20.54/20.35 MAYBE 20.54/20.35 20.54/20.35 DP problem for innermost termination. 20.54/20.35 P = 20.54/20.35 f8#(x1, x2, x3, x4, x5) -> f7#(x1, x2, x3, x4, x5) 20.54/20.35 f7#(I0, I1, I2, I3, I4) -> f3#(I0, I1, I2, I3, I4) [I0 <= 0] 20.54/20.35 f3#(I5, I6, I7, I8, I9) -> f6#(I5, I6, I7, I8, I9) [1 <= I9 /\ 1 <= I8] 20.54/20.35 f6#(I10, I11, I12, I13, I14) -> f5#(I10, I11, I12, -1 + I13, I14) 20.54/20.35 f6#(I15, I16, I17, I18, I19) -> f5#(I15, I16, I17, I18, -1 + I19) 20.54/20.35 f5#(I20, I21, I22, I23, I24) -> f1#(I20, I21, I22, I23, I24) [1 <= I20] 20.54/20.35 f5#(I25, I26, I27, I28, I29) -> f4#(I25, I26, I27, I28, I29) [I25 <= 0] 20.54/20.35 f4#(I30, I31, I32, I33, I34) -> f3#(1, I33, I34, I33, I34) 20.54/20.35 f4#(I35, I36, I37, I38, I39) -> f3#(I35, I36, I37, I38, I39) [I35 <= 0] 20.54/20.35 f1#(I40, I41, I42, I43, I44) -> f3#(I40, I41, I42, I43, I44) 20.54/20.35 R = 20.54/20.35 f8(x1, x2, x3, x4, x5) -> f7(x1, x2, x3, x4, x5) 20.54/20.35 f7(I0, I1, I2, I3, I4) -> f3(I0, I1, I2, I3, I4) [I0 <= 0] 20.54/20.35 f3(I5, I6, I7, I8, I9) -> f6(I5, I6, I7, I8, I9) [1 <= I9 /\ 1 <= I8] 20.54/20.35 f6(I10, I11, I12, I13, I14) -> f5(I10, I11, I12, -1 + I13, I14) 20.54/20.35 f6(I15, I16, I17, I18, I19) -> f5(I15, I16, I17, I18, -1 + I19) 20.54/20.35 f5(I20, I21, I22, I23, I24) -> f1(I20, I21, I22, I23, I24) [1 <= I20] 20.54/20.35 f5(I25, I26, I27, I28, I29) -> f4(I25, I26, I27, I28, I29) [I25 <= 0] 20.54/20.35 f4(I30, I31, I32, I33, I34) -> f3(1, I33, I34, I33, I34) 20.54/20.35 f4(I35, I36, I37, I38, I39) -> f3(I35, I36, I37, I38, I39) [I35 <= 0] 20.54/20.35 f1(I40, I41, I42, I43, I44) -> f3(I40, I41, I42, I43, I44) 20.54/20.35 f1(I45, I46, I47, I48, I49) -> f2(I45, I46, I47, I48, I49) [I47 <= I49 /\ I46 <= I48] 20.54/20.35 20.54/20.35 The dependency graph for this problem is: 20.54/20.35 0 -> 1 20.54/20.35 1 -> 2 20.54/20.35 2 -> 3, 4 20.54/20.35 3 -> 5, 6 20.54/20.35 4 -> 5, 6 20.54/20.35 5 -> 9 20.54/20.35 6 -> 7, 8 20.54/20.35 7 -> 2 20.54/20.35 8 -> 2 20.54/20.35 9 -> 2 20.54/20.35 Where: 20.54/20.35 0) f8#(x1, x2, x3, x4, x5) -> f7#(x1, x2, x3, x4, x5) 20.54/20.35 1) f7#(I0, I1, I2, I3, I4) -> f3#(I0, I1, I2, I3, I4) [I0 <= 0] 20.54/20.35 2) f3#(I5, I6, I7, I8, I9) -> f6#(I5, I6, I7, I8, I9) [1 <= I9 /\ 1 <= I8] 20.54/20.35 3) f6#(I10, I11, I12, I13, I14) -> f5#(I10, I11, I12, -1 + I13, I14) 20.54/20.35 4) f6#(I15, I16, I17, I18, I19) -> f5#(I15, I16, I17, I18, -1 + I19) 20.54/20.35 5) f5#(I20, I21, I22, I23, I24) -> f1#(I20, I21, I22, I23, I24) [1 <= I20] 20.54/20.35 6) f5#(I25, I26, I27, I28, I29) -> f4#(I25, I26, I27, I28, I29) [I25 <= 0] 20.54/20.35 7) f4#(I30, I31, I32, I33, I34) -> f3#(1, I33, I34, I33, I34) 20.54/20.35 8) f4#(I35, I36, I37, I38, I39) -> f3#(I35, I36, I37, I38, I39) [I35 <= 0] 20.54/20.35 9) f1#(I40, I41, I42, I43, I44) -> f3#(I40, I41, I42, I43, I44) 20.54/20.35 20.54/20.35 We have the following SCCs. 20.54/20.35 { 2, 3, 4, 5, 6, 7, 8, 9 } 20.54/20.35 20.54/20.35 DP problem for innermost termination. 20.54/20.35 P = 20.54/20.35 f3#(I5, I6, I7, I8, I9) -> f6#(I5, I6, I7, I8, I9) [1 <= I9 /\ 1 <= I8] 20.54/20.35 f6#(I10, I11, I12, I13, I14) -> f5#(I10, I11, I12, -1 + I13, I14) 20.54/20.35 f6#(I15, I16, I17, I18, I19) -> f5#(I15, I16, I17, I18, -1 + I19) 20.54/20.35 f5#(I20, I21, I22, I23, I24) -> f1#(I20, I21, I22, I23, I24) [1 <= I20] 20.54/20.35 f5#(I25, I26, I27, I28, I29) -> f4#(I25, I26, I27, I28, I29) [I25 <= 0] 20.54/20.35 f4#(I30, I31, I32, I33, I34) -> f3#(1, I33, I34, I33, I34) 20.54/20.35 f4#(I35, I36, I37, I38, I39) -> f3#(I35, I36, I37, I38, I39) [I35 <= 0] 20.54/20.35 f1#(I40, I41, I42, I43, I44) -> f3#(I40, I41, I42, I43, I44) 20.54/20.35 R = 20.54/20.35 f8(x1, x2, x3, x4, x5) -> f7(x1, x2, x3, x4, x5) 20.54/20.35 f7(I0, I1, I2, I3, I4) -> f3(I0, I1, I2, I3, I4) [I0 <= 0] 20.54/20.35 f3(I5, I6, I7, I8, I9) -> f6(I5, I6, I7, I8, I9) [1 <= I9 /\ 1 <= I8] 20.54/20.35 f6(I10, I11, I12, I13, I14) -> f5(I10, I11, I12, -1 + I13, I14) 20.54/20.35 f6(I15, I16, I17, I18, I19) -> f5(I15, I16, I17, I18, -1 + I19) 20.54/20.35 f5(I20, I21, I22, I23, I24) -> f1(I20, I21, I22, I23, I24) [1 <= I20] 20.54/20.35 f5(I25, I26, I27, I28, I29) -> f4(I25, I26, I27, I28, I29) [I25 <= 0] 20.54/20.35 f4(I30, I31, I32, I33, I34) -> f3(1, I33, I34, I33, I34) 20.54/20.35 f4(I35, I36, I37, I38, I39) -> f3(I35, I36, I37, I38, I39) [I35 <= 0] 20.54/20.35 f1(I40, I41, I42, I43, I44) -> f3(I40, I41, I42, I43, I44) 20.54/20.35 f1(I45, I46, I47, I48, I49) -> f2(I45, I46, I47, I48, I49) [I47 <= I49 /\ I46 <= I48] 20.54/20.35 20.54/23.33 EOF