8.85/8.76	MAYBE
8.85/8.76	
8.85/8.76	DP problem for innermost termination.
8.85/8.76	P =
8.85/8.76	  f7#(x1, x2, x3, x4) -> f6#(x1, x2, x3, x4) 
8.85/8.76	  f4#(I4, I5, I6, I7) -> f1#(I4, 1, 1 + I6, I7) [0 <= I5 /\ I5 <= 0 /\ 0 <= -1 - I6 + I7]
8.85/8.76	  f6#(I8, I9, I10, I11) -> f4#(I8, 0, I10, I11) 
8.85/8.76	  f3#(I17, I18, I19, I20) -> f4#(I17, 0, I19, 1 + I20) 
8.85/8.76	  f2#(I21, I22, I23, I24) -> f3#(I21, I22, I23, I24) [1 <= I22]
8.85/8.76	  f2#(I25, I26, I27, I28) -> f3#(I25, I26, I27, I28) [1 + I26 <= 0]
8.85/8.76	  f1#(I29, I30, I31, I32) -> f2#(I29, I30, I31, I32) [0 <= -1 - I31 + I32]
8.85/8.76	R = 
8.85/8.76	  f7(x1, x2, x3, x4) -> f6(x1, x2, x3, x4) 
8.85/8.76	  f4(I0, I1, I2, I3) -> f5(rnd1, I1, I2, I3) [rnd1 = rnd1 /\ -1 * I2 + I3 <= 0]
8.85/8.76	  f4(I4, I5, I6, I7) -> f1(I4, 1, 1 + I6, I7) [0 <= I5 /\ I5 <= 0 /\ 0 <= -1 - I6 + I7]
8.85/8.76	  f6(I8, I9, I10, I11) -> f4(I8, 0, I10, I11) 
8.85/8.76	  f1(I12, I13, I14, I15) -> f5(I16, I13, I14, I15) [I16 = I16 /\ -1 * I14 + I15 <= 0]
8.85/8.76	  f3(I17, I18, I19, I20) -> f4(I17, 0, I19, 1 + I20) 
8.85/8.76	  f2(I21, I22, I23, I24) -> f3(I21, I22, I23, I24) [1 <= I22]
8.85/8.76	  f2(I25, I26, I27, I28) -> f3(I25, I26, I27, I28) [1 + I26 <= 0]
8.85/8.76	  f1(I29, I30, I31, I32) -> f2(I29, I30, I31, I32) [0 <= -1 - I31 + I32]
8.85/8.76	
8.85/8.76	The dependency graph for this problem is:
8.85/8.76	  0 -> 2
8.85/8.76	  1 -> 6
8.85/8.76	  2 -> 1
8.85/8.76	  3 -> 1
8.85/8.76	  4 -> 3
8.85/8.76	  5 -> 3
8.85/8.76	  6 -> 4, 5
8.85/8.76	Where:
8.85/8.76	  0) f7#(x1, x2, x3, x4) -> f6#(x1, x2, x3, x4) 
8.85/8.76	  1) f4#(I4, I5, I6, I7) -> f1#(I4, 1, 1 + I6, I7) [0 <= I5 /\ I5 <= 0 /\ 0 <= -1 - I6 + I7]
8.85/8.76	  2) f6#(I8, I9, I10, I11) -> f4#(I8, 0, I10, I11) 
8.85/8.76	  3) f3#(I17, I18, I19, I20) -> f4#(I17, 0, I19, 1 + I20) 
8.85/8.76	  4) f2#(I21, I22, I23, I24) -> f3#(I21, I22, I23, I24) [1 <= I22]
8.85/8.76	  5) f2#(I25, I26, I27, I28) -> f3#(I25, I26, I27, I28) [1 + I26 <= 0]
8.85/8.76	  6) f1#(I29, I30, I31, I32) -> f2#(I29, I30, I31, I32) [0 <= -1 - I31 + I32]
8.85/8.76	
8.85/8.76	We have the following SCCs.
8.85/8.76	  { 1, 3, 4, 5, 6 }
8.85/8.76	
8.85/8.76	DP problem for innermost termination.
8.85/8.76	P =
8.85/8.76	  f4#(I4, I5, I6, I7) -> f1#(I4, 1, 1 + I6, I7) [0 <= I5 /\ I5 <= 0 /\ 0 <= -1 - I6 + I7]
8.85/8.76	  f3#(I17, I18, I19, I20) -> f4#(I17, 0, I19, 1 + I20) 
8.85/8.76	  f2#(I21, I22, I23, I24) -> f3#(I21, I22, I23, I24) [1 <= I22]
8.85/8.76	  f2#(I25, I26, I27, I28) -> f3#(I25, I26, I27, I28) [1 + I26 <= 0]
8.85/8.76	  f1#(I29, I30, I31, I32) -> f2#(I29, I30, I31, I32) [0 <= -1 - I31 + I32]
8.85/8.76	R = 
8.85/8.76	  f7(x1, x2, x3, x4) -> f6(x1, x2, x3, x4) 
8.85/8.76	  f4(I0, I1, I2, I3) -> f5(rnd1, I1, I2, I3) [rnd1 = rnd1 /\ -1 * I2 + I3 <= 0]
8.85/8.76	  f4(I4, I5, I6, I7) -> f1(I4, 1, 1 + I6, I7) [0 <= I5 /\ I5 <= 0 /\ 0 <= -1 - I6 + I7]
8.85/8.76	  f6(I8, I9, I10, I11) -> f4(I8, 0, I10, I11) 
8.85/8.76	  f1(I12, I13, I14, I15) -> f5(I16, I13, I14, I15) [I16 = I16 /\ -1 * I14 + I15 <= 0]
8.85/8.76	  f3(I17, I18, I19, I20) -> f4(I17, 0, I19, 1 + I20) 
8.85/8.76	  f2(I21, I22, I23, I24) -> f3(I21, I22, I23, I24) [1 <= I22]
8.85/8.76	  f2(I25, I26, I27, I28) -> f3(I25, I26, I27, I28) [1 + I26 <= 0]
8.85/8.76	  f1(I29, I30, I31, I32) -> f2(I29, I30, I31, I32) [0 <= -1 - I31 + I32]
8.85/8.76	
8.85/11.73	EOF