10.02/10.21	MAYBE
10.02/10.21	
10.02/10.21	DP problem for innermost termination.
10.02/10.21	P =
10.02/10.21	  f5#(x1, x2, x3, x4, x5, x6, x7, x8) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8) 
10.02/10.21	  f4#(I0, I1, I2, I3, I4, I5, I6, I7) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7) 
10.02/10.21	  f2#(I8, I9, I10, I11, I12, I13, I14, I15) -> f4#(I8, I9, I10, rnd4, rnd5, rnd6, I14, I15) [y2 = I9 /\ y3 = I10 /\ 0 <= -1 - y2 + y3 /\ rnd5 = rnd5 /\ rnd6 = rnd6 /\ y1 = I9 /\ rnd4 = rnd4]
10.02/10.21	  f1#(I28, I29, I30, I31, I32, I33, I34, I35) -> f2#(I28, I29, I30, I31, I32, I33, rnd7, rnd8) [rnd7 = rnd7 /\ rnd8 = rnd8]
10.02/10.21	R = 
10.02/10.21	  f5(x1, x2, x3, x4, x5, x6, x7, x8) -> f1(x1, x2, x3, x4, x5, x6, x7, x8) 
10.02/10.21	  f4(I0, I1, I2, I3, I4, I5, I6, I7) -> f2(I0, I1, I2, I3, I4, I5, I6, I7) 
10.02/10.21	  f2(I8, I9, I10, I11, I12, I13, I14, I15) -> f4(I8, I9, I10, rnd4, rnd5, rnd6, I14, I15) [y2 = I9 /\ y3 = I10 /\ 0 <= -1 - y2 + y3 /\ rnd5 = rnd5 /\ rnd6 = rnd6 /\ y1 = I9 /\ rnd4 = rnd4]
10.02/10.21	  f2(I16, I17, I18, I19, I20, I21, I22, I23) -> f3(rnd1, I17, I18, I19, I24, I25, I22, I23) [I26 = I17 /\ I27 = I18 /\ -1 * I26 + I27 <= 0 /\ I24 = I24 /\ I25 = I25 /\ rnd1 = rnd1]
10.02/10.21	  f1(I28, I29, I30, I31, I32, I33, I34, I35) -> f2(I28, I29, I30, I31, I32, I33, rnd7, rnd8) [rnd7 = rnd7 /\ rnd8 = rnd8]
10.02/10.21	
10.02/10.21	The dependency graph for this problem is:
10.02/10.21	  0 -> 3
10.02/10.21	  1 -> 2
10.02/10.21	  2 -> 1
10.02/10.21	  3 -> 2
10.02/10.21	Where:
10.02/10.21	  0) f5#(x1, x2, x3, x4, x5, x6, x7, x8) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8) 
10.02/10.21	  1) f4#(I0, I1, I2, I3, I4, I5, I6, I7) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7) 
10.02/10.21	  2) f2#(I8, I9, I10, I11, I12, I13, I14, I15) -> f4#(I8, I9, I10, rnd4, rnd5, rnd6, I14, I15) [y2 = I9 /\ y3 = I10 /\ 0 <= -1 - y2 + y3 /\ rnd5 = rnd5 /\ rnd6 = rnd6 /\ y1 = I9 /\ rnd4 = rnd4]
10.02/10.21	  3) f1#(I28, I29, I30, I31, I32, I33, I34, I35) -> f2#(I28, I29, I30, I31, I32, I33, rnd7, rnd8) [rnd7 = rnd7 /\ rnd8 = rnd8]
10.02/10.21	
10.02/10.21	We have the following SCCs.
10.02/10.21	  { 1, 2 }
10.02/10.21	
10.02/10.21	DP problem for innermost termination.
10.02/10.21	P =
10.02/10.21	  f4#(I0, I1, I2, I3, I4, I5, I6, I7) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7) 
10.02/10.21	  f2#(I8, I9, I10, I11, I12, I13, I14, I15) -> f4#(I8, I9, I10, rnd4, rnd5, rnd6, I14, I15) [y2 = I9 /\ y3 = I10 /\ 0 <= -1 - y2 + y3 /\ rnd5 = rnd5 /\ rnd6 = rnd6 /\ y1 = I9 /\ rnd4 = rnd4]
10.02/10.21	R = 
10.02/10.21	  f5(x1, x2, x3, x4, x5, x6, x7, x8) -> f1(x1, x2, x3, x4, x5, x6, x7, x8) 
10.02/10.21	  f4(I0, I1, I2, I3, I4, I5, I6, I7) -> f2(I0, I1, I2, I3, I4, I5, I6, I7) 
10.02/10.21	  f2(I8, I9, I10, I11, I12, I13, I14, I15) -> f4(I8, I9, I10, rnd4, rnd5, rnd6, I14, I15) [y2 = I9 /\ y3 = I10 /\ 0 <= -1 - y2 + y3 /\ rnd5 = rnd5 /\ rnd6 = rnd6 /\ y1 = I9 /\ rnd4 = rnd4]
10.02/10.21	  f2(I16, I17, I18, I19, I20, I21, I22, I23) -> f3(rnd1, I17, I18, I19, I24, I25, I22, I23) [I26 = I17 /\ I27 = I18 /\ -1 * I26 + I27 <= 0 /\ I24 = I24 /\ I25 = I25 /\ rnd1 = rnd1]
10.02/10.21	  f1(I28, I29, I30, I31, I32, I33, I34, I35) -> f2(I28, I29, I30, I31, I32, I33, rnd7, rnd8) [rnd7 = rnd7 /\ rnd8 = rnd8]
10.02/10.21	
10.10/13.19	EOF