4.82/4.78	MAYBE
4.82/4.78	
4.82/4.78	DP problem for innermost termination.
4.82/4.78	P =
4.82/4.78	  f6#(x1, x2, x3, x4) -> f5#(x1, x2, x3, x4) 
4.82/4.78	  f5#(I0, I1, I2, I3) -> f2#(I0, I1, I0, 1) 
4.82/4.78	  f2#(I4, I5, I6, I7) -> f3#(I4, I5, I6, I7) 
4.82/4.78	  f3#(I8, I9, I10, I11) -> f1#(I8, rnd2, I10, I11) [rnd2 = rnd2 /\ 2 + I11 <= I10]
4.82/4.78	  f1#(I16, I17, I18, I19) -> f2#(I16, I17, I17, I19) 
4.82/4.78	  f1#(I20, I21, I22, I23) -> f2#(I20, I21, I22, I21) 
4.82/4.78	R = 
4.82/4.78	  f6(x1, x2, x3, x4) -> f5(x1, x2, x3, x4) 
4.82/4.78	  f5(I0, I1, I2, I3) -> f2(I0, I1, I0, 1) 
4.82/4.78	  f2(I4, I5, I6, I7) -> f3(I4, I5, I6, I7) 
4.82/4.78	  f3(I8, I9, I10, I11) -> f1(I8, rnd2, I10, I11) [rnd2 = rnd2 /\ 2 + I11 <= I10]
4.82/4.78	  f3(I12, I13, I14, I15) -> f4(I12, I13, I14, I15) [I14 <= 1 + I15]
4.82/4.78	  f1(I16, I17, I18, I19) -> f2(I16, I17, I17, I19) 
4.82/4.78	  f1(I20, I21, I22, I23) -> f2(I20, I21, I22, I21) 
4.82/4.78	
4.82/4.78	The dependency graph for this problem is:
4.82/4.78	  0 -> 1
4.82/4.78	  1 -> 2
4.82/4.78	  2 -> 3
4.82/4.78	  3 -> 4, 5
4.82/4.78	  4 -> 2
4.82/4.78	  5 -> 2
4.82/4.78	Where:
4.82/4.78	  0) f6#(x1, x2, x3, x4) -> f5#(x1, x2, x3, x4) 
4.82/4.78	  1) f5#(I0, I1, I2, I3) -> f2#(I0, I1, I0, 1) 
4.82/4.78	  2) f2#(I4, I5, I6, I7) -> f3#(I4, I5, I6, I7) 
4.82/4.78	  3) f3#(I8, I9, I10, I11) -> f1#(I8, rnd2, I10, I11) [rnd2 = rnd2 /\ 2 + I11 <= I10]
4.82/4.78	  4) f1#(I16, I17, I18, I19) -> f2#(I16, I17, I17, I19) 
4.82/4.78	  5) f1#(I20, I21, I22, I23) -> f2#(I20, I21, I22, I21) 
4.82/4.78	
4.82/4.78	We have the following SCCs.
4.82/4.78	  { 2, 3, 4, 5 }
4.82/4.78	
4.82/4.78	DP problem for innermost termination.
4.82/4.78	P =
4.82/4.78	  f2#(I4, I5, I6, I7) -> f3#(I4, I5, I6, I7) 
4.82/4.78	  f3#(I8, I9, I10, I11) -> f1#(I8, rnd2, I10, I11) [rnd2 = rnd2 /\ 2 + I11 <= I10]
4.82/4.78	  f1#(I16, I17, I18, I19) -> f2#(I16, I17, I17, I19) 
4.82/4.78	  f1#(I20, I21, I22, I23) -> f2#(I20, I21, I22, I21) 
4.82/4.78	R = 
4.82/4.78	  f6(x1, x2, x3, x4) -> f5(x1, x2, x3, x4) 
4.82/4.78	  f5(I0, I1, I2, I3) -> f2(I0, I1, I0, 1) 
4.82/4.78	  f2(I4, I5, I6, I7) -> f3(I4, I5, I6, I7) 
4.82/4.78	  f3(I8, I9, I10, I11) -> f1(I8, rnd2, I10, I11) [rnd2 = rnd2 /\ 2 + I11 <= I10]
4.82/4.78	  f3(I12, I13, I14, I15) -> f4(I12, I13, I14, I15) [I14 <= 1 + I15]
4.82/4.78	  f1(I16, I17, I18, I19) -> f2(I16, I17, I17, I19) 
4.82/4.78	  f1(I20, I21, I22, I23) -> f2(I20, I21, I22, I21) 
4.82/4.78	
4.82/7.76	EOF