1.48/1.53	MAYBE
1.48/1.53	
1.48/1.53	DP problem for innermost termination.
1.48/1.53	P =
1.48/1.53	  f9#(x1, x2, x3) -> f8#(x1, x2, x3) 
1.48/1.53	  f8#(I0, I1, I2) -> f7#(0, I1, I2) 
1.48/1.53	  f7#(I3, I4, I5) -> f5#(I3, I4, I5) [1 <= I4]
1.48/1.53	  f7#(I6, I7, I8) -> f3#(I6, I7, I8) [I7 <= 0]
1.48/1.53	  f6#(I9, I10, I11) -> f5#(I9, I10, I11) 
1.48/1.53	  f5#(I12, I13, I14) -> f6#(1 + I12, I13, I14) 
1.48/1.53	  f5#(I15, I16, I17) -> f1#(I15, I16, I17) [2 <= 0]
1.48/1.53	  f4#(I18, I19, I20) -> f3#(I18, I19, I20) 
1.48/1.53	  f3#(I21, I22, I23) -> f4#(I21, I22, -1 + I23) [1 <= I23]
1.48/1.53	  f3#(I24, I25, I26) -> f1#(0, I25, I26) [I26 <= 0]
1.48/1.53	  f2#(I27, I28, I29) -> f1#(I27, I28, I29) 
1.48/1.53	  f1#(I30, I31, I32) -> f2#(I30, 1, I32) 
1.48/1.53	R = 
1.48/1.53	  f9(x1, x2, x3) -> f8(x1, x2, x3) 
1.48/1.53	  f8(I0, I1, I2) -> f7(0, I1, I2) 
1.48/1.53	  f7(I3, I4, I5) -> f5(I3, I4, I5) [1 <= I4]
1.48/1.53	  f7(I6, I7, I8) -> f3(I6, I7, I8) [I7 <= 0]
1.48/1.53	  f6(I9, I10, I11) -> f5(I9, I10, I11) 
1.48/1.53	  f5(I12, I13, I14) -> f6(1 + I12, I13, I14) 
1.48/1.53	  f5(I15, I16, I17) -> f1(I15, I16, I17) [2 <= 0]
1.48/1.53	  f4(I18, I19, I20) -> f3(I18, I19, I20) 
1.48/1.53	  f3(I21, I22, I23) -> f4(I21, I22, -1 + I23) [1 <= I23]
1.48/1.53	  f3(I24, I25, I26) -> f1(0, I25, I26) [I26 <= 0]
1.48/1.53	  f2(I27, I28, I29) -> f1(I27, I28, I29) 
1.48/1.53	  f1(I30, I31, I32) -> f2(I30, 1, I32) 
1.48/1.53	
1.48/1.53	The dependency graph for this problem is:
1.48/1.53	  0 -> 1
1.48/1.53	  1 -> 2, 3
1.48/1.53	  2 -> 5
1.48/1.53	  3 -> 8, 9
1.48/1.53	  4 -> 5
1.48/1.53	  5 -> 4
1.48/1.53	  6 -> 
1.48/1.53	  7 -> 8, 9
1.48/1.53	  8 -> 7
1.48/1.53	  9 -> 11
1.48/1.53	  10 -> 11
1.48/1.53	  11 -> 10
1.48/1.53	Where:
1.48/1.53	  0) f9#(x1, x2, x3) -> f8#(x1, x2, x3) 
1.48/1.53	  1) f8#(I0, I1, I2) -> f7#(0, I1, I2) 
1.48/1.53	  2) f7#(I3, I4, I5) -> f5#(I3, I4, I5) [1 <= I4]
1.48/1.53	  3) f7#(I6, I7, I8) -> f3#(I6, I7, I8) [I7 <= 0]
1.48/1.53	  4) f6#(I9, I10, I11) -> f5#(I9, I10, I11) 
1.48/1.53	  5) f5#(I12, I13, I14) -> f6#(1 + I12, I13, I14) 
1.48/1.53	  6) f5#(I15, I16, I17) -> f1#(I15, I16, I17) [2 <= 0]
1.48/1.53	  7) f4#(I18, I19, I20) -> f3#(I18, I19, I20) 
1.48/1.53	  8) f3#(I21, I22, I23) -> f4#(I21, I22, -1 + I23) [1 <= I23]
1.48/1.53	  9) f3#(I24, I25, I26) -> f1#(0, I25, I26) [I26 <= 0]
1.48/1.53	  10) f2#(I27, I28, I29) -> f1#(I27, I28, I29) 
1.48/1.53	  11) f1#(I30, I31, I32) -> f2#(I30, 1, I32) 
1.48/1.53	
1.48/1.53	We have the following SCCs.
1.48/1.53	  { 4, 5 }
1.48/1.53	  { 7, 8 }
1.48/1.53	  { 10, 11 }
1.48/1.53	
1.48/1.53	DP problem for innermost termination.
1.48/1.53	P =
1.48/1.53	  f2#(I27, I28, I29) -> f1#(I27, I28, I29) 
1.48/1.53	  f1#(I30, I31, I32) -> f2#(I30, 1, I32) 
1.48/1.53	R = 
1.48/1.53	  f9(x1, x2, x3) -> f8(x1, x2, x3) 
1.48/1.53	  f8(I0, I1, I2) -> f7(0, I1, I2) 
1.48/1.53	  f7(I3, I4, I5) -> f5(I3, I4, I5) [1 <= I4]
1.48/1.53	  f7(I6, I7, I8) -> f3(I6, I7, I8) [I7 <= 0]
1.48/1.53	  f6(I9, I10, I11) -> f5(I9, I10, I11) 
1.48/1.53	  f5(I12, I13, I14) -> f6(1 + I12, I13, I14) 
1.48/1.53	  f5(I15, I16, I17) -> f1(I15, I16, I17) [2 <= 0]
1.48/1.53	  f4(I18, I19, I20) -> f3(I18, I19, I20) 
1.48/1.53	  f3(I21, I22, I23) -> f4(I21, I22, -1 + I23) [1 <= I23]
1.48/1.53	  f3(I24, I25, I26) -> f1(0, I25, I26) [I26 <= 0]
1.48/1.53	  f2(I27, I28, I29) -> f1(I27, I28, I29) 
1.48/1.53	  f1(I30, I31, I32) -> f2(I30, 1, I32) 
1.48/1.53	
1.48/4.51	EOF