14.49/14.65	MAYBE
14.49/14.65	
14.49/14.65	DP problem for innermost termination.
14.49/14.65	P =
14.49/14.65	  f8#(x1, x2, x3, x4) -> f7#(x1, x2, x3, x4) 
14.49/14.65	  f7#(I0, I1, I2, I3) -> f2#(I0, I1, I2, I3) [I0 <= 0]
14.49/14.65	  f2#(I4, I5, I6, I7) -> f6#(I4, I5, I6, I7) [1 <= I7 /\ 1 <= I6]
14.49/14.65	  f6#(I8, I9, I10, I11) -> f5#(I8, I9, -1 + I10, I11) 
14.49/14.65	  f6#(I12, I13, I14, I15) -> f5#(I12, I13, I14, -1 + I15) 
14.49/14.65	  f5#(I16, I17, I18, I19) -> f1#(I16, I17, I18, I19) [1 <= I16]
14.49/14.65	  f5#(I20, I21, I22, I23) -> f4#(I20, I21, I22, I23) [I20 <= 0]
14.49/14.65	  f4#(I24, I25, I26, I27) -> f2#(1, I26, I26, I27) 
14.49/14.65	  f4#(I28, I29, I30, I31) -> f2#(I28, I29, I30, I31) [I28 <= 0]
14.49/14.65	  f1#(I36, I37, I38, I39) -> f2#(I36, I37, I38, I39) [1 + I38 <= I37]
14.49/14.65	R = 
14.49/14.65	  f8(x1, x2, x3, x4) -> f7(x1, x2, x3, x4) 
14.49/14.65	  f7(I0, I1, I2, I3) -> f2(I0, I1, I2, I3) [I0 <= 0]
14.49/14.65	  f2(I4, I5, I6, I7) -> f6(I4, I5, I6, I7) [1 <= I7 /\ 1 <= I6]
14.49/14.65	  f6(I8, I9, I10, I11) -> f5(I8, I9, -1 + I10, I11) 
14.49/14.65	  f6(I12, I13, I14, I15) -> f5(I12, I13, I14, -1 + I15) 
14.49/14.65	  f5(I16, I17, I18, I19) -> f1(I16, I17, I18, I19) [1 <= I16]
14.49/14.65	  f5(I20, I21, I22, I23) -> f4(I20, I21, I22, I23) [I20 <= 0]
14.49/14.65	  f4(I24, I25, I26, I27) -> f2(1, I26, I26, I27) 
14.49/14.65	  f4(I28, I29, I30, I31) -> f2(I28, I29, I30, I31) [I28 <= 0]
14.49/14.65	  f1(I32, I33, I34, I35) -> f3(I32, I33, I34, I35) [I33 <= I34]
14.49/14.65	  f1(I36, I37, I38, I39) -> f2(I36, I37, I38, I39) [1 + I38 <= I37]
14.49/14.65	
14.49/14.65	The dependency graph for this problem is:
14.49/14.65	  0 -> 1
14.49/14.65	  1 -> 2
14.49/14.65	  2 -> 3, 4
14.49/14.65	  3 -> 5, 6
14.49/14.65	  4 -> 5, 6
14.49/14.65	  5 -> 9
14.49/14.65	  6 -> 7, 8
14.49/14.65	  7 -> 2
14.49/14.65	  8 -> 2
14.49/14.65	  9 -> 2
14.49/14.65	Where:
14.49/14.65	  0) f8#(x1, x2, x3, x4) -> f7#(x1, x2, x3, x4) 
14.49/14.65	  1) f7#(I0, I1, I2, I3) -> f2#(I0, I1, I2, I3) [I0 <= 0]
14.49/14.65	  2) f2#(I4, I5, I6, I7) -> f6#(I4, I5, I6, I7) [1 <= I7 /\ 1 <= I6]
14.49/14.65	  3) f6#(I8, I9, I10, I11) -> f5#(I8, I9, -1 + I10, I11) 
14.49/14.65	  4) f6#(I12, I13, I14, I15) -> f5#(I12, I13, I14, -1 + I15) 
14.49/14.65	  5) f5#(I16, I17, I18, I19) -> f1#(I16, I17, I18, I19) [1 <= I16]
14.49/14.65	  6) f5#(I20, I21, I22, I23) -> f4#(I20, I21, I22, I23) [I20 <= 0]
14.49/14.65	  7) f4#(I24, I25, I26, I27) -> f2#(1, I26, I26, I27) 
14.49/14.65	  8) f4#(I28, I29, I30, I31) -> f2#(I28, I29, I30, I31) [I28 <= 0]
14.49/14.65	  9) f1#(I36, I37, I38, I39) -> f2#(I36, I37, I38, I39) [1 + I38 <= I37]
14.49/14.65	
14.49/14.65	We have the following SCCs.
14.49/14.65	  { 2, 3, 4, 5, 6, 7, 8, 9 }
14.49/14.65	
14.49/14.65	DP problem for innermost termination.
14.49/14.65	P =
14.49/14.65	  f2#(I4, I5, I6, I7) -> f6#(I4, I5, I6, I7) [1 <= I7 /\ 1 <= I6]
14.49/14.65	  f6#(I8, I9, I10, I11) -> f5#(I8, I9, -1 + I10, I11) 
14.49/14.65	  f6#(I12, I13, I14, I15) -> f5#(I12, I13, I14, -1 + I15) 
14.49/14.65	  f5#(I16, I17, I18, I19) -> f1#(I16, I17, I18, I19) [1 <= I16]
14.49/14.65	  f5#(I20, I21, I22, I23) -> f4#(I20, I21, I22, I23) [I20 <= 0]
14.49/14.65	  f4#(I24, I25, I26, I27) -> f2#(1, I26, I26, I27) 
14.49/14.65	  f4#(I28, I29, I30, I31) -> f2#(I28, I29, I30, I31) [I28 <= 0]
14.49/14.65	  f1#(I36, I37, I38, I39) -> f2#(I36, I37, I38, I39) [1 + I38 <= I37]
14.49/14.65	R = 
14.49/14.65	  f8(x1, x2, x3, x4) -> f7(x1, x2, x3, x4) 
14.49/14.65	  f7(I0, I1, I2, I3) -> f2(I0, I1, I2, I3) [I0 <= 0]
14.49/14.65	  f2(I4, I5, I6, I7) -> f6(I4, I5, I6, I7) [1 <= I7 /\ 1 <= I6]
14.49/14.65	  f6(I8, I9, I10, I11) -> f5(I8, I9, -1 + I10, I11) 
14.49/14.65	  f6(I12, I13, I14, I15) -> f5(I12, I13, I14, -1 + I15) 
14.49/14.65	  f5(I16, I17, I18, I19) -> f1(I16, I17, I18, I19) [1 <= I16]
14.49/14.65	  f5(I20, I21, I22, I23) -> f4(I20, I21, I22, I23) [I20 <= 0]
14.49/14.65	  f4(I24, I25, I26, I27) -> f2(1, I26, I26, I27) 
14.49/14.65	  f4(I28, I29, I30, I31) -> f2(I28, I29, I30, I31) [I28 <= 0]
14.49/14.65	  f1(I32, I33, I34, I35) -> f3(I32, I33, I34, I35) [I33 <= I34]
14.49/14.65	  f1(I36, I37, I38, I39) -> f2(I36, I37, I38, I39) [1 + I38 <= I37]
14.49/14.65	
14.49/17.62	EOF