13.77/13.57	MAYBE
13.77/13.57	
13.77/13.57	DP problem for innermost termination.
13.77/13.57	P =
13.77/13.57	  f15#(x1, x2, x3) -> f14#(x1, x2, x3) 
13.77/13.57	  f14#(I0, I1, I2) -> f4#(rnd1, I1, I2) [y1 = y1 /\ rnd1 = rnd1]
13.77/13.57	  f3#(I3, I4, I5) -> f13#(I3, I4, I5) [1 + I5 <= 0]
13.77/13.57	  f3#(I6, I7, I8) -> f13#(I6, I7, I8) [1 <= I8]
13.77/13.57	  f3#(I9, I10, I11) -> f2#(I9, I10, I11) [0 <= I11 /\ I11 <= 0]
13.77/13.57	  f13#(I12, I13, I14) -> f5#(1 + I12, I13, I14) [I12 <= I13]
13.77/13.57	  f13#(I15, I16, I17) -> f5#(1 + I15, I16, I17) [1 + I16 <= I15]
13.77/13.57	  f2#(I18, I19, I20) -> f6#(I18, I19, I20) 
13.77/13.57	  f12#(I21, I22, I23) -> f11#(I21, I22, I23) 
13.77/13.57	  f11#(I24, I25, I26) -> f12#(I24, I25, I26) 
13.77/13.57	  f7#(I27, I28, I29) -> f6#(-1 + I27, I28, I29) [3 <= I27]
13.77/13.57	  f7#(I30, I31, I32) -> f4#(I30, I31, I32) [I30 <= 2]
13.77/13.57	  f10#(I33, I34, I35) -> f11#(I33, I34, I35) 
13.77/13.57	  f6#(I39, I40, I41) -> f7#(I39, I40, I41) 
13.77/13.57	  f5#(I42, I43, I44) -> f1#(I42, I43, I44) 
13.77/13.57	  f4#(I45, I46, I47) -> f5#(I45, I46, I47) 
13.77/13.57	  f1#(I48, I49, I50) -> f3#(I48, I49, rnd3) [rnd3 = rnd3 /\ I48 <= I49]
13.77/13.57	  f1#(I51, I52, I53) -> f2#(I51, I52, I53) [1 + I52 <= I51]
13.77/13.57	R = 
13.77/13.57	  f15(x1, x2, x3) -> f14(x1, x2, x3) 
13.77/13.57	  f14(I0, I1, I2) -> f4(rnd1, I1, I2) [y1 = y1 /\ rnd1 = rnd1]
13.77/13.57	  f3(I3, I4, I5) -> f13(I3, I4, I5) [1 + I5 <= 0]
13.77/13.57	  f3(I6, I7, I8) -> f13(I6, I7, I8) [1 <= I8]
13.77/13.57	  f3(I9, I10, I11) -> f2(I9, I10, I11) [0 <= I11 /\ I11 <= 0]
13.77/13.57	  f13(I12, I13, I14) -> f5(1 + I12, I13, I14) [I12 <= I13]
13.77/13.57	  f13(I15, I16, I17) -> f5(1 + I15, I16, I17) [1 + I16 <= I15]
13.77/13.57	  f2(I18, I19, I20) -> f6(I18, I19, I20) 
13.77/13.57	  f12(I21, I22, I23) -> f11(I21, I22, I23) 
13.77/13.57	  f11(I24, I25, I26) -> f12(I24, I25, I26) 
13.77/13.57	  f7(I27, I28, I29) -> f6(-1 + I27, I28, I29) [3 <= I27]
13.77/13.57	  f7(I30, I31, I32) -> f4(I30, I31, I32) [I30 <= 2]
13.77/13.57	  f10(I33, I34, I35) -> f11(I33, I34, I35) 
13.77/13.57	  f8(I36, I37, I38) -> f9(I36, I37, I38) 
13.77/13.57	  f6(I39, I40, I41) -> f7(I39, I40, I41) 
13.77/13.57	  f5(I42, I43, I44) -> f1(I42, I43, I44) 
13.77/13.57	  f4(I45, I46, I47) -> f5(I45, I46, I47) 
13.77/13.57	  f1(I48, I49, I50) -> f3(I48, I49, rnd3) [rnd3 = rnd3 /\ I48 <= I49]
13.77/13.57	  f1(I51, I52, I53) -> f2(I51, I52, I53) [1 + I52 <= I51]
13.77/13.57	
13.77/13.57	The dependency graph for this problem is:
13.77/13.57	  0 -> 1
13.77/13.57	  1 -> 15
13.77/13.57	  2 -> 5, 6
13.77/13.57	  3 -> 5, 6
13.77/13.57	  4 -> 7
13.77/13.57	  5 -> 14
13.77/13.57	  6 -> 14
13.77/13.57	  7 -> 13
13.77/13.57	  8 -> 9
13.77/13.57	  9 -> 8
13.77/13.57	  10 -> 13
13.77/13.57	  11 -> 15
13.77/13.57	  12 -> 9
13.77/13.57	  13 -> 10, 11
13.77/13.57	  14 -> 16, 17
13.77/13.57	  15 -> 14
13.77/13.57	  16 -> 2, 3, 4
13.77/13.57	  17 -> 7
13.77/13.57	Where:
13.77/13.57	  0) f15#(x1, x2, x3) -> f14#(x1, x2, x3) 
13.77/13.57	  1) f14#(I0, I1, I2) -> f4#(rnd1, I1, I2) [y1 = y1 /\ rnd1 = rnd1]
13.77/13.57	  2) f3#(I3, I4, I5) -> f13#(I3, I4, I5) [1 + I5 <= 0]
13.77/13.57	  3) f3#(I6, I7, I8) -> f13#(I6, I7, I8) [1 <= I8]
13.77/13.57	  4) f3#(I9, I10, I11) -> f2#(I9, I10, I11) [0 <= I11 /\ I11 <= 0]
13.77/13.57	  5) f13#(I12, I13, I14) -> f5#(1 + I12, I13, I14) [I12 <= I13]
13.77/13.57	  6) f13#(I15, I16, I17) -> f5#(1 + I15, I16, I17) [1 + I16 <= I15]
13.77/13.57	  7) f2#(I18, I19, I20) -> f6#(I18, I19, I20) 
13.77/13.57	  8) f12#(I21, I22, I23) -> f11#(I21, I22, I23) 
13.77/13.57	  9) f11#(I24, I25, I26) -> f12#(I24, I25, I26) 
13.77/13.57	  10) f7#(I27, I28, I29) -> f6#(-1 + I27, I28, I29) [3 <= I27]
13.77/13.57	  11) f7#(I30, I31, I32) -> f4#(I30, I31, I32) [I30 <= 2]
13.77/13.57	  12) f10#(I33, I34, I35) -> f11#(I33, I34, I35) 
13.77/13.57	  13) f6#(I39, I40, I41) -> f7#(I39, I40, I41) 
13.77/13.57	  14) f5#(I42, I43, I44) -> f1#(I42, I43, I44) 
13.77/13.57	  15) f4#(I45, I46, I47) -> f5#(I45, I46, I47) 
13.77/13.57	  16) f1#(I48, I49, I50) -> f3#(I48, I49, rnd3) [rnd3 = rnd3 /\ I48 <= I49]
13.77/13.57	  17) f1#(I51, I52, I53) -> f2#(I51, I52, I53) [1 + I52 <= I51]
13.77/13.57	
13.77/13.57	We have the following SCCs.
13.77/13.57	  { 8, 9 }
13.77/13.57	  { 2, 3, 4, 5, 6, 7, 10, 11, 13, 14, 15, 16, 17 }
13.77/13.57	
13.77/13.57	DP problem for innermost termination.
13.77/13.57	P =
13.77/13.57	  f3#(I3, I4, I5) -> f13#(I3, I4, I5) [1 + I5 <= 0]
13.77/13.57	  f3#(I6, I7, I8) -> f13#(I6, I7, I8) [1 <= I8]
13.77/13.57	  f3#(I9, I10, I11) -> f2#(I9, I10, I11) [0 <= I11 /\ I11 <= 0]
13.77/13.57	  f13#(I12, I13, I14) -> f5#(1 + I12, I13, I14) [I12 <= I13]
13.77/13.57	  f13#(I15, I16, I17) -> f5#(1 + I15, I16, I17) [1 + I16 <= I15]
13.77/13.57	  f2#(I18, I19, I20) -> f6#(I18, I19, I20) 
13.77/13.57	  f7#(I27, I28, I29) -> f6#(-1 + I27, I28, I29) [3 <= I27]
13.77/13.57	  f7#(I30, I31, I32) -> f4#(I30, I31, I32) [I30 <= 2]
13.77/13.57	  f6#(I39, I40, I41) -> f7#(I39, I40, I41) 
13.77/13.57	  f5#(I42, I43, I44) -> f1#(I42, I43, I44) 
13.77/13.57	  f4#(I45, I46, I47) -> f5#(I45, I46, I47) 
13.77/13.57	  f1#(I48, I49, I50) -> f3#(I48, I49, rnd3) [rnd3 = rnd3 /\ I48 <= I49]
13.77/13.57	  f1#(I51, I52, I53) -> f2#(I51, I52, I53) [1 + I52 <= I51]
13.77/13.57	R = 
13.77/13.57	  f15(x1, x2, x3) -> f14(x1, x2, x3) 
13.77/13.57	  f14(I0, I1, I2) -> f4(rnd1, I1, I2) [y1 = y1 /\ rnd1 = rnd1]
13.77/13.57	  f3(I3, I4, I5) -> f13(I3, I4, I5) [1 + I5 <= 0]
13.77/13.57	  f3(I6, I7, I8) -> f13(I6, I7, I8) [1 <= I8]
13.77/13.57	  f3(I9, I10, I11) -> f2(I9, I10, I11) [0 <= I11 /\ I11 <= 0]
13.77/13.57	  f13(I12, I13, I14) -> f5(1 + I12, I13, I14) [I12 <= I13]
13.77/13.57	  f13(I15, I16, I17) -> f5(1 + I15, I16, I17) [1 + I16 <= I15]
13.77/13.57	  f2(I18, I19, I20) -> f6(I18, I19, I20) 
13.77/13.57	  f12(I21, I22, I23) -> f11(I21, I22, I23) 
13.77/13.57	  f11(I24, I25, I26) -> f12(I24, I25, I26) 
13.77/13.57	  f7(I27, I28, I29) -> f6(-1 + I27, I28, I29) [3 <= I27]
13.77/13.57	  f7(I30, I31, I32) -> f4(I30, I31, I32) [I30 <= 2]
13.77/13.57	  f10(I33, I34, I35) -> f11(I33, I34, I35) 
13.77/13.57	  f8(I36, I37, I38) -> f9(I36, I37, I38) 
13.77/13.57	  f6(I39, I40, I41) -> f7(I39, I40, I41) 
13.77/13.57	  f5(I42, I43, I44) -> f1(I42, I43, I44) 
13.77/13.57	  f4(I45, I46, I47) -> f5(I45, I46, I47) 
13.77/13.57	  f1(I48, I49, I50) -> f3(I48, I49, rnd3) [rnd3 = rnd3 /\ I48 <= I49]
13.77/13.57	  f1(I51, I52, I53) -> f2(I51, I52, I53) [1 + I52 <= I51]
13.77/13.57	
13.77/16.54	EOF