8.50/8.41	MAYBE
8.50/8.41	
8.50/8.41	DP problem for innermost termination.
8.50/8.41	P =
8.50/8.41	  f14#(x1, x2) -> f13#(x1, x2) 
8.50/8.41	  f13#(I0, I1) -> f4#(rnd1, I1) [y1 = y1 /\ rnd1 = rnd1]
8.50/8.41	  f3#(I2, I3) -> f5#(1 + I2, I3) [I2 <= 5]
8.50/8.41	  f3#(I4, I5) -> f5#(1 + I4, I5) [6 <= I4]
8.50/8.41	  f2#(I6, I7) -> f3#(I6, I7) [1 + I7 <= 0]
8.50/8.41	  f2#(I8, I9) -> f3#(I8, I9) [1 <= I9]
8.50/8.41	  f2#(I10, I11) -> f6#(I10, I11) [0 <= I11 /\ I11 <= 0]
8.50/8.41	  f7#(I12, I13) -> f6#(-1 + I12, I13) [3 <= I12]
8.50/8.41	  f7#(I14, I15) -> f4#(I14, I15) [I14 <= 2]
8.50/8.41	  f12#(I16, I17) -> f11#(I16, I17) 
8.50/8.41	  f11#(I18, I19) -> f12#(I18, I19) 
8.50/8.41	  f10#(I20, I21) -> f11#(I20, I21) 
8.50/8.41	  f6#(I24, I25) -> f7#(I24, I25) 
8.50/8.41	  f5#(I26, I27) -> f1#(I26, I27) 
8.50/8.41	  f4#(I28, I29) -> f5#(I28, I29) 
8.50/8.41	  f1#(I30, I31) -> f3#(I30, I31) [I30 <= 5]
8.50/8.41	  f1#(I32, I33) -> f2#(I32, rnd2) [rnd2 = rnd2 /\ 6 <= I32]
8.50/8.41	R = 
8.50/8.41	  f14(x1, x2) -> f13(x1, x2) 
8.50/8.41	  f13(I0, I1) -> f4(rnd1, I1) [y1 = y1 /\ rnd1 = rnd1]
8.50/8.41	  f3(I2, I3) -> f5(1 + I2, I3) [I2 <= 5]
8.50/8.41	  f3(I4, I5) -> f5(1 + I4, I5) [6 <= I4]
8.50/8.41	  f2(I6, I7) -> f3(I6, I7) [1 + I7 <= 0]
8.50/8.41	  f2(I8, I9) -> f3(I8, I9) [1 <= I9]
8.50/8.41	  f2(I10, I11) -> f6(I10, I11) [0 <= I11 /\ I11 <= 0]
8.50/8.41	  f7(I12, I13) -> f6(-1 + I12, I13) [3 <= I12]
8.50/8.41	  f7(I14, I15) -> f4(I14, I15) [I14 <= 2]
8.50/8.41	  f12(I16, I17) -> f11(I16, I17) 
8.50/8.41	  f11(I18, I19) -> f12(I18, I19) 
8.50/8.41	  f10(I20, I21) -> f11(I20, I21) 
8.50/8.41	  f8(I22, I23) -> f9(I22, I23) 
8.50/8.41	  f6(I24, I25) -> f7(I24, I25) 
8.50/8.41	  f5(I26, I27) -> f1(I26, I27) 
8.50/8.41	  f4(I28, I29) -> f5(I28, I29) 
8.50/8.41	  f1(I30, I31) -> f3(I30, I31) [I30 <= 5]
8.50/8.41	  f1(I32, I33) -> f2(I32, rnd2) [rnd2 = rnd2 /\ 6 <= I32]
8.50/8.41	
8.50/8.41	The dependency graph for this problem is:
8.50/8.41	  0 -> 1
8.50/8.41	  1 -> 14
8.50/8.41	  2 -> 13
8.50/8.41	  3 -> 13
8.50/8.41	  4 -> 2, 3
8.50/8.41	  5 -> 2, 3
8.50/8.41	  6 -> 12
8.50/8.41	  7 -> 12
8.50/8.41	  8 -> 14
8.50/8.41	  9 -> 10
8.50/8.41	  10 -> 9
8.50/8.41	  11 -> 10
8.50/8.41	  12 -> 7, 8
8.50/8.41	  13 -> 15, 16
8.50/8.41	  14 -> 13
8.50/8.41	  15 -> 2
8.50/8.41	  16 -> 4, 5, 6
8.50/8.41	Where:
8.50/8.41	  0) f14#(x1, x2) -> f13#(x1, x2) 
8.50/8.41	  1) f13#(I0, I1) -> f4#(rnd1, I1) [y1 = y1 /\ rnd1 = rnd1]
8.50/8.41	  2) f3#(I2, I3) -> f5#(1 + I2, I3) [I2 <= 5]
8.50/8.41	  3) f3#(I4, I5) -> f5#(1 + I4, I5) [6 <= I4]
8.50/8.41	  4) f2#(I6, I7) -> f3#(I6, I7) [1 + I7 <= 0]
8.50/8.41	  5) f2#(I8, I9) -> f3#(I8, I9) [1 <= I9]
8.50/8.41	  6) f2#(I10, I11) -> f6#(I10, I11) [0 <= I11 /\ I11 <= 0]
8.50/8.41	  7) f7#(I12, I13) -> f6#(-1 + I12, I13) [3 <= I12]
8.50/8.41	  8) f7#(I14, I15) -> f4#(I14, I15) [I14 <= 2]
8.50/8.41	  9) f12#(I16, I17) -> f11#(I16, I17) 
8.50/8.41	  10) f11#(I18, I19) -> f12#(I18, I19) 
8.50/8.41	  11) f10#(I20, I21) -> f11#(I20, I21) 
8.50/8.41	  12) f6#(I24, I25) -> f7#(I24, I25) 
8.50/8.41	  13) f5#(I26, I27) -> f1#(I26, I27) 
8.50/8.41	  14) f4#(I28, I29) -> f5#(I28, I29) 
8.50/8.41	  15) f1#(I30, I31) -> f3#(I30, I31) [I30 <= 5]
8.50/8.41	  16) f1#(I32, I33) -> f2#(I32, rnd2) [rnd2 = rnd2 /\ 6 <= I32]
8.50/8.41	
8.50/8.41	We have the following SCCs.
8.50/8.41	  { 9, 10 }
8.50/8.41	  { 2, 3, 4, 5, 6, 7, 8, 12, 13, 14, 15, 16 }
8.50/8.41	
8.50/8.41	DP problem for innermost termination.
8.50/8.41	P =
8.50/8.41	  f3#(I2, I3) -> f5#(1 + I2, I3) [I2 <= 5]
8.50/8.41	  f3#(I4, I5) -> f5#(1 + I4, I5) [6 <= I4]
8.50/8.41	  f2#(I6, I7) -> f3#(I6, I7) [1 + I7 <= 0]
8.50/8.41	  f2#(I8, I9) -> f3#(I8, I9) [1 <= I9]
8.50/8.41	  f2#(I10, I11) -> f6#(I10, I11) [0 <= I11 /\ I11 <= 0]
8.50/8.41	  f7#(I12, I13) -> f6#(-1 + I12, I13) [3 <= I12]
8.50/8.41	  f7#(I14, I15) -> f4#(I14, I15) [I14 <= 2]
8.50/8.41	  f6#(I24, I25) -> f7#(I24, I25) 
8.50/8.41	  f5#(I26, I27) -> f1#(I26, I27) 
8.50/8.41	  f4#(I28, I29) -> f5#(I28, I29) 
8.50/8.41	  f1#(I30, I31) -> f3#(I30, I31) [I30 <= 5]
8.50/8.41	  f1#(I32, I33) -> f2#(I32, rnd2) [rnd2 = rnd2 /\ 6 <= I32]
8.50/8.41	R = 
8.50/8.41	  f14(x1, x2) -> f13(x1, x2) 
8.50/8.41	  f13(I0, I1) -> f4(rnd1, I1) [y1 = y1 /\ rnd1 = rnd1]
8.50/8.41	  f3(I2, I3) -> f5(1 + I2, I3) [I2 <= 5]
8.50/8.41	  f3(I4, I5) -> f5(1 + I4, I5) [6 <= I4]
8.50/8.41	  f2(I6, I7) -> f3(I6, I7) [1 + I7 <= 0]
8.50/8.41	  f2(I8, I9) -> f3(I8, I9) [1 <= I9]
8.50/8.41	  f2(I10, I11) -> f6(I10, I11) [0 <= I11 /\ I11 <= 0]
8.50/8.41	  f7(I12, I13) -> f6(-1 + I12, I13) [3 <= I12]
8.50/8.41	  f7(I14, I15) -> f4(I14, I15) [I14 <= 2]
8.50/8.41	  f12(I16, I17) -> f11(I16, I17) 
8.50/8.41	  f11(I18, I19) -> f12(I18, I19) 
8.50/8.41	  f10(I20, I21) -> f11(I20, I21) 
8.50/8.41	  f8(I22, I23) -> f9(I22, I23) 
8.50/8.41	  f6(I24, I25) -> f7(I24, I25) 
8.50/8.41	  f5(I26, I27) -> f1(I26, I27) 
8.50/8.41	  f4(I28, I29) -> f5(I28, I29) 
8.50/8.41	  f1(I30, I31) -> f3(I30, I31) [I30 <= 5]
8.50/8.41	  f1(I32, I33) -> f2(I32, rnd2) [rnd2 = rnd2 /\ 6 <= I32]
8.50/8.41	
8.50/11.39	EOF