0.00/0.01	YES
0.00/0.01	
0.00/0.01	DP problem for innermost termination.
0.00/0.01	P =
0.00/0.01	  f5#(x1, x2, x3, x4, x5) -> f1#(x1, x2, x3, x4, x5) 
0.00/0.01	R = 
0.00/0.01	  f5(x1, x2, x3, x4, x5) -> f1(x1, x2, x3, x4, x5) 
0.00/0.01	  f3(I0, I1, I2, I3, I4) -> f4(I0, I1, I2, I3, I4) 
0.00/0.01	  f1(I5, I6, I7, I8, I9) -> f2(1, I7, I7, I7, 1) [0 <= -1 + I7 /\ 0 <= I7]
0.00/0.01	
0.00/0.01	The dependency graph for this problem is:
0.00/0.01	  0 -> 
0.00/0.01	Where:
0.00/0.01	  0) f5#(x1, x2, x3, x4, x5) -> f1#(x1, x2, x3, x4, x5) 
0.00/0.01	
0.00/0.01	We have the following SCCs.
0.00/0.01	  
0.00/0.01	EOF