36.40/35.87	YES
36.40/35.87	
36.40/35.87	DP problem for innermost termination.
36.40/35.87	P =
36.40/35.87	  f12#(x1, x2, x3, x4, x5, x6, x7) -> f11#(x1, x2, x3, x4, x5, x6, x7) 
36.40/35.87	  f11#(I0, I1, I2, I3, I4, I5, I6) -> f4#(0, I1, I2, I3, I4, I5, I6) 
36.40/35.87	  f3#(I7, I8, I9, I10, I11, I12, I13) -> f4#(1 + I7, I8, I9, I10, I11, I12, I13) [1 + I7 <= 10]
36.40/35.87	  f3#(I14, I15, I16, I17, I18, I19, I20) -> f2#(I14, I15, I16, I17, I18, I19, I20) [10 <= I14]
36.40/35.87	  f2#(I21, I22, I23, I24, I25, I26, I27) -> f8#(0, I22, I23, I24, I25, I26, I27) 
36.40/35.87	  f10#(I28, I29, I30, I31, I32, I33, I34) -> f9#(I28, I29, rnd3, I31, rnd5, I33, I28) [rnd5 = rnd3 /\ rnd3 = rnd3 /\ 1 + I28 <= 10]
36.40/35.87	  f10#(I35, I36, I37, I38, I39, I40, I41) -> f5#(I35, I36, I37, I38, I39, I40, I41) [10 <= I35]
36.40/35.87	  f8#(I42, I43, I44, I45, I46, I47, I48) -> f10#(I42, I43, I44, I45, I46, I47, I48) 
36.40/35.87	  f9#(I49, I50, I51, I52, I53, I54, I55) -> f7#(I49, I50, I51, I52, I53, I54, I55) [1 + I53 <= 0]
36.40/35.87	  f9#(I56, I57, I58, I59, I60, I61, I62) -> f7#(I56, I57, I58, I59, I60, I61, I62) [1 <= I60]
36.40/35.87	  f9#(I63, I64, I65, I66, I67, I68, I69) -> f5#(I63, I64, I65, I66, I67, I68, I69) [0 <= I67 /\ I67 <= 0]
36.40/35.87	  f7#(I70, I71, I72, I73, I74, I75, I76) -> f8#(1 + I70, I71, I72, I73, I74, I75, I76) 
36.40/35.87	  f4#(I84, I85, I86, I87, I88, I89, I90) -> f1#(I84, rnd2, I86, rnd4, I88, I84, I90) [rnd4 = rnd2 /\ rnd2 = rnd2]
36.40/35.87	  f1#(I91, I92, I93, I94, I95, I96, I97) -> f3#(I91, I92, I93, I94, I95, I96, I97) [1 + I94 <= 0]
36.40/35.87	  f1#(I98, I99, I100, I101, I102, I103, I104) -> f3#(I98, I99, I100, I101, I102, I103, I104) [1 <= I101]
36.40/35.87	  f1#(I105, I106, I107, I108, I109, I110, I111) -> f2#(I105, I106, I107, I108, I109, I110, I111) [0 <= I108 /\ I108 <= 0]
36.40/35.87	R = 
36.40/35.87	  f12(x1, x2, x3, x4, x5, x6, x7) -> f11(x1, x2, x3, x4, x5, x6, x7) 
36.40/35.87	  f11(I0, I1, I2, I3, I4, I5, I6) -> f4(0, I1, I2, I3, I4, I5, I6) 
36.40/35.87	  f3(I7, I8, I9, I10, I11, I12, I13) -> f4(1 + I7, I8, I9, I10, I11, I12, I13) [1 + I7 <= 10]
36.40/35.87	  f3(I14, I15, I16, I17, I18, I19, I20) -> f2(I14, I15, I16, I17, I18, I19, I20) [10 <= I14]
36.40/35.87	  f2(I21, I22, I23, I24, I25, I26, I27) -> f8(0, I22, I23, I24, I25, I26, I27) 
36.40/35.87	  f10(I28, I29, I30, I31, I32, I33, I34) -> f9(I28, I29, rnd3, I31, rnd5, I33, I28) [rnd5 = rnd3 /\ rnd3 = rnd3 /\ 1 + I28 <= 10]
36.40/35.87	  f10(I35, I36, I37, I38, I39, I40, I41) -> f5(I35, I36, I37, I38, I39, I40, I41) [10 <= I35]
36.40/35.87	  f8(I42, I43, I44, I45, I46, I47, I48) -> f10(I42, I43, I44, I45, I46, I47, I48) 
36.40/35.87	  f9(I49, I50, I51, I52, I53, I54, I55) -> f7(I49, I50, I51, I52, I53, I54, I55) [1 + I53 <= 0]
36.40/35.87	  f9(I56, I57, I58, I59, I60, I61, I62) -> f7(I56, I57, I58, I59, I60, I61, I62) [1 <= I60]
36.40/35.87	  f9(I63, I64, I65, I66, I67, I68, I69) -> f5(I63, I64, I65, I66, I67, I68, I69) [0 <= I67 /\ I67 <= 0]
36.40/35.87	  f7(I70, I71, I72, I73, I74, I75, I76) -> f8(1 + I70, I71, I72, I73, I74, I75, I76) 
36.40/35.87	  f5(I77, I78, I79, I80, I81, I82, I83) -> f6(I77, I78, I79, I80, I81, I82, I83) 
36.40/35.87	  f4(I84, I85, I86, I87, I88, I89, I90) -> f1(I84, rnd2, I86, rnd4, I88, I84, I90) [rnd4 = rnd2 /\ rnd2 = rnd2]
36.40/35.87	  f1(I91, I92, I93, I94, I95, I96, I97) -> f3(I91, I92, I93, I94, I95, I96, I97) [1 + I94 <= 0]
36.40/35.87	  f1(I98, I99, I100, I101, I102, I103, I104) -> f3(I98, I99, I100, I101, I102, I103, I104) [1 <= I101]
36.40/35.87	  f1(I105, I106, I107, I108, I109, I110, I111) -> f2(I105, I106, I107, I108, I109, I110, I111) [0 <= I108 /\ I108 <= 0]
36.40/35.87	
36.40/35.87	The dependency graph for this problem is:
36.40/35.87	  0 -> 1
36.40/35.87	  1 -> 12
36.40/35.87	  2 -> 12
36.40/35.87	  3 -> 4
36.40/35.87	  4 -> 7
36.40/35.87	  5 -> 8, 9, 10
36.40/35.87	  6 -> 
36.40/35.87	  7 -> 5, 6
36.40/35.87	  8 -> 11
36.40/35.87	  9 -> 11
36.40/35.87	  10 -> 
36.40/35.87	  11 -> 7
36.40/35.87	  12 -> 13, 14, 15
36.40/35.87	  13 -> 2, 3
36.40/35.87	  14 -> 2, 3
36.40/35.87	  15 -> 4
36.40/35.87	Where:
36.40/35.87	  0) f12#(x1, x2, x3, x4, x5, x6, x7) -> f11#(x1, x2, x3, x4, x5, x6, x7) 
36.40/35.87	  1) f11#(I0, I1, I2, I3, I4, I5, I6) -> f4#(0, I1, I2, I3, I4, I5, I6) 
36.40/35.87	  2) f3#(I7, I8, I9, I10, I11, I12, I13) -> f4#(1 + I7, I8, I9, I10, I11, I12, I13) [1 + I7 <= 10]
36.40/35.87	  3) f3#(I14, I15, I16, I17, I18, I19, I20) -> f2#(I14, I15, I16, I17, I18, I19, I20) [10 <= I14]
36.40/35.87	  4) f2#(I21, I22, I23, I24, I25, I26, I27) -> f8#(0, I22, I23, I24, I25, I26, I27) 
36.40/35.87	  5) f10#(I28, I29, I30, I31, I32, I33, I34) -> f9#(I28, I29, rnd3, I31, rnd5, I33, I28) [rnd5 = rnd3 /\ rnd3 = rnd3 /\ 1 + I28 <= 10]
36.40/35.87	  6) f10#(I35, I36, I37, I38, I39, I40, I41) -> f5#(I35, I36, I37, I38, I39, I40, I41) [10 <= I35]
36.40/35.87	  7) f8#(I42, I43, I44, I45, I46, I47, I48) -> f10#(I42, I43, I44, I45, I46, I47, I48) 
36.40/35.87	  8) f9#(I49, I50, I51, I52, I53, I54, I55) -> f7#(I49, I50, I51, I52, I53, I54, I55) [1 + I53 <= 0]
36.40/35.87	  9) f9#(I56, I57, I58, I59, I60, I61, I62) -> f7#(I56, I57, I58, I59, I60, I61, I62) [1 <= I60]
36.40/35.87	  10) f9#(I63, I64, I65, I66, I67, I68, I69) -> f5#(I63, I64, I65, I66, I67, I68, I69) [0 <= I67 /\ I67 <= 0]
36.40/35.87	  11) f7#(I70, I71, I72, I73, I74, I75, I76) -> f8#(1 + I70, I71, I72, I73, I74, I75, I76) 
36.40/35.87	  12) f4#(I84, I85, I86, I87, I88, I89, I90) -> f1#(I84, rnd2, I86, rnd4, I88, I84, I90) [rnd4 = rnd2 /\ rnd2 = rnd2]
36.40/35.87	  13) f1#(I91, I92, I93, I94, I95, I96, I97) -> f3#(I91, I92, I93, I94, I95, I96, I97) [1 + I94 <= 0]
36.40/35.87	  14) f1#(I98, I99, I100, I101, I102, I103, I104) -> f3#(I98, I99, I100, I101, I102, I103, I104) [1 <= I101]
36.40/35.87	  15) f1#(I105, I106, I107, I108, I109, I110, I111) -> f2#(I105, I106, I107, I108, I109, I110, I111) [0 <= I108 /\ I108 <= 0]
36.40/35.87	
36.40/35.87	We have the following SCCs.
36.40/35.87	  { 2, 12, 13, 14 }
36.40/35.87	  { 5, 7, 8, 9, 11 }
36.40/35.87	
36.40/35.87	DP problem for innermost termination.
36.40/35.87	P =
36.40/35.87	  f10#(I28, I29, I30, I31, I32, I33, I34) -> f9#(I28, I29, rnd3, I31, rnd5, I33, I28) [rnd5 = rnd3 /\ rnd3 = rnd3 /\ 1 + I28 <= 10]
36.40/35.87	  f8#(I42, I43, I44, I45, I46, I47, I48) -> f10#(I42, I43, I44, I45, I46, I47, I48) 
36.40/35.87	  f9#(I49, I50, I51, I52, I53, I54, I55) -> f7#(I49, I50, I51, I52, I53, I54, I55) [1 + I53 <= 0]
36.40/35.87	  f9#(I56, I57, I58, I59, I60, I61, I62) -> f7#(I56, I57, I58, I59, I60, I61, I62) [1 <= I60]
36.40/35.87	  f7#(I70, I71, I72, I73, I74, I75, I76) -> f8#(1 + I70, I71, I72, I73, I74, I75, I76) 
36.40/35.87	R = 
36.40/35.87	  f12(x1, x2, x3, x4, x5, x6, x7) -> f11(x1, x2, x3, x4, x5, x6, x7) 
36.40/35.87	  f11(I0, I1, I2, I3, I4, I5, I6) -> f4(0, I1, I2, I3, I4, I5, I6) 
36.40/35.87	  f3(I7, I8, I9, I10, I11, I12, I13) -> f4(1 + I7, I8, I9, I10, I11, I12, I13) [1 + I7 <= 10]
36.40/35.87	  f3(I14, I15, I16, I17, I18, I19, I20) -> f2(I14, I15, I16, I17, I18, I19, I20) [10 <= I14]
36.40/35.87	  f2(I21, I22, I23, I24, I25, I26, I27) -> f8(0, I22, I23, I24, I25, I26, I27) 
36.40/35.87	  f10(I28, I29, I30, I31, I32, I33, I34) -> f9(I28, I29, rnd3, I31, rnd5, I33, I28) [rnd5 = rnd3 /\ rnd3 = rnd3 /\ 1 + I28 <= 10]
36.40/35.87	  f10(I35, I36, I37, I38, I39, I40, I41) -> f5(I35, I36, I37, I38, I39, I40, I41) [10 <= I35]
36.40/35.87	  f8(I42, I43, I44, I45, I46, I47, I48) -> f10(I42, I43, I44, I45, I46, I47, I48) 
36.40/35.87	  f9(I49, I50, I51, I52, I53, I54, I55) -> f7(I49, I50, I51, I52, I53, I54, I55) [1 + I53 <= 0]
36.40/35.87	  f9(I56, I57, I58, I59, I60, I61, I62) -> f7(I56, I57, I58, I59, I60, I61, I62) [1 <= I60]
36.40/35.87	  f9(I63, I64, I65, I66, I67, I68, I69) -> f5(I63, I64, I65, I66, I67, I68, I69) [0 <= I67 /\ I67 <= 0]
36.40/35.87	  f7(I70, I71, I72, I73, I74, I75, I76) -> f8(1 + I70, I71, I72, I73, I74, I75, I76) 
36.40/35.87	  f5(I77, I78, I79, I80, I81, I82, I83) -> f6(I77, I78, I79, I80, I81, I82, I83) 
36.40/35.87	  f4(I84, I85, I86, I87, I88, I89, I90) -> f1(I84, rnd2, I86, rnd4, I88, I84, I90) [rnd4 = rnd2 /\ rnd2 = rnd2]
36.40/35.87	  f1(I91, I92, I93, I94, I95, I96, I97) -> f3(I91, I92, I93, I94, I95, I96, I97) [1 + I94 <= 0]
36.40/35.87	  f1(I98, I99, I100, I101, I102, I103, I104) -> f3(I98, I99, I100, I101, I102, I103, I104) [1 <= I101]
36.40/35.87	  f1(I105, I106, I107, I108, I109, I110, I111) -> f2(I105, I106, I107, I108, I109, I110, I111) [0 <= I108 /\ I108 <= 0]
36.40/35.87	
36.40/35.87	We use the extended value criterion with the projection function NU:
36.40/35.87	  NU[f7#(x0,x1,x2,x3,x4,x5,x6)] = -x0 + 8
36.40/35.87	  NU[f8#(x0,x1,x2,x3,x4,x5,x6)] = -x0 + 9
36.40/35.87	  NU[f9#(x0,x1,x2,x3,x4,x5,x6)] = -x0 + 8
36.40/35.87	  NU[f10#(x0,x1,x2,x3,x4,x5,x6)] = -x0 + 9
36.40/35.87	
36.40/35.87	This gives the following inequalities:
36.40/35.87	  rnd5 = rnd3 /\ rnd3 = rnd3 /\ 1 + I28 <= 10  ==>  -I28 + 9 > -I28 + 8  with  -I28 + 9 >= 0
36.40/35.87	    ==>  -I42 + 9 >= -I42 + 9
36.40/35.87	  1 + I53 <= 0  ==>  -I49 + 8 >= -I49 + 8
36.40/35.87	  1 <= I60  ==>  -I56 + 8 >= -I56 + 8
36.40/35.87	    ==>  -I70 + 8 >= -(1 + I70) + 9
36.40/35.87	
36.40/35.87	We remove all the strictly oriented dependency pairs.
36.40/35.87	
36.40/35.87	DP problem for innermost termination.
36.40/35.87	P =
36.40/35.87	  f8#(I42, I43, I44, I45, I46, I47, I48) -> f10#(I42, I43, I44, I45, I46, I47, I48) 
36.40/35.87	  f9#(I49, I50, I51, I52, I53, I54, I55) -> f7#(I49, I50, I51, I52, I53, I54, I55) [1 + I53 <= 0]
36.40/35.87	  f9#(I56, I57, I58, I59, I60, I61, I62) -> f7#(I56, I57, I58, I59, I60, I61, I62) [1 <= I60]
36.40/35.87	  f7#(I70, I71, I72, I73, I74, I75, I76) -> f8#(1 + I70, I71, I72, I73, I74, I75, I76) 
36.40/35.87	R = 
36.40/35.87	  f12(x1, x2, x3, x4, x5, x6, x7) -> f11(x1, x2, x3, x4, x5, x6, x7) 
36.40/35.87	  f11(I0, I1, I2, I3, I4, I5, I6) -> f4(0, I1, I2, I3, I4, I5, I6) 
36.40/35.87	  f3(I7, I8, I9, I10, I11, I12, I13) -> f4(1 + I7, I8, I9, I10, I11, I12, I13) [1 + I7 <= 10]
36.40/35.87	  f3(I14, I15, I16, I17, I18, I19, I20) -> f2(I14, I15, I16, I17, I18, I19, I20) [10 <= I14]
36.40/35.87	  f2(I21, I22, I23, I24, I25, I26, I27) -> f8(0, I22, I23, I24, I25, I26, I27) 
36.40/35.87	  f10(I28, I29, I30, I31, I32, I33, I34) -> f9(I28, I29, rnd3, I31, rnd5, I33, I28) [rnd5 = rnd3 /\ rnd3 = rnd3 /\ 1 + I28 <= 10]
36.40/35.87	  f10(I35, I36, I37, I38, I39, I40, I41) -> f5(I35, I36, I37, I38, I39, I40, I41) [10 <= I35]
36.40/35.87	  f8(I42, I43, I44, I45, I46, I47, I48) -> f10(I42, I43, I44, I45, I46, I47, I48) 
36.40/35.87	  f9(I49, I50, I51, I52, I53, I54, I55) -> f7(I49, I50, I51, I52, I53, I54, I55) [1 + I53 <= 0]
36.40/35.87	  f9(I56, I57, I58, I59, I60, I61, I62) -> f7(I56, I57, I58, I59, I60, I61, I62) [1 <= I60]
36.40/35.87	  f9(I63, I64, I65, I66, I67, I68, I69) -> f5(I63, I64, I65, I66, I67, I68, I69) [0 <= I67 /\ I67 <= 0]
36.40/35.87	  f7(I70, I71, I72, I73, I74, I75, I76) -> f8(1 + I70, I71, I72, I73, I74, I75, I76) 
36.40/35.87	  f5(I77, I78, I79, I80, I81, I82, I83) -> f6(I77, I78, I79, I80, I81, I82, I83) 
36.40/35.87	  f4(I84, I85, I86, I87, I88, I89, I90) -> f1(I84, rnd2, I86, rnd4, I88, I84, I90) [rnd4 = rnd2 /\ rnd2 = rnd2]
36.40/35.87	  f1(I91, I92, I93, I94, I95, I96, I97) -> f3(I91, I92, I93, I94, I95, I96, I97) [1 + I94 <= 0]
36.40/35.87	  f1(I98, I99, I100, I101, I102, I103, I104) -> f3(I98, I99, I100, I101, I102, I103, I104) [1 <= I101]
36.40/35.87	  f1(I105, I106, I107, I108, I109, I110, I111) -> f2(I105, I106, I107, I108, I109, I110, I111) [0 <= I108 /\ I108 <= 0]
36.40/35.87	
36.40/35.87	The dependency graph for this problem is:
36.40/35.87	  7 -> 
36.40/35.87	  8 -> 11
36.40/35.87	  9 -> 11
36.40/35.87	  11 -> 7
36.40/35.87	Where:
36.40/35.87	  7) f8#(I42, I43, I44, I45, I46, I47, I48) -> f10#(I42, I43, I44, I45, I46, I47, I48) 
36.40/35.87	  8) f9#(I49, I50, I51, I52, I53, I54, I55) -> f7#(I49, I50, I51, I52, I53, I54, I55) [1 + I53 <= 0]
36.40/35.87	  9) f9#(I56, I57, I58, I59, I60, I61, I62) -> f7#(I56, I57, I58, I59, I60, I61, I62) [1 <= I60]
36.40/35.87	  11) f7#(I70, I71, I72, I73, I74, I75, I76) -> f8#(1 + I70, I71, I72, I73, I74, I75, I76) 
36.40/35.87	
36.40/35.87	We have the following SCCs.
36.40/35.87	  
36.40/35.87	
36.40/35.87	DP problem for innermost termination.
36.40/35.87	P =
36.40/35.87	  f3#(I7, I8, I9, I10, I11, I12, I13) -> f4#(1 + I7, I8, I9, I10, I11, I12, I13) [1 + I7 <= 10]
36.40/35.87	  f4#(I84, I85, I86, I87, I88, I89, I90) -> f1#(I84, rnd2, I86, rnd4, I88, I84, I90) [rnd4 = rnd2 /\ rnd2 = rnd2]
36.40/35.87	  f1#(I91, I92, I93, I94, I95, I96, I97) -> f3#(I91, I92, I93, I94, I95, I96, I97) [1 + I94 <= 0]
36.40/35.87	  f1#(I98, I99, I100, I101, I102, I103, I104) -> f3#(I98, I99, I100, I101, I102, I103, I104) [1 <= I101]
36.40/35.87	R = 
36.40/35.87	  f12(x1, x2, x3, x4, x5, x6, x7) -> f11(x1, x2, x3, x4, x5, x6, x7) 
36.40/35.87	  f11(I0, I1, I2, I3, I4, I5, I6) -> f4(0, I1, I2, I3, I4, I5, I6) 
36.40/35.87	  f3(I7, I8, I9, I10, I11, I12, I13) -> f4(1 + I7, I8, I9, I10, I11, I12, I13) [1 + I7 <= 10]
36.40/35.87	  f3(I14, I15, I16, I17, I18, I19, I20) -> f2(I14, I15, I16, I17, I18, I19, I20) [10 <= I14]
36.40/35.87	  f2(I21, I22, I23, I24, I25, I26, I27) -> f8(0, I22, I23, I24, I25, I26, I27) 
36.40/35.87	  f10(I28, I29, I30, I31, I32, I33, I34) -> f9(I28, I29, rnd3, I31, rnd5, I33, I28) [rnd5 = rnd3 /\ rnd3 = rnd3 /\ 1 + I28 <= 10]
36.40/35.87	  f10(I35, I36, I37, I38, I39, I40, I41) -> f5(I35, I36, I37, I38, I39, I40, I41) [10 <= I35]
36.40/35.87	  f8(I42, I43, I44, I45, I46, I47, I48) -> f10(I42, I43, I44, I45, I46, I47, I48) 
36.40/35.87	  f9(I49, I50, I51, I52, I53, I54, I55) -> f7(I49, I50, I51, I52, I53, I54, I55) [1 + I53 <= 0]
36.40/35.87	  f9(I56, I57, I58, I59, I60, I61, I62) -> f7(I56, I57, I58, I59, I60, I61, I62) [1 <= I60]
36.40/35.87	  f9(I63, I64, I65, I66, I67, I68, I69) -> f5(I63, I64, I65, I66, I67, I68, I69) [0 <= I67 /\ I67 <= 0]
36.40/35.87	  f7(I70, I71, I72, I73, I74, I75, I76) -> f8(1 + I70, I71, I72, I73, I74, I75, I76) 
36.40/35.87	  f5(I77, I78, I79, I80, I81, I82, I83) -> f6(I77, I78, I79, I80, I81, I82, I83) 
36.40/35.87	  f4(I84, I85, I86, I87, I88, I89, I90) -> f1(I84, rnd2, I86, rnd4, I88, I84, I90) [rnd4 = rnd2 /\ rnd2 = rnd2]
36.40/35.87	  f1(I91, I92, I93, I94, I95, I96, I97) -> f3(I91, I92, I93, I94, I95, I96, I97) [1 + I94 <= 0]
36.40/35.87	  f1(I98, I99, I100, I101, I102, I103, I104) -> f3(I98, I99, I100, I101, I102, I103, I104) [1 <= I101]
36.40/35.87	  f1(I105, I106, I107, I108, I109, I110, I111) -> f2(I105, I106, I107, I108, I109, I110, I111) [0 <= I108 /\ I108 <= 0]
36.40/35.87	
36.40/35.87	We use the extended value criterion with the projection function NU:
36.40/35.87	  NU[f1#(x0,x1,x2,x3,x4,x5,x6)] = -x0 + 9
36.40/35.87	  NU[f4#(x0,x1,x2,x3,x4,x5,x6)] = -x0 + 9
36.40/35.87	  NU[f3#(x0,x1,x2,x3,x4,x5,x6)] = -x0 + 9
36.40/35.87	
36.40/35.87	This gives the following inequalities:
36.40/35.87	  1 + I7 <= 10  ==>  -I7 + 9 > -(1 + I7) + 9  with  -I7 + 9 >= 0
36.40/35.87	  rnd4 = rnd2 /\ rnd2 = rnd2  ==>  -I84 + 9 >= -I84 + 9
36.40/35.87	  1 + I94 <= 0  ==>  -I91 + 9 >= -I91 + 9
36.40/35.87	  1 <= I101  ==>  -I98 + 9 >= -I98 + 9
36.40/35.87	
36.40/35.87	We remove all the strictly oriented dependency pairs.
36.40/35.87	
36.40/35.87	DP problem for innermost termination.
36.40/35.87	P =
36.40/35.87	  f4#(I84, I85, I86, I87, I88, I89, I90) -> f1#(I84, rnd2, I86, rnd4, I88, I84, I90) [rnd4 = rnd2 /\ rnd2 = rnd2]
36.40/35.87	  f1#(I91, I92, I93, I94, I95, I96, I97) -> f3#(I91, I92, I93, I94, I95, I96, I97) [1 + I94 <= 0]
36.40/35.87	  f1#(I98, I99, I100, I101, I102, I103, I104) -> f3#(I98, I99, I100, I101, I102, I103, I104) [1 <= I101]
36.40/35.87	R = 
36.40/35.87	  f12(x1, x2, x3, x4, x5, x6, x7) -> f11(x1, x2, x3, x4, x5, x6, x7) 
36.40/35.87	  f11(I0, I1, I2, I3, I4, I5, I6) -> f4(0, I1, I2, I3, I4, I5, I6) 
36.40/35.87	  f3(I7, I8, I9, I10, I11, I12, I13) -> f4(1 + I7, I8, I9, I10, I11, I12, I13) [1 + I7 <= 10]
36.40/35.87	  f3(I14, I15, I16, I17, I18, I19, I20) -> f2(I14, I15, I16, I17, I18, I19, I20) [10 <= I14]
36.40/35.87	  f2(I21, I22, I23, I24, I25, I26, I27) -> f8(0, I22, I23, I24, I25, I26, I27) 
36.40/35.87	  f10(I28, I29, I30, I31, I32, I33, I34) -> f9(I28, I29, rnd3, I31, rnd5, I33, I28) [rnd5 = rnd3 /\ rnd3 = rnd3 /\ 1 + I28 <= 10]
36.40/35.87	  f10(I35, I36, I37, I38, I39, I40, I41) -> f5(I35, I36, I37, I38, I39, I40, I41) [10 <= I35]
36.40/35.87	  f8(I42, I43, I44, I45, I46, I47, I48) -> f10(I42, I43, I44, I45, I46, I47, I48) 
36.40/35.87	  f9(I49, I50, I51, I52, I53, I54, I55) -> f7(I49, I50, I51, I52, I53, I54, I55) [1 + I53 <= 0]
36.40/35.87	  f9(I56, I57, I58, I59, I60, I61, I62) -> f7(I56, I57, I58, I59, I60, I61, I62) [1 <= I60]
36.40/35.87	  f9(I63, I64, I65, I66, I67, I68, I69) -> f5(I63, I64, I65, I66, I67, I68, I69) [0 <= I67 /\ I67 <= 0]
36.40/35.87	  f7(I70, I71, I72, I73, I74, I75, I76) -> f8(1 + I70, I71, I72, I73, I74, I75, I76) 
36.40/35.87	  f5(I77, I78, I79, I80, I81, I82, I83) -> f6(I77, I78, I79, I80, I81, I82, I83) 
36.40/35.87	  f4(I84, I85, I86, I87, I88, I89, I90) -> f1(I84, rnd2, I86, rnd4, I88, I84, I90) [rnd4 = rnd2 /\ rnd2 = rnd2]
36.40/35.87	  f1(I91, I92, I93, I94, I95, I96, I97) -> f3(I91, I92, I93, I94, I95, I96, I97) [1 + I94 <= 0]
36.40/35.87	  f1(I98, I99, I100, I101, I102, I103, I104) -> f3(I98, I99, I100, I101, I102, I103, I104) [1 <= I101]
36.40/35.87	  f1(I105, I106, I107, I108, I109, I110, I111) -> f2(I105, I106, I107, I108, I109, I110, I111) [0 <= I108 /\ I108 <= 0]
36.40/35.87	
36.40/35.87	The dependency graph for this problem is:
36.40/35.87	  12 -> 13, 14
36.40/35.87	  13 -> 
36.40/35.87	  14 -> 
36.40/35.87	Where:
36.40/35.87	  12) f4#(I84, I85, I86, I87, I88, I89, I90) -> f1#(I84, rnd2, I86, rnd4, I88, I84, I90) [rnd4 = rnd2 /\ rnd2 = rnd2]
36.40/35.87	  13) f1#(I91, I92, I93, I94, I95, I96, I97) -> f3#(I91, I92, I93, I94, I95, I96, I97) [1 + I94 <= 0]
36.40/35.87	  14) f1#(I98, I99, I100, I101, I102, I103, I104) -> f3#(I98, I99, I100, I101, I102, I103, I104) [1 <= I101]
36.40/35.87	
36.40/35.87	We have the following SCCs.
36.40/35.87	  
36.40/38.84	EOF