10.14/9.98	MAYBE
10.14/9.98	
10.14/9.98	DP problem for innermost termination.
10.14/9.98	P =
10.14/9.98	  f5#(x1, x2, x3, x4, x5, x6, x7, x8) -> f4#(x1, x2, x3, x4, x5, x6, x7, x8) 
10.14/9.98	  f4#(I0, I1, I2, I3, I4, I5, I6, I7) -> f1#(I0, I1, I2, I3, I4, rnd6, rnd7, rnd8) [rnd7 = rnd6 /\ rnd8 = rnd8 /\ rnd6 = rnd6]
10.14/9.98	  f3#(I8, I9, I10, I11, I12, I13, I14, I15) -> f1#(I8, I9, I10, I11, I12, I13, I14, I15) 
10.14/9.98	  f1#(I16, I17, I18, I19, I20, I21, I22, I23) -> f3#(I16, I17, rnd3, rnd4, rnd5, I21, I22, I23) [y3 = I23 /\ y1 = I17 /\ 0 <= -1 + y1 /\ rnd5 = rnd5 /\ rnd3 = rnd3 /\ y2 = I17 /\ rnd4 = rnd4]
10.14/9.98	R = 
10.14/9.98	  f5(x1, x2, x3, x4, x5, x6, x7, x8) -> f4(x1, x2, x3, x4, x5, x6, x7, x8) 
10.14/9.98	  f4(I0, I1, I2, I3, I4, I5, I6, I7) -> f1(I0, I1, I2, I3, I4, rnd6, rnd7, rnd8) [rnd7 = rnd6 /\ rnd8 = rnd8 /\ rnd6 = rnd6]
10.14/9.98	  f3(I8, I9, I10, I11, I12, I13, I14, I15) -> f1(I8, I9, I10, I11, I12, I13, I14, I15) 
10.14/9.98	  f1(I16, I17, I18, I19, I20, I21, I22, I23) -> f3(I16, I17, rnd3, rnd4, rnd5, I21, I22, I23) [y3 = I23 /\ y1 = I17 /\ 0 <= -1 + y1 /\ rnd5 = rnd5 /\ rnd3 = rnd3 /\ y2 = I17 /\ rnd4 = rnd4]
10.14/9.98	  f1(I24, I25, I26, I27, I28, I29, I30, I31) -> f2(rnd1, I25, I32, I27, I33, I29, I30, I31) [I34 = I31 /\ I35 = I25 /\ I35 <= 0 /\ I33 = I33 /\ I32 = I32 /\ rnd1 = rnd1]
10.14/9.98	
10.14/9.98	The dependency graph for this problem is:
10.14/9.98	  0 -> 1
10.14/9.98	  1 -> 3
10.14/9.98	  2 -> 3
10.14/9.98	  3 -> 2
10.14/9.98	Where:
10.14/9.98	  0) f5#(x1, x2, x3, x4, x5, x6, x7, x8) -> f4#(x1, x2, x3, x4, x5, x6, x7, x8) 
10.14/9.98	  1) f4#(I0, I1, I2, I3, I4, I5, I6, I7) -> f1#(I0, I1, I2, I3, I4, rnd6, rnd7, rnd8) [rnd7 = rnd6 /\ rnd8 = rnd8 /\ rnd6 = rnd6]
10.14/9.98	  2) f3#(I8, I9, I10, I11, I12, I13, I14, I15) -> f1#(I8, I9, I10, I11, I12, I13, I14, I15) 
10.14/9.98	  3) f1#(I16, I17, I18, I19, I20, I21, I22, I23) -> f3#(I16, I17, rnd3, rnd4, rnd5, I21, I22, I23) [y3 = I23 /\ y1 = I17 /\ 0 <= -1 + y1 /\ rnd5 = rnd5 /\ rnd3 = rnd3 /\ y2 = I17 /\ rnd4 = rnd4]
10.14/9.98	
10.14/9.98	We have the following SCCs.
10.14/9.98	  { 2, 3 }
10.14/9.98	
10.14/9.98	DP problem for innermost termination.
10.14/9.98	P =
10.14/9.98	  f3#(I8, I9, I10, I11, I12, I13, I14, I15) -> f1#(I8, I9, I10, I11, I12, I13, I14, I15) 
10.14/9.98	  f1#(I16, I17, I18, I19, I20, I21, I22, I23) -> f3#(I16, I17, rnd3, rnd4, rnd5, I21, I22, I23) [y3 = I23 /\ y1 = I17 /\ 0 <= -1 + y1 /\ rnd5 = rnd5 /\ rnd3 = rnd3 /\ y2 = I17 /\ rnd4 = rnd4]
10.14/9.98	R = 
10.14/9.98	  f5(x1, x2, x3, x4, x5, x6, x7, x8) -> f4(x1, x2, x3, x4, x5, x6, x7, x8) 
10.14/9.98	  f4(I0, I1, I2, I3, I4, I5, I6, I7) -> f1(I0, I1, I2, I3, I4, rnd6, rnd7, rnd8) [rnd7 = rnd6 /\ rnd8 = rnd8 /\ rnd6 = rnd6]
10.14/9.98	  f3(I8, I9, I10, I11, I12, I13, I14, I15) -> f1(I8, I9, I10, I11, I12, I13, I14, I15) 
10.14/9.98	  f1(I16, I17, I18, I19, I20, I21, I22, I23) -> f3(I16, I17, rnd3, rnd4, rnd5, I21, I22, I23) [y3 = I23 /\ y1 = I17 /\ 0 <= -1 + y1 /\ rnd5 = rnd5 /\ rnd3 = rnd3 /\ y2 = I17 /\ rnd4 = rnd4]
10.14/9.98	  f1(I24, I25, I26, I27, I28, I29, I30, I31) -> f2(rnd1, I25, I32, I27, I33, I29, I30, I31) [I34 = I31 /\ I35 = I25 /\ I35 <= 0 /\ I33 = I33 /\ I32 = I32 /\ rnd1 = rnd1]
10.14/9.98	
10.14/12.96	EOF