7.92/8.28	MAYBE
7.92/8.28	
7.92/8.28	DP problem for innermost termination.
7.92/8.28	P =
7.92/8.28	  f10#(x1, x2, x3, x4, x5, x6, x7) -> f9#(x1, x2, x3, x4, x5, x6, x7) 
7.92/8.28	  f9#(I0, I1, I2, I3, I4, I5, I6) -> f8#(I0, I1, rnd3, rnd4, rnd5, 0, 4) [rnd5 = 4 /\ 1 <= rnd4 /\ rnd4 = rnd3 /\ rnd3 = rnd3]
7.92/8.28	  f8#(I7, I8, I9, I10, I11, I12, I13) -> f1#(I7, I8, I9, I10, I11, I12, I13) [I10 <= I7]
7.92/8.28	  f8#(I14, I15, I16, I17, I18, I19, I20) -> f5#(I14, I15, I16, I17, I18, I19, I20) [1 + I14 <= I17]
7.92/8.28	  f2#(I21, I22, I23, I24, I25, I26, I27) -> f5#(I21, I22, I23, I24, I25, I26, I27) [I25 <= 0]
7.92/8.28	  f2#(I28, I29, I30, I31, I32, I33, I34) -> f7#(I28, rnd2, I30, I31, I32, I33, I34) [rnd2 = rnd2 /\ 1 <= I32]
7.92/8.28	  f7#(I35, I36, I37, I38, I39, I40, I41) -> f1#(I35, I36, I37, -1 + I38, -1 + I39, 1 + I40, I41) [1 <= I36]
7.92/8.28	  f7#(I42, I43, I44, I45, I46, I47, I48) -> f1#(I42, I43, I44, I45, -1 + I46, I47, I48) [1 + I45 <= I46 /\ I43 <= 0]
7.92/8.28	  f6#(I49, I50, I51, I52, I53, I54, I55) -> f5#(I49, I50, I51, I52, I53, I54, I55) 
7.92/8.28	  f5#(I56, I57, I58, I59, I60, I61, I62) -> f6#(I56, I57, I58, I59, I60, I61, I62) 
7.92/8.28	  f1#(I70, I71, I72, I73, I74, I75, I76) -> f2#(I70, I71, I72, I73, I74, I75, I76) 
7.92/8.28	R = 
7.92/8.28	  f10(x1, x2, x3, x4, x5, x6, x7) -> f9(x1, x2, x3, x4, x5, x6, x7) 
7.92/8.28	  f9(I0, I1, I2, I3, I4, I5, I6) -> f8(I0, I1, rnd3, rnd4, rnd5, 0, 4) [rnd5 = 4 /\ 1 <= rnd4 /\ rnd4 = rnd3 /\ rnd3 = rnd3]
7.92/8.28	  f8(I7, I8, I9, I10, I11, I12, I13) -> f1(I7, I8, I9, I10, I11, I12, I13) [I10 <= I7]
7.92/8.28	  f8(I14, I15, I16, I17, I18, I19, I20) -> f5(I14, I15, I16, I17, I18, I19, I20) [1 + I14 <= I17]
7.92/8.28	  f2(I21, I22, I23, I24, I25, I26, I27) -> f5(I21, I22, I23, I24, I25, I26, I27) [I25 <= 0]
7.92/8.28	  f2(I28, I29, I30, I31, I32, I33, I34) -> f7(I28, rnd2, I30, I31, I32, I33, I34) [rnd2 = rnd2 /\ 1 <= I32]
7.92/8.28	  f7(I35, I36, I37, I38, I39, I40, I41) -> f1(I35, I36, I37, -1 + I38, -1 + I39, 1 + I40, I41) [1 <= I36]
7.92/8.28	  f7(I42, I43, I44, I45, I46, I47, I48) -> f1(I42, I43, I44, I45, -1 + I46, I47, I48) [1 + I45 <= I46 /\ I43 <= 0]
7.92/8.28	  f6(I49, I50, I51, I52, I53, I54, I55) -> f5(I49, I50, I51, I52, I53, I54, I55) 
7.92/8.28	  f5(I56, I57, I58, I59, I60, I61, I62) -> f6(I56, I57, I58, I59, I60, I61, I62) 
7.92/8.28	  f3(I63, I64, I65, I66, I67, I68, I69) -> f4(I63, I64, I65, I66, I67, I68, I69) 
7.92/8.28	  f1(I70, I71, I72, I73, I74, I75, I76) -> f2(I70, I71, I72, I73, I74, I75, I76) 
7.92/8.28	
7.92/8.28	The dependency graph for this problem is:
7.92/8.28	  0 -> 1
7.92/8.28	  1 -> 2, 3
7.92/8.28	  2 -> 10
7.92/8.28	  3 -> 9
7.92/8.28	  4 -> 9
7.92/8.28	  5 -> 6, 7
7.92/8.28	  6 -> 10
7.92/8.28	  7 -> 10
7.92/8.28	  8 -> 9
7.92/8.28	  9 -> 8
7.92/8.28	  10 -> 4, 5
7.92/8.28	Where:
7.92/8.28	  0) f10#(x1, x2, x3, x4, x5, x6, x7) -> f9#(x1, x2, x3, x4, x5, x6, x7) 
7.92/8.28	  1) f9#(I0, I1, I2, I3, I4, I5, I6) -> f8#(I0, I1, rnd3, rnd4, rnd5, 0, 4) [rnd5 = 4 /\ 1 <= rnd4 /\ rnd4 = rnd3 /\ rnd3 = rnd3]
7.92/8.28	  2) f8#(I7, I8, I9, I10, I11, I12, I13) -> f1#(I7, I8, I9, I10, I11, I12, I13) [I10 <= I7]
7.92/8.28	  3) f8#(I14, I15, I16, I17, I18, I19, I20) -> f5#(I14, I15, I16, I17, I18, I19, I20) [1 + I14 <= I17]
7.92/8.28	  4) f2#(I21, I22, I23, I24, I25, I26, I27) -> f5#(I21, I22, I23, I24, I25, I26, I27) [I25 <= 0]
7.92/8.28	  5) f2#(I28, I29, I30, I31, I32, I33, I34) -> f7#(I28, rnd2, I30, I31, I32, I33, I34) [rnd2 = rnd2 /\ 1 <= I32]
7.92/8.28	  6) f7#(I35, I36, I37, I38, I39, I40, I41) -> f1#(I35, I36, I37, -1 + I38, -1 + I39, 1 + I40, I41) [1 <= I36]
7.92/8.28	  7) f7#(I42, I43, I44, I45, I46, I47, I48) -> f1#(I42, I43, I44, I45, -1 + I46, I47, I48) [1 + I45 <= I46 /\ I43 <= 0]
7.92/8.28	  8) f6#(I49, I50, I51, I52, I53, I54, I55) -> f5#(I49, I50, I51, I52, I53, I54, I55) 
7.92/8.28	  9) f5#(I56, I57, I58, I59, I60, I61, I62) -> f6#(I56, I57, I58, I59, I60, I61, I62) 
7.92/8.28	  10) f1#(I70, I71, I72, I73, I74, I75, I76) -> f2#(I70, I71, I72, I73, I74, I75, I76) 
7.92/8.28	
7.92/8.28	We have the following SCCs.
7.92/8.28	  { 5, 6, 7, 10 }
7.92/8.28	  { 8, 9 }
7.92/8.28	
7.92/8.28	DP problem for innermost termination.
7.92/8.28	P =
7.92/8.28	  f6#(I49, I50, I51, I52, I53, I54, I55) -> f5#(I49, I50, I51, I52, I53, I54, I55) 
7.92/8.28	  f5#(I56, I57, I58, I59, I60, I61, I62) -> f6#(I56, I57, I58, I59, I60, I61, I62) 
7.92/8.28	R = 
7.92/8.28	  f10(x1, x2, x3, x4, x5, x6, x7) -> f9(x1, x2, x3, x4, x5, x6, x7) 
7.92/8.28	  f9(I0, I1, I2, I3, I4, I5, I6) -> f8(I0, I1, rnd3, rnd4, rnd5, 0, 4) [rnd5 = 4 /\ 1 <= rnd4 /\ rnd4 = rnd3 /\ rnd3 = rnd3]
7.92/8.28	  f8(I7, I8, I9, I10, I11, I12, I13) -> f1(I7, I8, I9, I10, I11, I12, I13) [I10 <= I7]
7.92/8.28	  f8(I14, I15, I16, I17, I18, I19, I20) -> f5(I14, I15, I16, I17, I18, I19, I20) [1 + I14 <= I17]
7.92/8.28	  f2(I21, I22, I23, I24, I25, I26, I27) -> f5(I21, I22, I23, I24, I25, I26, I27) [I25 <= 0]
7.92/8.28	  f2(I28, I29, I30, I31, I32, I33, I34) -> f7(I28, rnd2, I30, I31, I32, I33, I34) [rnd2 = rnd2 /\ 1 <= I32]
7.92/8.28	  f7(I35, I36, I37, I38, I39, I40, I41) -> f1(I35, I36, I37, -1 + I38, -1 + I39, 1 + I40, I41) [1 <= I36]
7.92/8.28	  f7(I42, I43, I44, I45, I46, I47, I48) -> f1(I42, I43, I44, I45, -1 + I46, I47, I48) [1 + I45 <= I46 /\ I43 <= 0]
7.92/8.28	  f6(I49, I50, I51, I52, I53, I54, I55) -> f5(I49, I50, I51, I52, I53, I54, I55) 
7.92/8.28	  f5(I56, I57, I58, I59, I60, I61, I62) -> f6(I56, I57, I58, I59, I60, I61, I62) 
7.92/8.28	  f3(I63, I64, I65, I66, I67, I68, I69) -> f4(I63, I64, I65, I66, I67, I68, I69) 
7.92/8.28	  f1(I70, I71, I72, I73, I74, I75, I76) -> f2(I70, I71, I72, I73, I74, I75, I76) 
7.92/8.28	
7.92/11.26	EOF