -1 + I20 /\ rnd3 = rnd3 /\ -1 <= rnd3 /\ rnd3 <= -1 /\ rnd2 = rnd2 /\ rnd2 <= rnd3 /\ rnd3 <= rnd2]
5.85/5.80	  f1(I24, I25, I26, I27, I28, I29) -> f2(I24, I25, 0, I27, I28, I29) [0 <= 0 /\ 0 <= 0]
5.85/5.80	
5.85/8.78	EOF